Scythe | Deep learning library based on the gcForest algorithm | Machine Learning library

 by   AntoinePassemiers C++ Version: Current License: Apache-2.0

kandi X-RAY | Scythe Summary

kandi X-RAY | Scythe Summary

Scythe is a C++ library typically used in Artificial Intelligence, Machine Learning, Deep Learning, Pytorch applications. Scythe has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Under development Deep learning library based on deep forests. A deep forest consists of a stack of layers, where each of them learns from both the input features and the output features of the previous layer. Each layer is made of a series of complete-random forests. This results in a whole hierarchy of predictors, from single trees to deep forests. The rationale behind this project is to solve the problem of high dimensionality of fine grained scanners. Indeed, contrary to neural networks' convolutional layers, multi-grained scanners tend to increase the size of the temporary data due to slicing. To get around this issue, the concept of virtual datasets has been developed. Furthermore, fast tree learning algorithms have been implemented.
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              Scythe has a low active ecosystem.
              It has 12 star(s) with 4 fork(s). There are 8 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 1 have been closed. On average issues are closed in 9 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Scythe is current.

            kandi-Quality Quality

              Scythe has 0 bugs and 0 code smells.

            kandi-Security Security

              Scythe has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Scythe code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Scythe is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Scythe releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.
              It has 912 lines of code, 42 functions and 15 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Scythe
            Get all kandi verified functions for this library.

            Scythe Key Features

            No Key Features are available at this moment for Scythe.

            Scythe Examples and Code Snippets

            No Code Snippets are available at this moment for Scythe.

            Community Discussions

            QUESTION

            How do I make the box stay fixed while keeping it's position when scrolling on the side?
            Asked 2022-Mar-07 at 23:30

            I am having a problem with my code an would be highly grateful for some advise. I want the yellow square to stay at the left side, having it´s own column just as it is now but I want the square to be fixed on the screen while scrolling down. Every time I write position:fixed or write both position:left:fixed;" in my code it takes over and melts everything together into one column.

            Here comes the code!

            ...

            ANSWER

            Answered 2022-Mar-07 at 12:58

            The problem is that when you use position: fixed;, the element is no longer relative to the container but relative to the page or in other words positioned absolute. That makes it appear on top of the 2nd div. The solution is that you can use position: sticky; instead.. The appearance is a bit different though...

            Source https://stackoverflow.com/questions/71381210

            QUESTION

            Add navbar below logo and center the content
            Asked 2021-Sep-17 at 06:47

            I'm trying add a navbar with links that should be below a logo text and centered. However I can't get it to work properly in tablet/mobile view. I have a mockup to follow and have to use only HTML & CSS. I have tried push it with margin & padding but can't get it to be in the center.

            Help appreciated.

            Mockup

            ...

            ANSWER

            Answered 2021-Sep-17 at 06:47

            You are almost there, but you forgot to remove display: flex on responsive view changing it into display:block will fix your problem

            Source https://stackoverflow.com/questions/69218827

            QUESTION

            How to sort an array by numerical value?
            Asked 2021-May-01 at 14:24

            Consider this array:

            ...

            ANSWER

            Answered 2021-May-01 at 14:24

            QUESTION

            Checking an array to see if it is empty immediately following a shift
            Asked 2020-Aug-02 at 08:49

            So I'm making progress on my music bot. Currently, it shuffles the playlist, and plays every song in the playlist once. The next step is for me to make him re-shuffle the playlist after it has played every song, and go again (I'll make the catch to 'stop' him using a command later). In theory - all I have to do is add in a check that 'if the array contains an entry in the 0 position, play that next song', otherwise 'if the array was empty, shuffle the playlist again, and THEN play the next song'

            Unfortunately, even if the next song is undefined - the check is failing, and after the first run-through of the playlist, he starts spamming songs that are undefined. I have tried multiple ways of checking this. Checking if the entry in the array is undefined, checking if the length of the array is undefined, checking whether the entry was or was not contained in the original list of songs - same problem for all of them.

