pareto | Spatial Containers , Pareto Fronts , and Pareto Archives | Machine Learning library
kandi X-RAY | pareto Summary
kandi X-RAY | pareto Summary
While most problems need to simultaneously organize objects according to many criteria, associative containers can only index objects in a single dimension. This library provides a number of containers with optimal asymptotic complexity to represent multi-dimensional associative containers. These containers are useful in many applications such as games, maps, nearest neighbor search, range search, compression algorithms, statistics, mechanics, graphics libraries, database queries, finance, multi-criteria decision making, optimization, machine learning, hyper-parameter tuning, approximation algorithms, networks, routing algorithms, robust optimization, design, and systems control.
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QUESTION
I simulated data with nrow=1000
(individuals) and ncol=100
(days) for step lengths according to a Pareto distribution function:
ANSWER
Answered 2021-Jun-07 at 12:17First, it looks like you have an error in your Rayleigh PDF. It should be:
QUESTION
I can't understand what's wrong with this code. Can someone help me please? This is a Pareto type II integrand from 1 to infinite and a and b are the parameters of the distribution. TypeError: object of type 'int' has no len() -> that's the error when I try to compute E
...ANSWER
Answered 2021-Jun-06 at 17:46Remove the line
QUESTION
ANSWER
Answered 2021-Jun-03 at 08:17One thing you could do would be to add a separate scaled y-axis for the geom_line
like this
QUESTION
I am trying to add a title to a dataframe when I write it into csv. My problems is that I am not managing to add the title above the dataframe.
I followed the advice in this link (How to add blank rows before a data frame while using pandas.to_csv) and add the title before the to_csv part but it's giving me the same result.
My code is:
...ANSWER
Answered 2021-Apr-06 at 15:11Change path
to outfile
in your table.to_csv()
and see how it works. Namely,
QUESTION
I have to carry out a challenge that involves the elaboration of an algorithm to compute the Pareto (set) boundary. The statement is basically:
Given a set S of n points in the square [0,1] x [0,1], make an algorithm to determine the subset P contained in S, formed by the non-dominated points of S.
It is also said that it is easy to elaborate an algorithm of the order n*n point comparisons that accomplish this purpose. Well I came up with an algorithm by researching here and there. The challenge is still to implement an algorithm of the order n*log(n). How do I get the order of these algorithms?
Thanks in advance!
...ANSWER
Answered 2021-Mar-30 at 02:21The intuition behind the efficient greedy solution to this problem lies in the fact that a point i
is dominated by point j
iff x[i] > x[j]
and y[i] > y[j]
, which implies that j
must come before i
when the points are ordered by either coordinate. Hence, if we traverse the points in increasing order of their x-coordinates, then the point j
(if any) that dominates point i
must have been traversed before point i
is traversed. In other words, it is impossible for the dominating point j
to come after the dominated point i
in this ordering.
Thus, with this traversal order the domination problem (i.e. checking if a point is dominated by some other point) boils down to checking if we have already seen a point with a lower y-coordinate as the traversal order already enforces the x-coordinate condition. This can easily be done by checking each point's y-coordinate to the lowest (minimum) y-coordinate we have seen so far -- if the minimum y-coordinate is less than the current point i
's y-coordinate then the point j
with the minimum y-coordinate dominates i
as x[j] < x[i]
because j
was seen before i
.
Sorting by the x-coordinate takes O(n log n)
time and checking each point (while maintaining the partial minimum y-coordinate) takes O(n)
time, making the entire algorithm take O(n log n)
time.
QUESTION
I need to create a table (either pivot or normal) that combines data laid out in this grid:
The grid shows the count of items by their size, broken down by width on one axis and height on the other. I can't figure out a way to correlate the sizes with the data. The only way I have gotten it to work so far is by manually creating table rows one by one using formulas that reference each cell.
For example, the table should read like this:
Size Count 3 X 3 0 3 X 4 0 3 X 6 20I'm eventually going to use this table to create a Pareto chart, but if I can create the chart from this grid that would work too.
...ANSWER
Answered 2021-Mar-22 at 15:44If you can get columns K and L below to show your distinct combinations, which shouldn't take more than several minutes, then the rest is pretty easy.
Column M is simply concatenating your results to show your data how you desire.
QUESTION
I'm trying to do an CLV analysis in R using the CLVTools package. This package is, according to the authors, an improved version for the BTYD package. I have no experience in this package so I'm sure this problem can be fixed fairly easily.
My data consists of a client_id, transaction_date and total_revenue, where each obsevation represents a customer purchase. This is all the data required in order to conduct a CLV analysis in my context.
The problem occours when I try to create the CLV data object using the clvdata()
function.
