vinit | line tool to generate V projects | Command Line Interface library
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kandi X-RAY | vinit Summary
Vinit is a command line tool to generate v projects and run scripts Documentation · Report a Bug · Request Feature. Vinit can be used to.
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QUESTION
I'm doing a code for language translator app using tkinter and as an extra feature, I decided to add a function which lets you save the translated text as a pdf file. The problem is, if the translated text contains characters outside of latin unicode, I get errors.
...ANSWER
Answered 2021-Jun-01 at 08:55An unicode font should be set up and used by using .add_font()
.
Below is an example code of using arialuni.ttf
:
QUESTION
The goal is to animate/simulate a sprinkler. The basic idea is to create multiple droplets at an instance, each exiting the sprinkler at a different angle. However, instead of having a point that moves along, I'm getting a straight, static line. I've tried the same code with only one or 2 drops/points, but I still get the same straight line. At first I thought it was because I included drag into the animation (in previous trials I got strange/unexpected results when I included the drag, so I was hoping it was the same problem)
Below is the code I wrote.
EDIT: dragx and dragy are no longer set to the same values. The initial velocities are calculated outside the update function.
Drag forces are recalculated at each index increase, since the drag depends on the velocity.
The imports are also now included.
I have also now tried to use a scatter plot instead of a line, which gave me a single dot at the origin. I reverted back to the line since then
...ANSWER
Answered 2019-Nov-27 at 16:43In addition to the mistakes pointed out by @JohanC, you are using the surface area (4 * pi * r^2
) instead of the cross-sectional area (pi * r^2
) of the water droplets (approximated as spheres). Furthermore, you appear to be trying to using equations of motion which assume a vacuum, those equations break down when air resistance or other nonconstant forces are added.
I would recommend you read this answer for a more complete explanation of calculating ballistic projectile motion with air resistance, but here is a simplified version.
Calculating the position of a particle moving through a medium is essentially solving a first order ODE, there are many ways to solve such an equation numerically. The simplest (albeit least robust) way is to break the problem into small segments and approximate the change from the current point to the next point. For this problem such a method works quite well, assuming you use a small enough time step.
In your case we could do something like this
QUESTION
I have an issue where the Visible property on my user control is always returning False
despite whether it should be visible on the page or not. I have the following user control:
ANSWER
Answered 2019-Aug-27 at 12:50When your ActiveViewIndex is updated in Click event of button, the sequence of event is:
1) Load for Page, ActiveIndex is 0, UC is not visible.
2) Load for UserControl, UC is not visible due to invisible View
3) Processing of events, ActiveIndex is updated to 1, Visibility property is updated for all related controls
4) Page.LoadComplete event (Visible is True already, but you do not have the event)
5) Page.PreRender (Visible is True already, but you do not have the event yet)
6) UC.PreRender - here you should see Visible=True.
I've just tedsted this on empty project and it works. You've must missed something when checking the PreRender event.
Init based on Visibility is not very good practice. I suggest you to add some initialization like this:
QUESTION
I am using SparkStreaming for reading data from a topic. I am facing an exception in it.
