treat | : candy : Themeable , statically extracted CSS‑in‑JS | Runtime Evironment library
kandi X-RAY | treat Summary
kandi X-RAY | treat Summary
Write your styles in JavaScript/TypeScript within treat files (e.g. Button.treat.js) that get executed at build time. All CSS rules are created ahead of time, so the runtime is very lightweight—only needing to swap out pre-existing classes. In fact, if your application doesn’t use theming, you don’t even need the runtime at all. See the documentation at seek-oss.github.io/treat for more information about using treat.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of treat
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treat Examples and Code Snippets
Lines of Code : 26License : Permissive (MIT)
Copy// 1)
typeof NaN === 'number' // true
// 🤔 ("not a number" is a "number"...)
// 2)
isNaN('1') // false
// 🤔 the string '1' is not-"not a number"... so it's a number??
// 3)
isNaN('one') // true
// 🤔 'one' is NaN but `NaN === 'one'` is false...
License : No LicenseCopymodule.exports = {
plugins: [
require('autoprefixer'),
require('postcss-fail-on-warn')
]
}
for layer in model
for output_neuron in layer
for weight_element in parameters(output_neuron)
weight_element = sample(N(0, sqrt(2 / num_outputs(layer))))
end
end
sigmas[layer] = stddev(parameters(layer))
end
for c in 1-- sample data
WITH dataset (client, information) AS (
VALUES (1, '[ { "ProductId" : { "$binary" : "7KgRQKabqkuxE+1pSw9b7Q==", "$type" : "03" }, "Risk" : "0", "Due_data" : { "$date" : 1634860800000 }} ]')
)
--query
SELECT client,
create table Request_details
(
id varchar(11) not null,
request_submission_date datetime not null
)
create table request_status
(
task_date datetime not null,
task_name varchar(50) not null,
request_id varchar(11) not let date = '2021-11-19 00:00:000000';
// Split on any non–digit character
let [y, m, d] = date.split(/\D/);
// Months are zero indexed
// Treat input as local
console.log(new Date(y, m-1, d).toString());
// Treat input as UTC
console.log(nif (process.env.NODE_ENV === 'production') {
module.exports = require('./cjs/react.production.min.js');
} else {
module.exports = require('./cjs/react.development.js');
}
...
exports.Children = Children;
exportclient.on("message", async (message) => {
if (message.channel.id !== "869294795019923486") return;
if (message.author.bot) return;
message.react("⭐");
});
client.on("messageReactionAdd", (reaction, SELECT JSON_OBJECT (
'id' VALUE to_char(a.id),
'name' VALUE to_char(a.name),
'age' value to_char(a.age),
'original' value treat ( col as json ) -- this is the key
)
FROM tabla_json_1 a
where a.id = :agendamiento_id;
--Create a simple table.
create table table1
(
id number,
contractdatetime date,
Attr3 varchar2(100),
Attr4 varchar2(100),
Attr5 varchar2(100)
);
--Insert 4 rows, the first three will be identical between databases,
--Community Discussions
Trending Discussions on treat
QUESTION
How can I escape metacharacters in a Raku regex the way I would with Perl's quotemeta function (\Q..\E)?
That is, the Perl code
...ANSWER
Answered 2022-Feb-10 at 00:03You can treat characters in a Raku regex literally by surrounding them with quotes (e.g., '.*?') or by using using regular variable interpolation (e.g., $substring inside the regex where $substring is a string contaning metacharacters).
Thus, to translate the Perl program with \Q...\E from your question into Raku, you could write:
QUESTION
I'm pretty new to Swift, currently writing an AR game. Seems like my issue is very basic, but I can't figure it out.
I added a button to an AR Scene through the storyboard and linked it to an IBAction function (which works correctly when the button is clicked). I gave the button an image and deleted the Title. See how the button shows up in the storyboard: button in Xcode storyboard without Title
But when I run the app, the button image shows up with a default label (saying "Button") as shown in this image: button in iPhone screenshot WITH label next to the button image
I can't figure out why this label is there and how to remove it. Should I add the button programmatically instead of adding it through the storyboard? Should the button be treated differently because it's an AR app?
I was able to remove the label by adding the same UIButton as an IBOutlet and adding the following line in viewWillAppear:
...ANSWER
Answered 2021-Nov-23 at 21:07When Interface Builder isn't playing nice, I often open the Storyboard file in a text editor (I use Sublime Text) and edit it manually.
