Cajita | An MPIKokkos library for logically rectilinear grids | Grid library

by ECP-copa C++ Version: 0.1.0 License: BSD-3-Clause

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | Cajita Summary

Cajita is a C++ library typically used in User Interface, Grid applications. Cajita has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A library for computations on logically rectilinear grids.

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Quality

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License

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Support

Cajita has a low active ecosystem.

It has 16 star(s) with 7 fork(s). There are 10 watchers for this library.

It had no major release in the last 12 months.

There are 0 open issues and 7 have been closed. On average issues are closed in 37 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Cajita is 0.1.0

Quality

Cajita has no bugs reported.

Security

Cajita has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

Cajita is licensed under the BSD-3-Clause License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

Cajita releases are available to install and integrate.

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Cajita Key Features

No Key Features are available at this moment for Cajita.

Cajita Examples and Code Snippets

No Code Snippets are available at this moment for Cajita.

Community Discussions

Trending Discussions on Cajita

I need to detect forms in ArrayList

QUESTION

I need to detect forms in ArrayList

Asked 2020-Oct-11 at 23:04

Hi my problem is that i have to implement a logic that detect if for example the "X" makes a 2x2 square. In this code you have to insert 4 times a string of 4 digits in an ArrayList in which it will be a "X" if its a a "plastic cube" ("plastic cube" helps to visualize that the output is a "plastic form") or a "." if its not.

So if the input is:

..XX

....

I have to detect that is a cube 2X2 and return for example "Its a cube".

I would appreciate if you could help me since I am stuck.

...

ANSWER

Answered 2020-Oct-11 at 23:04

You can do it like this:

Verify that a user-entered line is exactly 4 long and consists of only . and X, otherwise ask user to re-enter a valid line.
Once you have 4 valid lines, count the number of X's. If not 4, then it's not a square.
Find the first X, then:
- Check that next position in the line is also an X.
- Check that line below has X in same position.
- Check that line below has X in next position.
If any of those checks fail, then it's not a square.
Otherwise it's a square.

Have fun coding that.

Source https://stackoverflow.com/questions/64309758

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Cajita

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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