chrono | A natural language date parser in Javascript | Natural Language Processing library

 by   wanasit TypeScript Version: v2.6.3 License: MIT

kandi X-RAY | chrono Summary

kandi X-RAY | chrono Summary

chrono is a TypeScript library typically used in Artificial Intelligence, Natural Language Processing, Nodejs applications. chrono has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

A natural language date parser in Javascript.
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              chrono has a medium active ecosystem.
              It has 3247 star(s) with 335 fork(s). There are 35 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 109 open issues and 246 have been closed. On average issues are closed in 116 days. There are 5 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of chrono is v2.6.3

            kandi-Quality Quality

              chrono has 0 bugs and 0 code smells.

            kandi-Security Security

              chrono has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              chrono code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              chrono is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              chrono releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            chrono Key Features

            No Key Features are available at this moment for chrono.

            chrono Examples and Code Snippets

            How to detect dates with different formats
            JavaScriptdot img1Lines of Code : 5dot img1License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            npm i chrono-node
            
            import { parseDate } from 'chrono-node';
            const date = parseDate('This Friday at 13:00'); 
            

            Community Discussions

            QUESTION

            Find common rows across multiple, but not all available data frames, for all possible combinations of all those data frames
            Asked 2022-Mar-30 at 19:26

            I have multiple data frames with the following format:

            ...

            ANSWER

            Answered 2022-Mar-30 at 19:26

            One option involving dplyr and purrr could be:

            Source https://stackoverflow.com/questions/71681932

            QUESTION

            Is it guaranteed to be 2038-safe if sizeof(std::time_t) == sizeof(std::uint64_t) in C++?
            Asked 2022-Mar-25 at 17:04

            Excerpted from the cppref:

            Implementations in which std::time_t is a 32-bit signed integer (many historical implementations) fail in the year 2038.

            However, the documentation doesn't say how to detect whether the current implementation is 2038-safe. So, my question is:

            Is it guaranteed to be 2038-safe if sizeof(std::time_t) == sizeof(std::uint64_t) in C++?

            ...

            ANSWER

            Answered 2022-Mar-25 at 17:04

            Practically speaking yes. In all modern implementations in major OSes time_t is the number of seconds since POSIX epoch, so if time_t is larger than int32_t then it's immune to the y2038 problem

            You can also check if __USE_TIME_BITS64 is defined in 32-bit Linux and if _USE_32BIT_TIME_T is not defined in 32-bit Windows to know if it's 2038-safe

            However regarding the C++ standard, things aren't as simple. time_t in C++ is defined in which has the same content as in C standard. And in C time_t isn't defined to have any format

            3. The types declared are size_t (described in 7.19);

            Source https://stackoverflow.com/questions/70590092

            QUESTION

            Asio difference between prefer, require and make_work_guard
            Asked 2022-Feb-21 at 17:14

            In the following example I start a worker thread for my application. Later I post some work to it. To prevent it from returning prematurely I have to ensure "work" is outstanding. I do this with a work_guard object. However I have found two other ways to "ensure" work. Which one should I use throughout my application? Is there any difference?

            ...

            ANSWER

            Answered 2022-Feb-21 at 17:14

            My knowledge comes from e.g. WG22 P0443R12 "A Unified Executors Proposal for C++".

            Some differences up front: a work-guard

            • does not alter the executor, instead just calling on_work_started() and on_work_finished() on it. [It is possible to have an executor on which both of these have no effect.]
            • can be reset() independent of its lifetime, or that of any executor instance. Decoupled lifetime is a feature.

            On the other hand, using prefer/require to apply outstanding_work sub-properties:

            • modifies existing executors
            • notably when copied, all copies will have the same properties. This could be dangerous for something as invasive as keeping an execution context/resources around.
            Scanning The Field

            However, not all properties are requirable in the first place. Doing some reconaissance using Ex defined as:

            Source https://stackoverflow.com/questions/71194070

            QUESTION

            Create std::chrono::time_point from string
            Asked 2022-Feb-19 at 16:23

            A program like this

            ...

            ANSWER

            Answered 2022-Feb-19 at 16:23

            Just to be clear, there is no namespace date in C++20. So the code in the question should look like:

            Source https://stackoverflow.com/questions/71183145

            QUESTION

            Why does std::condition_variable::wait_for() return with timeout if duration too large?
            Asked 2022-Feb-11 at 06:13

            The following behavior was seen under g++ 11.2.1 . The std::condition_variable wait_for method returns immediately if the timeout variable is too large. In particular in the program below, if num_years==1, then the program hangs waiting as expected (presumably for 1 year), but if the variable num_years==1000 then the program returns immediatly.

            Why does this happen? Is this a bug in g++? And a related question, how do you make the cv.wait_for() wait indefinitely, instead of guessing a large timeout value?

            ...

            ANSWER

            Answered 2022-Feb-10 at 16:08

            This is an overflow bug under the hood of condition_variable::wait_for. Internally it is waiting using steady_clock which counts nanoseconds. This clock overflows at +/-292 years. So when 1000 years gets converted to nanoseconds, it is overflowing.

