spectral | flexible JSON/YAML linter | REST library

 by   stoplightio TypeScript Version: v6.7.0 License: Apache-2.0

kandi X-RAY | spectral Summary

kandi X-RAY | spectral Summary

spectral is a TypeScript library typically used in Web Services, REST, Swagger applications. spectral has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

A flexible JSON/YAML linter for creating automated style guides, with baked in support for OpenAPI v3.1, v3.0, and v2.0 as well as AsyncAPI v2.x.
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            kandi-support Support

              spectral has a medium active ecosystem.
              It has 1939 star(s) with 194 fork(s). There are 30 watchers for this library.
              There were 1 major release(s) in the last 12 months.
              There are 114 open issues and 647 have been closed. On average issues are closed in 350 days. There are 9 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of spectral is v6.7.0

            kandi-Quality Quality

              spectral has 0 bugs and 0 code smells.

            kandi-Security Security

              spectral has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              spectral code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              spectral is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              spectral releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.
              It has 129 lines of code, 0 functions and 404 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

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            spectral Key Features

            No Key Features are available at this moment for spectral.

            spectral Examples and Code Snippets

            Convolutional weight matrix .
            pythondot img1Lines of Code : 125dot img1License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def linear_to_mel_weight_matrix(num_mel_bins=20,
                                            num_spectrogram_bins=129,
                                            sample_rate=8000,
                                            lower_edge_hertz=125.0,
                                            upper  
            Construct an exponential power convolution kernel .
            pythondot img2Lines of Code : 110dot img2License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def exponential_power_convolution_kernel(
                grid_shape,
                length_scale,
                power=None,
                divisor=None,
                zero_inflation=None,
            ):
              """Make an exponentiated convolution kernel.
            
              In signal processing, a [kernel]
              (https://en.wikipedia.org/w  
            Create a hamming window .
            pythondot img3Lines of Code : 24dot img3License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def hamming_window(window_length, periodic=True, dtype=dtypes.float32,
                               name=None):
              """Generate a [Hamming][hamming] window.
            
              Args:
                window_length: A scalar `Tensor` indicating the window length to generate.
                periodic: A b  

            Community Discussions

            QUESTION

            Spatial heatmap with given value for colour
            Asked 2022-Mar-20 at 14:15

            I built upon this thread to plot a spatial heatmap. The difference is that I do not want to compute the density of points because I already have the value for the level of "heat". In detail I want to plot the population density of the canton of Berne (Switzerland) with colour gradients.

            The population data is from the Swiss statistical office and counts the inhabitants per hectare (100m x 100m squares), downloadable here (the "STATPOP2020.csv" file). Building on jlhoward answer in thread my code so far is:

            ...

            ANSWER

            Answered 2022-Mar-20 at 14:15

            The problem, as you have already established, is that you want a contour map that represents population density, not the density of measurements, which is what stat_density_2d does. It is possible to create such an object in R, but it is difficult when the measurements are not spaced regularly on a grid (as is the case with this data). It may be best to use geom_point here for that reason:

            Source https://stackoverflow.com/questions/71546183

            QUESTION

            How to import Skimage to segment an image with watershed?
            Asked 2022-Mar-14 at 01:01

            I'm trying to use Skimage to segment an image with watershed, but I always get this error. Do you have a solution please?

            AttributeError: module 'skimage.morphology' has no attribute 'watershed'

            Source code : https://scikit-image.org/docs/0.12.x/auto_examples/xx_applications/plot_coins_segmentation.html

            ...

            ANSWER

            Answered 2022-Mar-14 at 01:01

            You are for some reason looking at the old documentation for scikit-image, version 0.12. (See the 0.12.x in the URL that you shared.) You can look at the examples for the latest released version at:

            https://scikit-image.org/docs/stable/auto_examples/

            Concretely for your code, you need to update the import to from skimage.segmentation import watershed.

