Hangman | Simple Hangman Program | Frontend Framework library
kandi X-RAY | Hangman Summary
kandi X-RAY | Hangman Summary
The project started as a goal to learn C++. As I learned more, I improved the application, and now its just something to fool around with. After finding GitHub, this was the only "useful" project to upload as to test out GitHub. I plan to convert this to pure C and clean up the code. Then I'll improve it where I can.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Hangman
Hangman Key Features
Hangman Examples and Code Snippets
def display_hangman(tries):
stages = ["""
--------
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| 0
| \\|/
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| / \\
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Community Discussions
Trending Discussions on Hangman
QUESTION
I am trying to make a simple function that gets three inputs: a list of words, list of guessed letters and a pattern. The pattern is a word with some letters hidden with an underscore. (for example the word apple and the pattern '_pp_e') For some context it's a part of the game hangman where you try to guess a word and this function gives a hint. I want to make this function to return a filtered list of words from the input that does not contain any letters from the list of guessed letters and the filtered words contain the same letters and their position as with the given pattern. I tried making this work with three loops.
- First loop that filters all words by the same length as the pattern.
- Second loop that checks for similarity between the pattern and the given word. If the not filtered word does contain the letter but not in the same position I filter it out.
- Final loop checks the filtered word that it does not contain any letters from the given guessed list.
I tried making it work with not a lot of success, I would love for help. Also any tips for making the code shorter (without using third party libraries) will be a appreciated very much. Thanks in advance!
Example: pattern: "d _ _ _ _ a _ _ _ _" guessed word list ['b','c'] and word list contain all the words in english. output list: ['delegating', 'derogation', 'dishwasher']
this is the code for more context:
...ANSWER
Answered 2022-Apr-01 at 12:39Probably not the most efficient, but this should work:
QUESTION
I'm using Python 3, and I'm currently attempting to create a text-based version of Wordle. I've got much of the code down except for its alphabet feature.
In essence, it's an alphabet that eliminates any letter in the 6 guesses you get that isn't in the correct answer at all. It's similar to the game Hangman, in fact.
Now, to try and implement this into the game, I have a piece of code that checks the user's guess for any letters not in the answer, and leaves them while deleting letters that are in any place in the answer.
The problem is that I want to append these discarded letters to an outside string, which gets fed into a system that removes said letters from the string alphabet
("ABCDEFGHIJKLMNOPQRSTUVWXYZ
). Unfortunately, I am using a while loop to obtain inputs, and it doesn't seem to work.
In summary, I want to find a way to have string inputs be obtained from within a while loop and appended to an outside string, which I imagine looks like this in code:
...ANSWER
Answered 2022-Mar-25 at 16:18Possibly this can be implemented directly with a set
, removing remaining characters and intermediately displaying them
QUESTION
Im making a hangman game in python. and now i got stuck in a problem. i want the for loop to print display that says
wanted output: ['_', '_', '_', '_', '_']
ANSWER
Answered 2022-Feb-20 at 14:49Seems like you indented the print(display)
statement and added it to the for loop. Just unindent the loop and The code should work.
QUESTION
I have a problem with Object-Oriented Project Hangman - serialization part. I saved my code in serialize method, but when I try to unserialize it, I have a problem with it. I see all components of classes in the YAML file and when I try to reach them with code, I can't do it. I don't know where the problem is. Here is my serialize method and deserialize method.
...ANSWER
Answered 2022-Feb-20 at 14:15I think it's actually working fine.
YAML.load
returns an different instance of Game. You can call methods on that instance, but you don't have any access to the properties.
QUESTION
displayed_word = [" ", " ", " ", " "]
hangman = [":(", "-I", "-<", "you died!"]
guess_count = 0
secret_word = ["t", "e", "s", "t"]
miss_count = [-1]
def congratulations():
print("congratulations, you solved it")
def hangman_start():
guess = input("guess your letter:")
secret_word = ["t", "e", "s", "t"]
if guess == secret_word[0]:
displayed_word[0] = guess
if guess == secret_word[1]:
displayed_word[1] = guess
if guess == secret_word[2]:
displayed_word[2] = guess
if guess == secret_word[3]:
displayed_word[3] = guess
elif displayed_word == secret_word:
print("congratulations")
print(displayed_word)
if guess not in secret_word:
miss_count[0] += 1
print(hangman[miss_count[0]])
hangman_start()
hangman_start()
...ANSWER
Answered 2022-Feb-19 at 11:28break
is used to exit loops, such as for
or while
. Here your "loop" is actually recursion, so instead you want to use return
which makes the function return a value and stop, in our case we will simply return nothing, so None
. This should work:
QUESTION
So i want to make a simple hangman console game that chooses random words from a file. The problem is, when i try to check if the input is found in the word i'm trying to guess, the program jumps over the check. I'm thinking i made a serious mistake earlier in another functions and i don't know how to fix it. Below you can find the first function:
...ANSWER
Answered 2022-Jan-30 at 11:43I'm not sure why you have two for loops? The inner for loop checks whether the first letter matches, if it does then it prints correct and breaks, if it isn't then it prints incorrect and breaks so in both cases only the first letter is checked. The outer loop then runs again and again the inner loop checks the first letter. In the second iteration of the outer loop the inner loop again checks the first letter, if it was correct then it sets the second letter of the answer to the guessed character. If it was incorrect it uses up another life. I think you only need one for loop and your code can be simplified to:
QUESTION
I am trying to read JSON from a file in Rust which has the following dimensions:
...ANSWER
Answered 2022-Jan-10 at 18:07You can collect the map into a HashMap
or BTreeMap
and then use its key-value pairs to make a vector of words.
QUESTION
I'm working on a simple hangman app and I am trying to replace all the chars but three, in a word users have to guess, with underscores randomly.
So for example: America
to A_M___C_
I have most of it down, but my code sometimes leaves more than 3 characters unconverted to underscores. Here is my code:
...ANSWER
Answered 2022-Jan-05 at 13:10You have a few problems in your code. First of all the inner loop will restart for every character but that's not what you want. You want to put x underscores. Secondly, you only need to add your random choice, and not the while question. So, below a working program:
QUESTION
I have been trying to code a hangman game but couldn't do it because there seems to be an error with my if requests, because he dosn't detect a valid Letter in the word although there is .
please tell me if i can give you any more information. looking forward to hearing from yall and i am really interested in the skills i can learn:D
...ANSWER
Answered 2021-Dec-22 at 18:16The problem arises in your removeDupsBetter
method. You are trying to remove an element from L2
which is not present in L2
.
Maybe you actually meant to do this:
QUESTION
I have made a java code to play hangman game. I have given the user 15 chances to guess the word and once the user has guessed the correct answer it should execute the if statement but it does not. I have tried to solve this problem many times but it is never working. I would appreciate it if you could tell me the problem and give a suitable solution without making much change in my code.
My code:
...ANSWER
Answered 2021-Oct-27 at 05:42Try using equals()
method instead of ==
.
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