java.io.NotSerializableException: org.apache.kafka.clients.consumer.ConsumerRecord Serialization stack: - object not serializable (class: org.apache.kafka.clients.consumer.ConsumerRecord, value: ConsumerRecord(topic = rawEventTopic, partition = 0, offset = 14098, CreateTime = 1556113016951, serialized key size = -1, serialized value size = 2916, headers = RecordHeaders(headers = [], isReadOnly = false), key = null, value = {"id":null,"message":null,"eventDate":"","group":null,"category":"AD","userName":null,"inboundDataSource":"AD","source":"192.168.1.14","destination":"192.168.1.15","bytesSent":"200KB","rawData":"{username: vinit}","account_name":null,"security_id":null,"account_domain":null,"logon_id":null,"process_id":null,"process_information":null,"process_name":null,"target_server_name":null,"source_network_address":null,"logon_process":null,"authentication_Package":null,"network_address":null,"failure_reason":null,"workstation_name":null,"target_server":null,"network_information":null,"object_type":null,"object_name":null,"source_port":null,"logon_type":null,"group_name":null,"source_dra":null,"destination_dra":null,"group_admin":null,"sam_account_name":null,"new_logon":null,"destination_address":null,"destination_port":null,"source_address":null,"logon_account":null,"sub_status":null,"eventdate":null,"time_taken":null,"s_computername":null,"cs_method":null,"cs_uri_stem":null,"cs_uri_query":null,"c_ip":null,"s_ip":null,"s_supplier_name":null,"s_sitename":null,"cs_username":null,"cs_auth_group":null,"cs_categories":null,"s_action":null,"cs_host":null,"cs_uri":null,"cs_uri_scheme":null,"cs_uri_port":null,"cs_uri_path":null,"cs_uri_extension":null,"cs_referer":null,"cs_user_agent":null,"cs_bytes":null,"sc_status":null,"sc_bytes":null,"sc_filter_result":null,"sc_filter_category":null,"x_virus_id":null,"x_exception_id":null,"rs_content_type":null,"s_supplier_ip":null,"cs_cookie":null,"s_port":null,"cs_version":null,"creationTime":null,"operation":null,"workload":null,"clientIP":null,"userId":null,"eventSource":null,"itemType":null,"userAgent":null,"eventData":null,"sourceFileName":null,"siteUrl":null,"targetUserOrGroupType":null,"targetUserOrGroupName":null,"sourceFileExtension":null,"sourceRelativeUrl":null,"resultStatus":null,"client":null,"loginStatus":null,"userDomain":null,"clientIPAddress":null,"clientProcessName":null,"clientVersion":null,"externalAccess":null,"logonType":null,"mailboxOwnerUPN":null,"organizationName":null,"originatingServer":null,"subject":null,"sendAsUserSmtp":null,"deviceexternalid":null,"deviceeventcategory":null,"devicecustomstring1":null,"customnumber2":null,"customnumber1":null,"emailsender":null,"sourceusername":null,"sourceaddress":null,"emailrecipient":null,"destinationaddress":null,"destinationport":null,"requestclientapplication":null,"oldfilepath":null,"filepath":null,"additionaldetails11":null,"applicationprotocol":null,"emailrecipienttype":null,"emailsubject":null,"transactionstring1":null,"deviceaction":null,"devicecustomdate2":null,"devicecustomdate1":null,"sourcehostname":null,"additionaldetails10":null,"filename":null,"bytesout":null,"additionaldetails13":null,"additionaldetails14":null,"accountname":null,"destinationhostname":null,"dataSourceId":2,"date":"","violated":false,"oobjectId":null,"eventCategoryName":"AD","sourceDataType":"AD"})) - element of array (index: 0) - array (class [Lorg.apache.kafka.clients.consumer.ConsumerRecord;, size 1) at org.apache.spark.serializer.SerializationDebugger$.improveException(SerializationDebugger.scala:40) ~[spark-core_2.11-2.3.0.jar:2.3.0] at org.apache.spark.serializer.JavaSerializationStream.writeObject(JavaSerializer.scala:46) ~[spark-core_2.11-2.3.0.jar:2.3.0] at org.apache.spark.serializer.JavaSerializerInstance.serialize(JavaSerializer.scala:100) ~[spark-core_2.11-2.3.0.jar:2.3.0] at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:393) ~[spark-core_2.11-2.3.0.jar:2.3.0] at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source) [na:1.8.0_151] at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source) [na:1.8.0_151] at java.lang.Thread.run(Unknown Source) [na:1.8.0_151]
2019-04-24 19:07:00.025 ERROR 21144 --- [result-getter-1] o.apache.spark.scheduler.TaskSetManager : Task 1.0 in stage 48.0 (TID 97) had a not serializable result: org.apache.kafka.clients.consumer.ConsumerRecord
Code for reading topic data is below -
...ANSWER
Answered 2019-May-12 at 12:56Found a solution of my issue in below link -
org.apache.spark.SparkException: Task not serializable
declare the inner class as a static variable :
QUESTION
I have three drives, want to get three drives in kibana but I am able to get only one drive. I have added the name of those drives in system.yml configuration file but still, only one /dev/xvda1 is getting in kibana.
