castle | building Kafka and avro based apps | Pub Sub library
kandi X-RAY | castle Summary
kandi X-RAY | castle Summary
A framework around kafka.js to transparently use Schema Registry and create an application that consumes, produces, and reacts to different kafka topics. Supports consumption in batches or in parallel. Statically define and verify the schemas / message types in TypeScript.
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QUESTION
I have two large-ish data frames I am trying to append...
In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.
In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.
Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.
Edit: dput(df2)
...ANSWER
Answered 2022-Apr-18 at 03:52Here's one way you could turn state abbreviations into state names using R's built in state vectors:
QUESTION
The goal for my code is to make a rough roadmap using the latitude and longitude of the exits on the pennsylvania turnpike drawing a line between each exit.
I am using a for loop to plot a line on the map every time it loops. This works if i hard code the latitude and longitude but as soon as i plug in my variables nothing gets plotted. Since the coordinates are in order I am just increasing the index every time it loops to get the next coordinates. I have printed the variables inside the loop and verified they have the desired value. I have tried putting the values in ordered pairs but the plot function didn't like me using nparrays. I'm not sure if there is something simple i am missing, but I appreciate any input.
...ANSWER
Answered 2022-Apr-17 at 19:11Okay, based on the discussion above, see below for a solution.
Notes:
- Am using pandas DataFames to easily work with the
.csv
file. thenames
field is the column names. - Am not using orthographic projection at all.
- Am iterating through the list of highway exits one exit at a time; at each index, am extracting the current and next exits' data - am sure there's a more 'pythonic' way to do this, but this is readable at least.
- edit: the final index in the loop is length-1
QUESTION
I try to request a new certificate via EST protocol from the EST test service URL “https://testrfc7030.com/”. The program uses Bouncy Castle for this.
I have already configured the EST service’s TA and my client certificate obtained from them. I also use the BC JSSE provider to get access to the “tls-unique” channel binding value.
...ANSWER
Answered 2022-Apr-01 at 09:16Based on the input by Peter we were able to fix this problem as following:
QUESTION
I'm experimenting with Chaum's blind signature, and what I'm trying to do is have the blinding and un-blinding done in JavaScript, and signing and verifying in Java (with bouncy castle). For the Java side, my source is this, and for JavaScript, I found blind-signatures. I've created two small codes to play with, for the Java side:
...ANSWER
Answered 2021-Dec-13 at 14:56The blind-signature library used in the NodeJS code for blind signing implements the process described here:
BlindSignature.blind()
generates the SHA256 hash of the message and determines the blind message m' = m * re mod N.BlindSignature.sign()
calculates the blind signature s' = (m')d mod N.BlindSignature.unblind()
determines the unblind signature s = s' * r-1 mod N.BlindSignature.verify()
decrypts the unblind signature (se) and compares the result with the hashed message. If both are the same, the verification is successful.
No padding takes place in this process.
In the Java code, the implementation of signing the blind message in signConcealedMessage()
is functionally identical to BlindSignature.sign()
.
In contrast, the verification in the Java code is incompatible with the above process because the Java code uses PSS as padding during verification.
A compatible Java code would be for instance:
QUESTION
I'm using Java 8, trying to post https third party (other subdomain works), works with postman, but using RestTemplate
throws SSLHandshakeException
ANSWER
Answered 2022-Feb-28 at 18:33Please, be aware that the cipher suites described in your debug output doesn't show the cipher suite that was actually used by openssl
, ECDHE-RSA-AES256-GCM-SHA384
. In fact, they don't include any cipher suite that requires AES 256. It may not be of relevance, but it may be a symptom of any misconfiguration, and can explain why the handshake is failing. As indicated in the Oracle documentation when describing Java 8 supported cipher suites:
Cipher suites that use AES_256 require installation of the JCE Unlimited Strength Jurisdiction Policy Files.
As a consequence, please, be sure you installed and properly configured the JCE Unlimited Strength Jurisdiction Policy Files.
As indicated by @dave_thompson_085 in his excellent comment, only Oracle Java 8 below 8u161 requires adding the unlimited policy, as stated in Appendix C of the aforementioned Oracle documentation.
The JCE Unlimited Strength Jurisdiction Policy Files are bundled into the JDK since JDK 8u151, but the unlimited
policy was not defined as the default one since JDK 8u161.