I had a similar issue - I had a button with an image, I had deleted the default "Button" title text in IB, which looked fine in Xcode, but when I ran it, the word "Button" was still there. So I found this line using Sublime Text and deleted it there:
QUESTION
Haskell typeclasses often come with laws; for instance, instances of Monoid are expected to observe that x <> mempty = mempty <> x = x.
Typeclass laws are often written with single-equals (=) rather than double-equals (==). This suggests that the notion of equality used in typeclass laws is something other than that of Eq (which makes sense, since Eq is not a superclass of Monoid)
Searching around, I was unable to find any authoritative statement on the meaning of = in typeclass laws. For instance:
- The Haskell 2010 report does not even contain the word "law" in it
- Speaking with other Haskell users, most people seem to believe that
=usually means extensional equality or substitution but is fundamentally context-dependent. Nobody provided any authoritative source for this claim. - The Haskell wiki article on monad laws states that
=is extensional, but, again, fails to provide a source, and I wasn't able to track down any way to contact the author of the relevant edit.
The question, then: Is there any authoritative source on or standard for the semantics for = in typeclass laws? If so, what is it? Additionally, are there examples where the intended meaning of = is particularly exotic?
(As a side note, treating = extensionally can get tricky. For instance, there is a Monoid (IO a) instance, but it's not really clear what extensional equality of IO values looks like.)
ANSWER
Answered 2022-Feb-24 at 22:30Typeclass laws are not part of the Haskell language, so they are not subject to the same kind of language-theoretic semantic analysis as the language itself.
Instead, these laws are typically presented as an informal mathematical notation. Most presentations do not need a more detailed mathematical exposition, so they do not provide one.
QUESTION
Say I have a custom container class that stores data in a map:
...ANSWER
Answered 2022-Jan-31 at 08:18Are view iterators valid beyond the lifetime of the view?
The property here is called a borrowed range. If a range is a borrowed range, then its iterators are still valid even if a range is destroyed. R&, if R is a range, is the most trivial kind of borrowed range - since it's not the lifetime of the reference that the iterators would be tied into. There are several other familiar borrowed ranges - like span and string_view.
Some range adaptors are conditionally borrowed (P2017). That is, they don't add any additional state on top of the range they are adapting -- so the adapted range can be borrowed if the underlying range is (or underlying ranges are). For instance, views::reverse(r) is borrowed whenever r is borrowed. But views::split(r, pat) isn't conditionally borrowed - because the pattern is stored in the adaptor itself rather than in the iterators (hypothetically, it could also be stored in the iterators, at a cost).
views::values(r) is an example of such: it is a borrowed range whenever r is borrowed. And, in your example, the underlying range is a ref_view, which is itself always borrowed (by the same principle that R& is always borrowed).
Note that here:
QUESTION
When type annotating a variable of type dict, typically you'd annotate it like this:
...ANSWER
Answered 2022-Jan-20 at 22:49With dict[str:int] the hint you are passing is dict whose keys are slices, because x:y is a slice in python.
The dict[str, int] passes the correct key and value hints, previously there also was a typing.Dict but it has been deprecated.
QUESTION
I am trying to audit my application on Chrome Lighthouse, but I can't get Service Worker working. It is registered and running with no error, but when I try to run Lighthouse it gets stuck and console log the fallowing error:
...ANSWER
Answered 2022-Jan-11 at 19:31If I uncheck the clear cache option in lighthouse options it starts working.
Edit: As mentioned by Sean McCarthy below the correct name is "Clear storage"
QUESTION
The standard defines several 'happens before' relations that extend the good old 'sequenced before' over multiple threads:
[intro.races]11 An evaluation A simply happens before an evaluation B if either
(11.1) — A is sequenced before B, or
(11.2) — A synchronizes with B, or
(11.3) — A simply happens before X and X simply happens before B.[Note 10: In the absence of consume operations, the happens before and simply happens before relations are identical. — end note]
12 An evaluation A strongly happens before an evaluation D if, either
(12.1) — A is sequenced before D, or
(12.2) — A synchronizes with D, and both A and D are sequentially consistent atomic operations ([atomics.order]), or
(12.3) — there are evaluations B and C such that A is sequenced before B, B simply happens before C, and C is sequenced before D, or
(12.4) — there is an evaluation B such that A strongly happens before B, and B strongly happens before D.[Note 11: Informally, if A strongly happens before B, then A appears to be evaluated before B in all contexts. Strongly happens before excludes consume operations. — end note]
(bold mine)
The difference between the two seems very subtle. 'Strongly happens before' is never true for matching pairs or release-acquire operations (unless both are seq-cst), but it still respects release-acquire syncronization in a way, since operations sequenced before a release 'strongly happen before' the operations sequenced after the matching acquire.