I get the error message:
ANSWER
Answered 2021-Feb-25 at 13:55Disclaimer: Im a co-creator of the package
These probabilistic models of latent attrition are usually applied on customer cohorts because it is assumed that cohorts substantially differ from each other. Hence, you fit one separate model on each cohort. Most commonly the definition of cohorts refers to the join-date (=first transaction) but any other (further) definition is possible, such as by channel or by business segment. See also Fader and Hardie (2010) about why to cohort-wise application is important: http://www.brucehardie.com/papers/022/fader_hardie_mksc_10.pdf
But regardless of your exact cohort definition, all customers are required to have made their first transaction during the estimation period: The model is fit on the transaction data that is present in the estimation period. For all customers that have made a transaction in the estimation period, the future number of transactions are predicted for the prediction horizon which you specify as if you were standing at the end of the estimation period. All customers therefore need to have made their first transaction in the estimation period in order for the model to "know" that they exist. The model can simply not make a prediction for a customer it does not know it exists (=did not make a transaction in the estimation period).
The package could simply remove the customers that do not make their first transaction in the estimation period and only make predictions for the ones that do. However, we believe that user should be aware what happens and therefore consciously prepare the data him/herself.
I should now be able to set the estimation.split to something valid, which is what exactly
You have to specify the estimation end to a date by which all the customers in your data have already made their first transaction. If this is not the case in your data, you should split your data into cohorts defined by first transaction.
Say you have customers transactions from 2015-01-01 until 2020-01-01 and would like to split at 2017-01-01. Then you could define the first cohort as all customers that made their first transaction (=joined) between 2015-01-01 to 2015-12-31 and the second cohort from 2016-01-01 to 2016-12-31. You would create 2 separate clvdata objects for each cohort and then also fit 2 separate models. Note that you cannot create a third cohort from 2017-01-01 to 2018-01-01 with the estimation split at 2017-01-01, rather for this 3rd cohort you would have to define a later split date, say 2019-01-01.
Other cohorting windows such as 1month, 3month, 6month etc are also customary but depend on your data. Make sure to choose an estimation period long enough for the model to actually see the repeat-purchase patterns per customer (check mean interpurchase time in summary(clvdata)
). For this reason, the estimation period is commonly longer than the cohorting window, ie the estimation end for a cohort is after max(customer_join_date). You might also be interested in my more in-depth answer about data preparation and cohort-wise analysis here:
https://github.com/bachmannpatrick/CLVTools/issues/101
https://github.com/bachmannpatrick/CLVTools/issues/146
However, I would also like to use the model for prediction, which requires a holdout period
After you have successfully fit the model, you can always make a prediction, also without holdout period. However, you have to specify the prediction.end
argument to tell how far ahead you want to predict (number of periods or exact date). You do not have to specify the prediction.end
if your data has a holdout period, because it then defaults to the holdout period. The same applies for prediction.end
in plot()
.
To make your final CLV prediction, its actually customary to fit the model on all data in the cohort (ie without holdout period)
QUESTION
I am working with a user generated data set (say it's app user data or service), and I cluster it based on user behaviour characteristics i.e. frequency of use. I would like to see how many, or what percentage of users stop using the app/service after a specific date and from what cluster they come from.
Here is an reproducible example which I hope is appropriate:-
...ANSWER
Answered 2021-Mar-03 at 06:57library(lubridate)
how_many=function(df, cluster, my_date) {
df1=df%>%filter(ClusterName==cluster)
before=filter(df1, Datemy_date)
count=0
for (i in unique(before$id_sample)) {
if (i %in% after$id_sample) {
count=count+1
}
}
return(c(count, count/n_distinct(before$id_sample)))
}
QUESTION
I am working with a call log data set from a telephone hotline service. There are three call outcomes: Answered, Abandoned & Engaged. I am trying to find out the average time taken by each caller to contact the hotline again if they abandoned the previous call. The time difference can be either seconds, minutes, hours or days but I would like to get all four if possible.
Here is some mock data with the variables I am working with:-
...ANSWER
Answered 2021-Feb-18 at 13:05Keep rows in the data where the current row is "Abandoned"
and the next row is not "Abandoned"
for each ID
. Find difference in time between every 2 rows to get time required for the caller to make another call to service after it was abandoned, take average of each of the duration to get average time.
QUESTION
I am working with a longitudinal user event generated data set and I am trying to cluster the user ID's in the data at a Month-Year level using k-means. The idea is that I want to see how users disappear from or move into different cluster archetypes over the different timepoints.
Here is code I have so far, which contains a mock dataframe and the clustering process.
...ANSWER
Answered 2021-Feb-10 at 14:31I had to change your code a bit to make it run. CallerId
and ClusterName
are not part of callerData
. So first run this:
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