anna | A low-latency , cloud-native KVS | Machine Learning library
kandi X-RAY | anna Summary
kandi X-RAY | anna Summary
Anna is a low-latency, autoscaling key-value store developed in the RISE Lab at UC Berkeley.
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Trending Discussions on anna
QUESTION
What would be the best way to use queued_Dr
to alter its values like upcoming_appointments.PCD
by using all_appointments
?
What would be the best approach to this problem?
...ANSWER
Answered 2022-Jan-19 at 03:58The first solution is to find the name in all_appointments and return the corresponding abbreviation.
The second solution is to just compose the abbreviation without other arrays.
QUESTION
Is there a way to connect queued_Dr
to upcoming_appointments
by using all_appointments
What would be the best approach to this problem?
...ANSWER
Answered 2022-Jan-18 at 09:27From the information you have given to us you don't need upcoming_appointments
at all. The code below will return to you the desired result.
QUESTION
I'm struggling to strip down comma-separated strings to unique substrings in a cleanly fashion:
...ANSWER
Answered 2021-Nov-17 at 19:26You can use str_split
to get the individual substrings, followed by unique
to remove repeated strings. For example:
QUESTION
imagine, that i've some chatlog protocol. It could look like this:
...ANSWER
Answered 2021-Nov-10 at 14:15The following script:
QUESTION
I'm currently discovering all the possibilities of the Owlready library. Right now I'm trying to process some SWRL rules and so far it's been going very good, but I'm stuck at one point.
I've defined some rules in my ontology and now I want to see all the results (so, everything inferred from a rule).
For example, if I had a rule
has_brother(David, ?b) ^ has_child(?b, ?s) -> has_uncle(?s, David)
and David has two brothers, John and Pete, and John's kid is Anna, Pete's kid is Simon, I would like too see something like:
has_brother(David, John) ^ has_child(John, Anna) -> has_uncle(Anna, David)
has_brother(David, Pete) ^ has_child(Pete, Simon) -> has_uncle(Simon, David)
Is this possible in any way? I thought that maybe if I run the reasoner, I could see it in its output, but I can't find this anywhere.
I appreciate any help possible!
...ANSWER
Answered 2021-Oct-03 at 17:27This is my solution:
QUESTION
I'm new to C++, and I do not understand stacks that well. I tried following some tutorials to sort Stack1
using recursion, but nothing has been working or it is solely focused on arrays containing integers. I also tried sorting the Names
array directly, but it does not work. How do I go about sorting my Names
array for my Stack1
so in a non-complex manner (since I am new and do not understand it that well)?
Here's my code:
...ANSWER
Answered 2021-Sep-16 at 10:06To efficiently sort a stack, one would need to peek at random positions on the stack, preferably swapping the bottom of the stack with the largest element in the stack.
But this already violates the idea of the stack, thus we need something more, such as 2 or 3 more stacks.
One can start with one unsorted stack and two empty stacks, removing one item from the unsorted stack at a time and comparing if the element is smaller or larger than the top element of temporary stack A. If it's larger, place it on stack A, otherwise place it on stack B. In the end the largest element is at the top of stack A, and the original stack of random elements is empty. We can now move the top element from stack A to the top of the original stack, which starts to collect all the elements in descending order.
Then move all the elements from stacks A and B to the original stack and follow the previous step, except for last element, which is sorted.
If we are not allowed to know the size of the stacks (i.e. the number of iteration counts), then we need four stacks: unsorted, max so far, not max so far and sorted.
This algorithm would simulate bubble sort, however, since we know that the temporary stack A is partially sorted, we could probably utilise this fact to implement e.g. merge sort.
QUESTION
Suppose I have a data set with sales:
...ANSWER
Answered 2021-Sep-16 at 00:12I think separating the rows, extracting the project_id
s, attaching the details, nesting, and then joining back would be simpler and faster than trying to map
:
QUESTION
I'm designing an SSRS badge report for Avery 5392 badge stock (6 per page) that will also print each wearer's record ID on the back of their badge.
I've set up RowNumber & RowMod columns in my SELECT statement so that I can filter into my design elements only 3 rows of data per column and control which rows go on the left or right-side report elements, respectively. I've also set up PageNumber as a possible grouping option for page breaks.
Please consider this dummy table as a proxy for the data I'm actually using:
...ANSWER
Answered 2021-Sep-14 at 21:03I've taken your sample data and reworked the query to give the data I would use if I need to do this. It may not suit your setup exactly but it should be close enough to revise.
I basically output page numbers and row and column numbers from the dataset query that we can then use in a Matrix control.
Here's the modified query..
QUESTION
I am writing a program that functions like a bus ticket booking system. One of the features is that you can check the order history for customers. I am trying to figure out how to code so that the order history can be displayed like:
...ANSWER
Answered 2021-Aug-26 at 07:13zip
the values together
QUESTION
I'm attempting to replicate a search function in a messaging app with Firebase and display the results in a RecyclerView.
I would like to return users whose firstname, username, or lastname start with the search input text in the same recyclerview, in that order.
I am able to successfully search by one of the children, in this case I'm searching for a user's first name, but I'm really stuck as to how to add the results from the username and lastname, and in such a way that there is no duplication (e.g. if I search "A", a user with firstname "Anna" and lastname "Albury" doesn't appear twice.
Any and all help appreciated, thanks.
Activity searchUsers method:
...ANSWER
Answered 2021-Jul-30 at 08:23According to your last comment:
What I'm looking for is a way to get around this by effectively search three times, once for first names, once for last names, and once for usernames, and collate the resulting users in a single RecyclerView.
In this case, you should perform three different queries and collect all the results using Tasks.whenAllSuccess() method:
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