            This looks like a standards bug as opposed to an implementation bug: http://eel.is/c++draft/thread.condition#condvar-24

            The implementation should check for overflows of this type and in case found, just wait for the maximum time it is capable of waiting for.

            Source https://stackoverflow.com/questions/71068221

            QUESTION

            pybind11: send MPI communicator from Python to CPP
            Asked 2022-Jan-24 at 10:03

            I have a C++ class which I intend to call from python's mpi4py interface such that each node spawns the class. On the C++ side, I'm using the Open MPI library (installed via homebrew) and pybind11.

            The C++ class is as follows:

            ...

            ANSWER

            Answered 2022-Jan-24 at 10:03

            Using a void * as an argument compiled successfully for me. It's ABI-compatible with the pybind11 interfaces (an MPI_Comm is a pointer in any case). All I had to change was this:

            Source https://stackoverflow.com/questions/70423477

            QUESTION

            note: ld: library not found for -lpq when build rust in macOS
            Asked 2022-Jan-10 at 03:40

            When I build my rust project in macOS with apple sillicon using this command:

            ...

            ANSWER

            Answered 2021-Dec-17 at 20:55

            QUESTION

            How do I get a SystemTime from a human-readable date format in a cross-platform way? (Rust)
            Asked 2022-Jan-02 at 20:10

            How would I convert a human readable time (in any format, such as Tue, 1 Jul 2003 10:52:37 +0200) into a SystemTime, in a cross-platform way? I know about chrono::DateTime::from_rfc2822(), but I've been searching for quite a while and I can't find a way to convert a DateTime into a SystemTime. This conversion also needs to be cross-platform, so I can't use the platform-specific epochs (such as UNIX_EPOCH).

            Does anyone have any advice or ideas on how to do this?

            ...

            ANSWER

            Answered 2022-Jan-02 at 20:10

            There is a conversion available for DateTime to SystemTime, so you just need to call .into():

            Source https://stackoverflow.com/questions/70559280

            QUESTION

            C++ Linux fastest way to measure time (faster than std::chrono) ? Benchmark included
            Asked 2021-Dec-22 at 15:19
            #include 
            #include 
            using namespace std;
            
            class MyTimer {
             private:
              std::chrono::time_point starter;
              std::chrono::time_point ender;
            
             public:
              void startCounter() {
                starter = std::chrono::steady_clock::now();
              }
            
              double getCounter() {
                ender = std::chrono::steady_clock::now();
                return double(std::chrono::duration_cast(ender - starter).count()) /
                       1000000;  // millisecond output
              }
              
              // timer need to have nanosecond precision
              int64_t getCounterNs() {
                return std::chrono::duration_cast(std::chrono::steady_clock::now() - starter).count();
              }
            };
            
            MyTimer timer1, timer2, timerMain;
            volatile int64_t dummy = 0, res1 = 0, res2 = 0;
            
            // time run without any time measure
            void func0() {
                dummy++;
            }
            
            // we're trying to measure the cost of startCounter() and getCounterNs(), not "dummy++"
            void func1() {
                timer1.startCounter();  
                dummy++;
                res1 += timer1.getCounterNs();
            }
            
            void func2() {
                // start your counter here
                dummy++;
                // res2 += end your counter here
            }
            
            int main()
            {
                int i, ntest = 1000 * 1000 * 100;
                int64_t runtime0, runtime1, runtime2;
            
                timerMain.startCounter();
                for (i=1; i<=ntest; i++) func0();
                runtime0 = timerMain.getCounter();
                cout << "Time0 = " << runtime0 << "ms\n";
            
                timerMain.startCounter();
                for (i=1; i<=ntest; i++) func1();
                runtime1 = timerMain.getCounter();
                cout << "Time1 = " << runtime1 << "ms\n";
            
                timerMain.startCounter();
                for (i=1; i<=ntest; i++) func2();
                runtime2 = timerMain.getCounter();
                cout << "Time2 = " << runtime2 << "ms\n";
            
                return 0;
            }
            
            ...

            ANSWER

            Answered 2021-Dec-22 at 15:19

            What you want is called "micro-benchmarking". It can get very complex. I assume you are using Ubuntu Linux on x86_64. This is not valid form ARM, ARM64 or any other platforms.

            std::chrono is implemented at libstdc++ (gcc) and libc++ (clang) on Linux as simply a thin wrapper around the GLIBC, the C library, which does all the heavy lifting. If you look at std::chrono::steady_clock::now() you will see calls to clock_gettime().

            clock_gettime() is a VDSO, ie it is kernel code that runs in userspace. It should be very fast but it might be that from time to time it has to do some housekeeping and take a long time every n-th call. So I would not recommend for microbenchmarking.

            Almost every platform has a cycle counter and x86 has the assembly instruction rdtsc. This instruction can be inserted in your code by crafting asm calls or by using the compiler-specific builtins __builtin_ia32_rdtsc() or __rdtsc().

            These calls will return a 64-bit integer representing the number of clocks since the machine power up. rdtsc is not immediate but fast, it will take roughly 15-40 cycles to complete.