In JDK 8u151 or 8u152, as stated in one of the previous cited links, and explained as well by @dave_thompson_085 - thank you very much again, in order to make the unlimited
version of the JCE the one that should be used, you need to define the system property crypto.policy
. From the docs:
This release introduces a new feature whereby the JCE jurisdiction policy files used by the JDK can be controlled via a new Security property. In older releases, JCE jurisdiction files had to be downloaded and installed separately to allow unlimited cryptography to be used by the JDK. The download and install steps are no longer necessary. To enable unlimited cryptography, one can use the new
crypto.policy
Security property. If the new Security property (crypto.policy
) is set in thejava.security
file, or has been set dynamically by using theSecurity.setProperty()
call before the JCE framework has been initialized, that setting will be honored. By default, the property will be undefined. If the property is undefined and the legacy JCE jurisdiction files don't exist in the legacylib/security
directory, then the default cryptographic level will remain at 'limited'. To configure the JDK to use unlimited cryptography, set thecrypto.policy
to a value of 'unlimited'. See the notes in thejava.security
file shipping with this release for more information.
The issue is not present in OpenJDK.
As an alternative solution, as suggested in this related SO question, probably using an alternate provider like BouncyCastle could be of help as well.
QUESTION
I am upgrading my C#
function app from .net 3.1 to 6.0`.
When I run my test cases, I found that, 1 of my test case failed with the below error.
Castle.DynamicProxy.InvalidProxyConstructorArgumentsException : Can not instantiate proxy of class: System.Net.HttpWebRequest. Could not find a parameterless constructor.
Basically, I am trying to mock HttpWebRequest and below is my piece of code for that.
...ANSWER
Answered 2022-Feb-23 at 10:53Both HttpWebRequest constructors are obsolete and should not be used. You have to use the static function "Create" to create a new instance of the HttpWebRequest class:
HttpWebRequest myReq = (HttpWebRequest)WebRequest.Create("http://www.contoso.com/");
To solve your issue, use the HttpClient class instead. This class has a parameterless constructor.
QUESTION
Issue description: Brownie tests containing either
...ANSWER
Answered 2022-Feb-19 at 19:52This is fixed in Brownie v1.18.1. However, you will need to install Python 3.9.10 in order to get the latest brownie. For this to work in a virtual environment you can't use venv. Here is a process that works for me:
- install virtualenv on your standard Python version
- download python 3.9.10 and install it without "add to path" into a dedicated directory e.g. $home/pythonversions
- in your project directory create a virtual environment like so
python -m virtualenv -p=""
start your virtual environment e.g. home>..venv\Scripts\activate.ps1
test if your python version is the desired one with python --version
Now install Cython to avoid another error.
Install nodeenv in order to install ganage
Activate with
nodeenv -p
(for this step you will need PowerShell with admin rights)Install ganache with npm
Install eth-brownie with pip check if you got the latest version with
brownie --version
QUESTION
I'm making a text-based game that occurs in a castle and I want the monster to move randomly between the rooms to make the game over occur at random times I was thinking of using import random and setting each value to 25% but it says local value exits not used I have tried some other systems for movement but it relied on the movement of the player.
...ANSWER
Answered 2022-Feb-18 at 18:20If you want the monster to appear in a random room every time, you can just pick one at random:
QUESTION
As the Title described, these two functions has been removed from bouncy castle v1.50, is there any alternative? I have to use v1.64 or above.
this is my code
...ANSWER
Answered 2022-Feb-11 at 05:13There are two completely separate providers:
- "BC", i.e. BouncyCastleProvider, the very widely used cryptography API, currently at version 1.70 (website).
- "BCFIPS", i.e. BouncyCastleFipsProvider, a FIPS-compliant implementation of a more limited set of algorithms, currently at version 1.0.2.3 (website).
These can't be used together. Also BCFIPS is not just a drop-in replacement for BC that suddenly makes your project FIPS-compliant. The great majority of users should be using BC.
The methods you mention are only relevant to BCFIPS, yet you are talking about version numbers that are only relevant to BC, which implies either that you are confused about which jars/provider you are trying to use, or that perhaps you are trying to use both in the same process, which doesn't work.
QUESTION
I'm modifying a CSS template based on bootstrap, in order to obtain a responsive simple website.
The page provides a list of events. Since show_date
and show_shop
have fixed width, when the website is opened on a smartphone (smaller screen) the class flex-row
allows the show_name
and show_location
to be disposed in column to save space.
The problem is that when the text in show_name
and show_location
is too long, the text wrap out of the box in vertical.
How can I force the text in show_name
and show_location
to use only a single line (one for each one), truncating the text with ...
?
I tried overflow: hidden
with text-overflow: ellipsis
but it doesn't work (I think due to the flex width of the div).
Thanks for help.
...ANSWER
Answered 2022-Jan-28 at 21:12You could simply use the text-nowrap
class on those divs and use spans inside. I've also removed some redundant div elements and combined classes.
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