My Disks are:
...ANSWER
Answered 2019-Jan-28 at 09:23By default, metricbeat comes with a pre-configured exclusion rule in processors
block. Take a look at these lines:
QUESTION
ANSWER
Answered 2019-Jan-10 at 02:17okay referencing the following lines..
QUESTION
Error is
InvalidPipeArgument: 'Invalid Date' for pipe 'DatePipe'.
I want display json data in p-calendar (Primeng component). I am fetching data from json file and display in input field but its not working.
If it possible then please provide solution for p-dropdown and p-radiobutton for display json data in input field
demographic.component.html
...ANSWER
Answered 2018-Aug-04 at 18:10You get the error "InvalidPipeArgument: 'Invalid Date' for pipe 'DatePipe'", because you are trying to format undefined with a DatePipe (and also the syntax is incorrect).
First you have to fetch the data and then assign the date that you received from the response.
You can do.
in the top.
QUESTION
In the table calendar_event
there can be several calendar events (inspections). At present my query returns the oldest inspection (oldest if we rank them by the field ce.calendar_event_start
), I want it to return the newest (latest) inspection.
I'm struggling with the approach to this. I've tried adding MAX
around ce.calendar_event_start
but that doesn't work. I'm assuming I have to change the LEFT JOIN
but I can't figure out how I'd change it so that it's joining on the newest ce.calendar_event_start
value.
UPDATE 1 - Thanks to @Vinit
Changed the LEFT JOIN as per the below but the query fails to execute;
...ANSWER
Answered 2018-Jul-19 at 20:41The order by
on date column suppose to be descending to get latest inspection date
QUESTION
i am downloading the image from database and saving in download but want to save it in my own app named folder.
...ANSWER
Answered 2018-May-22 at 05:42File folder = new File(Environment.getExternalStorageDirectory() +File.separator + "YOUR_APP_NAME");
boolean success = true;
if (!folder.exists()) {
success = folder.mkdirs();
}
if (success) {
try {
bm.compress(Bitmap.CompressFormat.JPEG, 100, new FileOutputStream(new File(Environment.getExternalStorageDirectory() +
File.separator + "YOUR_APP_NAME" + File.separator + "file_name" + ".jpg")));
Toast.makeText(getActivity(), "Downloaded", Toast.LENGTH_SHORT).show();
} catch (FileNotFoundException e) {
e.printStackTrace();
}
} else {
// Do something else on failure
}
QUESTION
Below is a Archive PROBLEM from SPOJ. Sample testCase is passing, but I am getting W/A on submission. I am missing some testCase(testCases). Need help to figure out what case I am missing and/or what I am doing wrong here.
Ada the Ladybug is playing Game of Divisors against her friend Velvet Mite Vinit. The game has following rules. There is a pile of N stones between them. The player who's on move can pick at least 1 an at most σ(N) stones (where σ(N) stands for number of divisors of N). Obviously, N changes after each move. The one who won't get any stones (N == 0) loses.
As Ada the Ladybug is a lady, so she moves first. Can you decide who will be the winner? Assume that both players play optimally.
Input
The first line of input will contain 1 ≤ T ≤ 10^5, the number of test-cases. The next T lines will contain 1 ≤ N ≤ 2*10^7, the number of stones which are initially in pile.
Output
Output the name of winner, so either "Ada" or "Vinit".
Sample Input:
8
1
3
5
6
11
1000001
1000000
29
Sample Output:
Ada
Vinit
Ada
Ada
Vinit
Vinit
Ada
Ada
CODE
...ANSWER
Answered 2017-Dec-16 at 17:41There is a subtle bug in your countDivisors()
function. It assumes
that lastPrimeDivisor[num]
– as the name indicates – returns the
largest prime factor of the given argument.
However, that is not the case. For example, lastPrimeDivisor[num] = 2
for all even numbers, or lastPrimeDivisor[7 * 89] = 7
.
The reason is that in
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