Voidt | level game based on Handmade Hero

 by   JoeyDeVries C++ Version: Current License: GPL-3.0

kandi X-RAY | Voidt Summary

kandi X-RAY | Voidt Summary

Voidt is a C++ library. Voidt has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

C/C++ Educational project of developing a low-level game based on Handmade Hero
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            kandi-support Support

              Voidt has a low active ecosystem.
              It has 30 star(s) with 7 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              Voidt has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Voidt is current.

            kandi-Quality Quality

              Voidt has no bugs reported.

            kandi-Security Security

              Voidt has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Voidt is licensed under the GPL-3.0 License. This license is Strong Copyleft.
              Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

            kandi-Reuse Reuse

              Voidt releases are not available. You will need to build from source code and install.

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Voidt
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            Voidt Key Features

            No Key Features are available at this moment for Voidt.

            Voidt Examples and Code Snippets

            No Code Snippets are available at this moment for Voidt.

            Community Discussions

            QUESTION

            Why is my ANTLR4 parser grammar erroring 'no viable alternative at input'?
            Asked 2021-Mar-25 at 02:52

            When I run my grammar (lexer and parser) in powershell, it produces these errors:

            ...

            ANSWER

            Answered 2021-Mar-23 at 10:50

            Both global and a are listed in your grammer under kwr rule.

            kwr is mentioned in the inl rule which isn't used anywhere. So your parser don't know how to deal with inl and don't know what to do with two inl chained together (global a)

            Source https://stackoverflow.com/questions/66761457

            QUESTION

            SFINAE using VoidT with different compilers leads to different results
            Asked 2019-Oct-10 at 15:12

            Consider the following code:

            ...

            ANSWER

            Answered 2019-Oct-10 at 14:59

            Was this a bug in GCC that was fixed?

            It was a defect in the standard. It was fixed retroactively for previous standard versions, but of course only newer compiler versions will have the fix. It was CWG Issue 1558, and to quote from it:

            The treatment of unused arguments in an alias template specialization is not specified by the current wording of 17.6.7 [temp.alias]. For example:

            Source https://stackoverflow.com/questions/58325738

            QUESTION

            C++ detection idiom failure with inheritance
            Asked 2019-Aug-07 at 20:58

            The below code fails to compile. For some reason inheriting from HasFoo causes IsWrapper to fail. It has something to do with the friend function foo() because inheriting from other classes seems to work fine. I don't understand why inheriting from HasFoo causes the detection idiom to fail.

            What is the proper way to detect WithFoo as a Wrapper?

            https://godbolt.org/z/VPyarN

            ...

            ANSWER

            Answered 2019-Aug-07 at 12:43

            I don't understand why inheriting from HasFoo causes the detection idiom to fail.

            Isn't completely clear to me also but surely a problem is that you use IsWrapper inside the body of HasFoo and, when you inherit HasFoo> from WithFoo you have that WithFoo is incomplete when you check it with IsWrapper.

            A possible solution (I don't know if acceptable for you) is define (and SFINAE enable/disable) foo() outside HasFoo.

            I mean... try rewriting HasFoo as follows

            Source https://stackoverflow.com/questions/57384751

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Voidt

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
          • HTTPS

            https://github.com/JoeyDeVries/Voidt.git

          • CLI

            gh repo clone JoeyDeVries/Voidt

          • sshUrl

            git@github.com:JoeyDeVries/Voidt.git

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