random-forest | Randomized Decision Trees : A Fast C Implementation | Machine Learning library
kandi X-RAY | random-forest Summary
kandi X-RAY | random-forest Summary
A Fast C++ Implementation of Random Forests. This header file contains a fast C++ implementation of Random Forests as described in: Leo Breiman. Random Forests. Machine Learning 45(1):5-32, 2001.
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QUESTION
I am using the R programming language. I am trying to fit a "Random Forest" (a statistical model) to my data, but the problem is : one of my categorical variables has more than 53 categories - apparently the "random forest" package in R does not permit the user to have more than 53 categories, and this is preventing me from using this variable in my model. Ideally, I would like to use this variable.
To illustrate this example, I created a data set (called "data") where one of the variables has more than 53 categories:
...ANSWER
Answered 2021-Apr-28 at 16:05I can tell you that the caret
approach is correct. caret
contains tools for data splitting, preprocessing, feature selection and model tuning with resampling cross-validation. Here I post a typical workflow for fitting a model with the caret
package (example with the data you posted).
First, we set a cross-validation method for tuning the hyperparameters of the chosen model (in your case the tuning parameters are mtry
for both ranger
and randomForest
, splitrule
and min.node.size
for ranger
). In the example, I choose a k-fold corss-validation with k=10
QUESTION
I was trying to improve my random forest classifier parameters, but the output I was getting, does not look like the output I expected after looking at some examples from other people.
The code I'm using:
...ANSWER
Answered 2021-Apr-19 at 14:44You are getting that output because of verbose=2
. The higher its value, the more text it will print. These text prompts are not the results. They just tell you what models the search is currently fitting to the data.
This is useful to see the current progress of your search (sometimes it can take days, so it's nice to know what part of the process the search is currently at). If you do not want this text to appear, set verbose=0
.
You have not gotten the expected result yet because rf_random
is still fitting models to the data.
Once your search has finished use rf_random.best_params_
to get the output you want.
QUESTION
The RMSE values in my MLP and LSTM model seems to change when tested on the same sample and model again and again. I found this question, where adding a random state solved the issue. Is there something like that I could do too?
Sharing my MLP code here:
...ANSWER
Answered 2021-Apr-17 at 21:47You should fix the seed for numpy and tensorflow backend
QUESTION
I used this site as a reference https://www.r-bloggers.com/2021/02/how-to-build-a-handwritten-digit-classifier-with-r-and-random-forests/
to write a handwritten digit classifier using R with random forests.
Is it possible to build a plot of the colMeans obtained at the end of the code? The MNIST train and test datasets (that you can find in the link above) don't have any column headings. I'm new to R and still learning. Any kind of help would be greatly appreciated.
Here's the code:
...ANSWER
Answered 2021-Feb-16 at 16:50I slightly modified your code by subsetting quite a bit both the train and test set to speed up the analysis. You are free to comment/delete the related lines. Please have a look at the code below and tell me if this is what you are looking for.
QUESTION
I am trying to fit a RandomForestClassifier, like this.
...ANSWER
Answered 2021-Jan-29 at 01:26Assume that you have this dataset:
QUESTION
I'm trying to build A conditional random field model, following this tutorial https://www.kaggle.com/shoumikgoswami/ner-using-random-forest-and-crf I have followed all the steps but for some reason when I run the line
...ANSWER
Answered 2021-Jan-05 at 09:53I solved the issue. As we can see on the data examples the y labels are a list of arrays containing integers 0s and 1s,. So after I changed the labels from the y variable from ints to strings of 0s and 1s, It did work.
QUESTION
I have been following along with this really helpful XGBoost tutorial on Medium (code used towards bottom of article): https://medium.com/analytics-vidhya/random-forest-and-xgboost-on-amazon-sagemaker-and-aws-lambda-29abd9467795.
To-date, I've been able to get data appropriately formatted for ML purposes, a model created based on training data, and then test data fed through the model to give useful results.
Whenever I leave and come back to work more on the model or feed in new test data however, I find I need to re-run all model creation steps in order to make any further predictions. Instead I would like to just call my already created model endpoint based on the Image_URI and feed in new data.
Current steps performed:
Model Training
...ANSWER
Answered 2020-Nov-11 at 15:26that's a good question :) I agree, many of the official tutorials tend to show the full train-to-invoke pipeline and don't emphasize enough that each step can be done separately. In your specific case, when you want to invoke an already-deployed endpoint, you can either: (A) use the invoke API call in one of the numerous SDKs (example in CLI, boto3) or (B) or instantiate a predictor
with the high-level Python SDK, either the generic sagemaker.model.Model
class or its XGBoost-specific child: sagemaker.xgboost.model.XGBoostPredictor
as illustrated below:
QUESTION
The same question has been asked. But since the OP didn't post the code, not much helpful information was given.
I'm having basically the same problem, where for some reason shuffling data is making a big accuracy gain (from 45% to 94%!) to my random forest classifier. (In my case removing duplicates also affected the accuracy, but that may be a discussion for another day) Based on my understanding on how RF algorithm works, this really should not happen.
My data are merged from several files, each containing the same samples in the same order. For each sample, the first 3 columns are separate outputs, but currently I'm just focusing on the first output.
The merged data looks like this. The output (1st column) is ordered and unevenly distributed:
...ANSWER
Answered 2020-Oct-20 at 03:49The unshuffled data you are using shows that values of certain features tend to be constant for some rows. This causes the forest to be weaker because all the individual tress composing it are weaker.
To see that, take an extreme reasoning; if one of the features is constant all along the data set (or if you use a chunk of this dataset where the feature is constant), then this feature brings nothing in entropy changes if selected. so this feature is never selected, and the tree underfits.
QUESTION
I'm referring to this Random Forrest Algorithm example to predict rejection in different stages.
I'm fetching values from the database for stages
and reject_count
. And using stages
values for x
and reject_count
values for y
.
My code is:
ANSWER
Answered 2020-Oct-05 at 10:51Two thing going on here
First your x and y does not have the same dimension one is a list of list the other a list. Secondly assuming that you want your data as an array of one observation per sample you should reshape your x value. more on that here
QUESTION
I was reading a blog about Feature Selection based on the density curves of the features. The blog is in R language and I am not familiar with that.
Blog:
- https://myabakhova.blogspot.com/2016/02/computing-ratio-of-areas.html
- https://www.datasciencecentral.com/profiles/blogs/choosing-features-for-random-forests-algorithm
The blog says if the density curves of two features are significantly different (look below the equation, which says > 0.75), then we can discard one of the features.
Now, I am familiar with how to plot density curves, but not sure how to get the intersection area. Any help with finding the intersection area is greatly appreciated.
Here is my attempt:
...ANSWER
Answered 2020-May-23 at 16:51
- How to find the area under each curve?
By numerical integration of the kde curve, e.g. using trapez:
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