            Source https://stackoverflow.com/questions/71461134

            QUESTION

            How to perform spatial crossvalidation using mlr3 and then perform raster predict
            Asked 2022-Mar-02 at 11:11

            I have the following problem. I want to build a model for landcover classification. My data are multitemporal Remote Sensing data with several bands. For training I created stratified randomly distributed points to extract spectral data at their positions. With these data a Random Forrest (Rpart) was trained using mlr3 package. For accuracy measurement a repeated spatial cross validation using mlr3spatiotempcv was performed. The resulting model of the training step is, after extraction, stored in an R Object of type rpart. In the terms field of this object are the variable names stored. These are all my used bands but also the spatial x and y coordinates. This brings problems when predicting new data. I used terra package and got an error the x and y layer are missing in my input data. Which kind of makes sense because they are stored in the terms field of the model. But from my understanding, the coordinates should not be a variable of the model. The coordinates are just used for spatial resampling and not for predicting. I "solved" this problem by removing x and y coordinates during the training process and perform just an ordinary non-spatial cross validation. After that I performed the prediction and it works perfectly.

            So, my Question is, how can I train a model, using mlr3 package, with data containing coordinates, to perform spatial cross validation?, and then use this model to predict a new Raster.

            ...

            ANSWER

            Answered 2022-Mar-02 at 11:11

            You have found a bug. When the task is created from a data.frame instead of an sf object, coords_as_features is set to TRUE. The default should be FALSE. You can install a fixed version of the package with remotes::install_github("mlr-org/mlr3spatiotempcv"). This fix should be included in the next CRAN version soon. Thanks for reporting.

            This brings problems when predicting new data.

            Why do you use the models from resampling to predict new data? Usually, you estimate the performance of the final model with (spatial) cross validation but the final model to predict new data is fitted on the complete data set.

            Source https://stackoverflow.com/questions/71308422

            QUESTION

            How to arrange bins in stacked histogram, Python
            Asked 2022-Mar-01 at 09:28

            I am working on a code of a stacked histogram and I need help arranging the bins in the order if this is possible.

            ...

            ANSWER

            Answered 2022-Mar-01 at 09:20

            QUESTION

            Is there a generalized version of scale_fill_distiller and scale_colour_distiller?
            Asked 2022-Feb-01 at 11:33

            I do different plots with ggplot2 and want them all to have the same colour. The thing is that I use different geoms that sometimes work with fill and sometimes with col. See here:

            ...

            ANSWER

            Answered 2022-Feb-01 at 11:33

            You can use the aesthetics parameter, either with scale_color_distiller or scale_fill_distiller:

            Source https://stackoverflow.com/questions/70939703

            QUESTION

            Create d3 linear color legend using d3 colors
            Asked 2022-Jan-26 at 13:10

            I want to create color legend using linear gradient > https://bl.ocks.org/HarryStevens/6eb89487fc99ad016723b901cbd57fde . But how can I pass my d3 colors here because its in the form like d3.scaleSequential(d3.interpolateViridis).domain([0,1]). In linear gradient the colors are passed as below :

            ...

            ANSWER

            Answered 2022-Jan-26 at 13:10

            Here's an example using d3.interpolateSpectral. You can create your data with d3.range and map:

            Source https://stackoverflow.com/questions/70829892

            QUESTION

            Extracting Instrument Qualities From Audio Signal
            Asked 2022-Jan-24 at 23:21

            I'm looking to write a function that takes an audio signal (assuming it contains a single instrument playing), out of which I would like to extract the instrument-like features out of the audio and into a vector space. So in theory, if I had two signals with similar-sounding instruments (such as two pianos), their respective vectors should be fairly similar (by euclidian distance/cosine similarity/etc.). How would one go about doing this?

            What I've tried: I'm currently extracting (and temporally averaging) the chroma energy, spectral contrast, MFCC (and their 1st and 2nd derivatives), as well as the Mel spectrogram and concatenating them into a single representation vector:

            ...

            ANSWER

            Answered 2022-Jan-24 at 23:21

            The part of the instrument audio that gives its distinctive sound, independently from the pitch played, is called the timbre. The modern approach to get a vector representation, would be to train a neural network. This kind of learned vector representation is often called to create an audio embedding.