            It is not guaranteed in all platforms that this counter will be the same for each core so beware when the process gets moved from core to core. In modern systems this should not be a problem though.

            Another problem with rdtsc is that compilers will often reorder instructions if they find they don't have side effects and unfortunately rdtsc is one of them. So you have to use fake barriers around these counter reads if you see that the compiler is playing tricks on you - look at the generated assembly.

            Also a big problem is cpu out of order execution itself. Not only the compiler can change the order of execution but the cpu can as well. Since the x86 486 the Intel CPUs are pipelined so several instructions can be executed at the same time - roughly speaking. So you might end up measuring spurious execution.

            I recommend you to get familiar with the quantum-like problems of micro-benchmarking. It is not straightforward.

            Notice that rdtsc() will return the number of cycles. You have to convert to nanoseconds using the timestamp counter frequency.

            Here is one example:

            Source https://stackoverflow.com/questions/70444744

            QUESTION

            Most insanely fastest way to convert 9 char digits into an int or unsigned int
            Asked 2021-Dec-21 at 21:48
            #include 
            #include 
            #include 
            #include 
            using namespace std;
            
            const int p[9] =   {1, 10, 100, 
                                1000, 10000, 100000, 
                                1000000, 10000000, 100000000};
                                
            class MyTimer {
             private:
              std::chrono::time_point starter;
              std::chrono::time_point ender;
            
             public:
              void startCounter() {
                starter = std::chrono::steady_clock::now();
              }
            
              double getCounter() {
                ender = std::chrono::steady_clock::now();
                return double(std::chrono::duration_cast(ender - starter).count()) /
                       1000000;  // millisecond output
              }
            };
                                
            int convert1(char *a) {
                int res = 0;
                for (int i=0; i<9; i++) res = res * 10 + a[i] - 48;
                return res;
            }
            
            int convert2(char *a) {
                return (a[0] - 48) * p[8] + (a[1] - 48) * p[7] + (a[2] - 48) * p[6]
                        + (a[3] - 48) * p[5] + (a[4] - 48) * p[4] + (a[5] - 48) * p[3]
                        + (a[6] - 48) * p[2] + (a[7] - 48) * p[1] + (a[8] - 48) * p[0];
            }
            
            int convert3(char *a) {
                return (a[0] - 48) * p[8] + a[1] * p[7] + a[2] * p[6] + a[3] * p[5]
                        + a[4] * p[4] + a[5] * p[3] + a[6] * p[2] + a[7] * p[1] + a[8]
                        - 533333328;
            }
            
            const unsigned pu[9] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000,
                100000000};
            
            int convert4u(char *aa) {
              const unsigned char *a = (const unsigned char*) aa;
              return a[0] * pu[8] + a[1] * pu[7] + a[2] * pu[6] + a[3] * pu[5] + a[4] * pu[4]
                  + a[5] * pu[3] + a[6] * pu[2] + a[7] * pu[1] + a[8] - (unsigned) 5333333328u;
            }
            
            int convert5(char* a) {
                int val = 0;
                for(size_t k =0;k <9;++k) {
                    val = (val << 3) + (val << 1) + (a[k]-'0');
                }
                return val;
            }
            
            const unsigned pu2[9] = {100000000, 10000000, 1000000, 100000, 10000, 1000, 100, 10, 1};
            
            int convert6u(char *a) {
              return a[0]*pu2[0] + a[1]*pu2[1] + a[2]*pu2[2] + a[3] * pu2[3] + a[4] * pu2[4] + a[5] * pu2[5] + a[6] * pu2[6] + a[7] * pu2[7] + a[8] - (unsigned) 5333333328u;
            }
            
            using ConvertFunc = int(char*);    
            
            volatile int result = 0; // do something with the result of function to prevent unexpected optimization
            void benchmark(ConvertFunc converter, string name, int numTest=10000) {
                MyTimer timer;
                const int N = 100000;
                char *a = new char[9*N + 1];
                double runtime = 0;
                
                for (int t=1; t<=numTest; t++) {        
                    // change something to prevent unexpected optimization
                    for (int i=0; i<9*N; i++) a[i] = rand() % 10 + '0'; 
            
                    timer.startCounter();
                    for (int i=0; i<9*N; i+= 9) result = converter(a+i);
                    runtime += timer.getCounter();
                }
                cout << name << ": " << runtime << "ms\n";
            }   
            
            int main() {        
                benchmark(convert1, "slow");
                benchmark(convert2, "normal");    
                benchmark(convert3, "fast");
                benchmark(convert4u, "unsigned");
                benchmark(convert5, "shifting");
                benchmark(convert6u, "reverse");
                return 0;
            }
            
            ...

            ANSWER

            Answered 2021-Dec-20 at 12:59

            An alternative candidate

            Use unsigned math to avoid UB of int overflow and allow for taking all the - 48 out and then into a constant.

            Source https://stackoverflow.com/questions/70420948

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install chrono

            You can download it from GitHub.

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            Checkout the Typescript Documentation in the project's Github page.
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