redwood | The App Framework for Startups | GraphQL library
kandi X-RAY | redwood Summary
kandi X-RAY | redwood Summary
At the highest level, a Redwood app is a React frontend that talks to a custom GraphQL API. The API uses Prisma to operate on a database. Out of the box you get tightly integrated testing with Jest, logging with Pino, and a UI component catalog with Storybook. Setting up authentication (like Auth0) or CSS frameworks (like Tailwind CSS) are a single command line invocation away. And to top it off, Redwood's architecture allows you to deploy to either serverless providers (e.g. Netlify, Vercel) or traditional server and container providers (e.g. AWS, Render) with nearly no code changes between the two!. By making a lot of decisions for you, Redwood lets you get to work on what makes your application special, instead of wasting cycles choosing and re-choosing various technologies and configurations. Plus, because Redwood is a proper framework, you benefit from continued performance and feature upgrades over time and with minimum effort. Redwood is the latest open source project initiated by Tom Preston-Werner, cofounder of GitHub (most popular code host on the planet), creator of Jekyll (one of the first and most popular static site generators), creator of Gravatar (the most popular avatar service on the planet), author of the Semantic Versioning specification (powers the Node packaging ecosystem), and inventor of TOML (an obvious, minimal configuration language used by many projects). NOTICE: RedwoodJS is very close to a stable version 1.0. In the last two years, the project has matured significantly and is already used in production by a number of VC-backed startups. We are currently in the release candidate phase and intend to release a final v1.0.0 in March of 2022.
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QUESTION
I'm using TTK buttons in my tkinter application and they're appearing as the old TK buttons. I don't know why, but I would like to know how I can fix it, and why it happens. The application is basic, so if someone can help me, I would gladly appreciate help. This is my code, it's just some funny EA joke application:
...ANSWER
Answered 2021-Feb-10 at 15:31Your code did not import ttk
module. The following line just imports tkinter
and use ttk
as its alias name:
QUESTION
How do you concat numerous lists altogether into one single list, when there's a collection of lists assigned to only one variable already?
Most online advices has shown two or many variables to concat together, but mine's only a single variable assigned to many lists. I attempted at a nested For-Loop, but resulted in duplications and incoherent lists. Also attempted with extend and append functions with no success. Maybe I should approach this with Data Frame?
Any help is much appreciated. If you have questions, feel free to ask.
Actual Code:
...ANSWER
Answered 2021-Feb-09 at 15:11(Hopefully I understood the problem)
If each of the sublists is a variable, you can do one of the following to convert them into a single list:
QUESTION
I have code where I'm trying to index and pull data from a previous sheet. This code used to work, but now i'm getting a typeError
when running the code.
ANSWER
Answered 2021-Jan-28 at 09:45Array.prototype.indexOf() returns the first index at which a given element can be found in the array, or -1 if it is not present.
Based on the error you are getting I assume that this returns -1
:
QUESTION
I am trying to have an array be searched for a string by using a For loop, going through each spot of the array for its length. If the string is present, it should show that string (in this case, a letter). For some reason, even when that letter is there, the output is not being updated.
For example, say the word is DOG. The output array would look like '▢ ▢ ▢'. If I guessed 'D', it should update the output array to be 'D ▢ ▢'. The problem here is, it is not doing that.
This is my code related to this part:
...ANSWER
Answered 2020-Dec-07 at 15:13String comparisons are case sensitive. That means that the letter "e" is different from the letter "E". In your code, you are saying that the letter being guessed is a vowel if it's equal to "a", "e", "i", "o", "u", but you are not checking for "A", "E", "I", "O", "U".
As a consequence, you get "Test 1 guessed a consonant" when the input was "E".
If you want the comparison to be case sensitive, you should add the uppercase letters to your check. If you don't care about case sensitivity, you can apply the function toLowerCase() to your variable playerGuess before comparing it.
QUESTION
I have 2 pandas dataframes:
- state abbreviations and states.
- state names and all the national parks in each state. This is not the whole dataframe.
I need to search for a user input in the state dataframe, in this case the state abbreviation, then take the adjacent value, the full name and use that to display the correct column from the parks dataframe. I am sure this could be easier if they were one dataframe, but I could not figure a way to do that and keep all of the functionality; I want to be able to display the state dataframe for the user. Any suggestions would be really appreciated. here is my code. Around line 72 I could use help. I kept as much out as i could while keeping this functional, it is a large program, but this is my biggest problem so far. thank you
...ANSWER
Answered 2020-Nov-19 at 05:41You can do your task in this way:
Combine the all-states and abbreviations into a single column
QUESTION
Android emulator shows error when we launch a bare bone app, please see the screenshot attached. It works as expected for iOS.
I have tried all the default templates navbar,navdrawer and blank.
This is an app directly from the getting started page and no modifications have been made to the template code.
...ANSWER
Answered 2020-Sep-23 at 14:45The below solution worked for me
QUESTION
My question is very similar to this one, except that I want to exclude all columns that have a unique value in a column. If we assume that to be the input.
...ANSWER
Answered 2020-Jun-25 at 10:43Try this query:
QUESTION
I have a dataframe for all possible combinations of 2 stations in Caltrain and fare for the trip between them. I want to make a matrix of values but cannot understand how. Data looks like that:
...ANSWER
Answered 2020-May-24 at 21:16You need to use df.pivot()
.
QUESTION
I want to create the matrix with times to go from 1 station to another. I have done this matrix but I have some of the negative timedeltas in every column and row of the dataframe. It looks like that (it is a part of it):
...ANSWER
Answered 2020-May-24 at 15:09You could convert all to timedelta
, then stack
and filter:
QUESTION
I have a list of distance increase between every two adjacent stations in a railroad in the right order. What I need to do is to create a matrix for the distances between every two stations. This is this list.
...ANSWER
Answered 2020-May-24 at 10:49If the names of the station are the same in departure and arrival, maybe you can try something like this:
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