            An example implementation of this is described in Learning Disentangled Representations Of Timbre And Pitch For Musical Instrument Sounds Using Gaussian Mixture Variational Autoencoders (2019).

            Source https://stackoverflow.com/questions/70841114

            QUESTION

            Matplotlib Colormaps – Choosing a different color for each graph/line/subject
            Asked 2021-Nov-30 at 10:40

            I created a script that reads and plots .txt files and their content (numbers/values). Each .txt file is located in a different folder. Each folder, in turn, represents one subject from which the data stems.

            This code works fine. Python reads each single .txt. file and plots 23 individual graphs/lines into one single plot. Python uses some standard colors here, i.e., each graph is automatically presented in a different color.

            What I would like to do is the following: Instead of using the standard colors that are assigned by python automatically without adding any color related code, I would like to use a specific colormap (for example "plasma") from matplotlib.

            The problem: no matter what code from the internet I use, all graphs/lines/subjects always receive the same color (e.g. the first color or last color from the plasma colormap).

            How do I specify the code so that every line gets one distinct color from a colormap of choice?

            Here is my code:

            ...

            ANSWER

            Answered 2021-Nov-30 at 04:22

            One way to achieve your goal is to slice-up a colormap and then plot each line with one of the resulting colors. See the lines below that can be integrated in your code in appropriate places.

            Source https://stackoverflow.com/questions/70142953

            QUESTION

            Fourier Transform Time Series in Python
            Asked 2021-Nov-27 at 13:26

            I've got a time series of sunspot numbers, where the mean number of sunspots is counted per month, and I'm trying to use a Fourier Transform to convert from the time domain to the frequency domain. The data used is from https://wwwbis.sidc.be/silso/infosnmtot. The first thing I'm confused about is how to express the sampling frequency as once per month. Do I need to convert it to seconds, eg. 1/(seconds in 30 days)? Here's what I've got so far:

            ...

            ANSWER

            Answered 2021-Nov-27 at 13:26

            You can use any units you want. Feel free to express your sampling frequency as fs=12 (samples/year), the x-axis will then be 1/year units. Or use fs=1 (sample/month), the units will then be 1/month.

            The extra line you spotted comes from the way you plot your data. Look at the output of the np.fft.fftfreq call. The first half of that array contains positive values from 0 to 1.2e6 or so, the other half contain negative values from -1.2e6 to almost 0. By plotting all your data, you get a data line from 0 to the right, then a straight line from the rightmost point to the leftmost point, then the rest of the data line back to zero. Your xlim call makes it so you don’t see half the data plotted.

            Typically you’d plot only the first half of your data, just crop the freqs and power_spectrum arrays.

            Source https://stackoverflow.com/questions/70131817

            QUESTION

            how to change / specify fill color which exceeds the limits of a gradient bar?
            Asked 2021-Nov-22 at 17:53

            In ggplot2/geom_tile, how to change fill color whice exceed the limits? As the image, Region_4/5 are out of limis(1,11) , so the fill color is default grey, how to change 'Region_4' to 'darkblue', 'Region_5' to 'black' . Thanks!

            ...

            ANSWER

            Answered 2021-Nov-22 at 10:06

            You can try scales::squish, define the limits, and put the out of bound (oob) values into the scalw:

            Source https://stackoverflow.com/questions/70060267

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install spectral

            Find more installation methods in our documentation.
            Run this command to get our predefined rulesets based on OpenAPI or AsyncAPI:
            Create your own ruleset.

            Support

            Documentation Getting Started - The basics of Spectral. Different Workflows - When and where should you use Spectral? Editors, Git-hooks, Continuous Integration, GitHub Actions, wherever you like! Using the command-line interface - Quickest way to get going with Spectral is in the CLI. Using the JavaScript API - Access the raw power of Spectral via the JS, or hey, TypeScript if you want. Custom Rulesets - Don't like our rules? Throw 'em out and make your own. Custom Functions - Rules can do absolutely anything, just write a little code. Take a look at our getting started documentation, then peek through some of our guides:
            Find more information at:

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