            ...

            ANSWER

            Answered 2020-Aug-02 at 08:49

            It's a bit hard without seeing all your code so I've made a simple version which should suit - it just prints rather than playing anything or messaging but this should be a reasonable structure for you.

            Source https://stackoverflow.com/questions/63213356

            QUESTION

            How to I make my music bot play a finite playlist of songs?
            Asked 2020-Aug-01 at 22:24

            Building further on my music bot... I'm trying to make the jump from having him play a single song, and then leave, to having him play a finite list of songs, and then leave.

            This should not be confused with a queue - the list of songs is predetermined and finite. It can't be added to or changed by the bot, at least at this time. The bot DOES shuffle the list though.

            The problem right now is that instead of playing the songs in the list, one by one - he plays the first song, then the second... and stops dead.

            I've tried setting up a loop based on the length of the SongToPlay array, but all that does is make the bot rapidly spam through each song (before the previous song had time to play), and leave.

            ...

            ANSWER

            Answered 2020-Aug-01 at 22:24
            const connection = message.member.voice.channel.name; const channel = message.member.voice.channel; message.channel.send("Now playing Scythe OST in the "+connection+" channel.");
            
            var SongToPlay = shuffle(testbells); channel.join().then(connection => {
                let currentSong = 0;
                const keepPlaying = () => {
                    console.log(`Now playing ${SongToPlay[currentSong]}.`);
                    message.channel.send(`Now playing ${SongToPlay[currentSong]}.`);
                    const dispatcher =
                    connection.play(`./Scythe Digital Edition - Soundtrack/${SongToPlay[currentSong]}.mp3`);
                    dispatcher.setVolume(0.1);
                    dispatcher.on("finish", () => {
                        if (currentSong < SongToPlay.length - 1) {
                            currentSong++;
                            keepPlaying();
                        }
            
                    });
                }
                keepPlaying();
            }).catch(console.error);
            

            Source https://stackoverflow.com/questions/63204935

            QUESTION

            Discord music bot doesn't leave the server when the song ends
            Asked 2020-Aug-01 at 09:55

            I am working on a discord bot now named Amadeus. Amadeus plays music when he receives a given command... well... he will. Right now while I'm still working on him he only plays one song. While he connects to the voice channel and plays his song perfectly fine - he does not leave the voice channel once his song is concluded. For some reason, I guess it never detects that the song ends? Any help appreciated

            ...

            ANSWER

            Answered 2020-Aug-01 at 09:55

            As @Tenclea suggested, if you take a look at the Discord.js Documentation > Topics you can see that dispatcher.on("finish", () => {}) is used.

            Source https://stackoverflow.com/questions/63203781

            QUESTION

            Use more than one core in bash
            Asked 2020-Mar-23 at 11:16

            I have a linux tool that (greatly simplifying) cuts me the sequences specified in illumnaSeq file. I have 32 files to grind. One file is processed in about 5 hours. I have a server on the centos, it has 128 cores.

            I've found a few solutions, but each one works in a way that only uses one core. The last one seems to fire 32 nohups, but it'll still pressurize the whole thing with one core.

            My question is, does anyone have any idea how to use the server's potential? Because basically every file can be processed independently, there are no relations between them.

            This is the current version of the script and I don't know why it only uses one core. I wrote it with the help of advice here on stack and found on the Internet:

            ...

            ANSWER

            Answered 2020-Mar-23 at 11:16

            IMHO, the most likely solution is GNU Parallel, so you can run up to say, 64 jobs in parallel something like this:

            Source https://stackoverflow.com/questions/60812172

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Scythe

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries
            CLONE
          • HTTPS

            https://github.com/AntoinePassemiers/Scythe.git

          • CLI

            gh repo clone AntoinePassemiers/Scythe

          • sshUrl

            git@github.com:AntoinePassemiers/Scythe.git

          • Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link