Why does this difference matter?
'Strongly happens before' was introduced in C++20, and pre-C++20, 'simply happens before' used to be called 'strongly happens before'. Why was it introduced?
[atomics.order]/4 says that the total order of all seq-cst operations is consistent with 'strongly happens before'.
Does it mean that it's not consistent with 'simply happens before'? If so, why not?
I'm ignoring the plain 'happens before', because it differs from 'simply happens before' only in its handling of memory_order_consume, the use of which is temporarily discouraged, since apparently most (all?) major compilers treat it as memory_order_acquire.
I've already seen this Q&A, but it doesn't explain why 'strongly happens before' exists, and doesn't fully address what it means (it just states that it doesn't respect release-acquire syncronization, which isn't completely the case).
Found the proposal that introduced 'simply happens before'.
I don't fully understand it, but it explains following:
- 'Strongly happens before' is a weakened version of 'simply happens before'.
- The difference is only observable when seq-cst is mixed with aqc-rel on the same variable (I think, it means when an acquire load reads a value from a seq-cst store, or when an seq-cst load reads a value from a release store). But the exact effects of mixing the two are still unclear to me.
ANSWER
Answered 2022-Jan-02 at 18:21Here's my current understanding, which could be incomplete or incorrect. A verification would be appreciated.
C++20 renamed strongly happens before to simply happens before, and introduced a new, more relaxed definition for strongly happens before, which imposes less ordering.
Simply happens before is used to reason about the presence of data races in your code. (Actually that would be the plain 'happens before', but the two are equivalent in absence of consume operations, the use of which is discouraged by the standard, since most (all?) major compilers treat them as acquires.)
The weaker strongly happens before is used to reason about the global order of seq-cst operations.
This change was introduced in proposal P0668R5: Revising the C++ memory model, which is based on the paper Repairing Sequential Consistency in C/C++11 by Lahav et al (which I didn't fully read).
The proposal explains why the change was made. Long story short, the way most compilers implement atomics on Power and ARM architectures turned out to be non-conformant in rare edge cases, and fixing the compilers had a performance cost, so they fixed the standard instead.
The change only affects you if you mix seq-cst operations with acquire-release operations on the same atomic variable (i.e. if an acquire operation reads a value from a seq-cst store, or a seq-cst operation reads a value from a release store).
If you don't mix operations in this manner, then you're not affected (i.e. can treat simply happens before and strongly happens before as equivalent).
The gist of the change is that the synchronization between a seq-cst operation and the corresponding acquire/release operation no longer affects the position of this specific seq-cst operation in the global seq-cst order, but the synchronization itself is still there.
This makes the seq-cst order for such seq-cst operations very moot, see below.
The proposal presents following example, and I'll try to explain my understanding of it:
QUESTION
I have the following function:
...ANSWER
Answered 2021-Nov-30 at 14:50you can cast it as a bool.
QUESTION
When defining a String using text blocks by default the trailing white space gets removed as it's treated as incidental white space.
...ANSWER
Answered 2021-Nov-03 at 14:10This can be done using an escape sequence for space at the end of a line. E.g.
QUESTION
Take a look at these two overloaded function templates:
...ANSWER
Answered 2021-Oct-08 at 23:05The non language lawyer answer is that there is a tie breaker rule for exactly this case.
Understanding standard wording well enough to decode it would require a short book chapter. But when deduced T&& vs T& overloads are options being chosen between for an lvalue and everything else ties, the T& wins.
This was done intentionally to (a) make universal references work, while (b) allowing you to overload on lvalue references if you want to handle them seperately.
The tie breaker comes from the template function overload "more specialized" ordering rules. The same reason why T* is preferred over T for pointers, even though both T=Foo* and T=Foo give the same function parameters. A secondary ordering on template parameters occurs, and the fact that T can emulate T* means T* is more specialized (or rather not not, the wording in the standard is awkward). An extra rule stating that T& beats T&& for lvalues is in the same section.
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