Regexp | Regular expression parser for microcontrollers | Parser library

 by   nickgammon C++ Version: Current License: No License

kandi X-RAY | Regexp Summary

kandi X-RAY | Regexp Summary

Regexp is a C++ library typically used in Utilities, Parser, Nodejs applications. Regexp has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Regular expression parser for microcontrollers based on the Lua one.
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              Regexp has a low active ecosystem.
              It has 66 star(s) with 16 fork(s). There are 8 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 8 have been closed. On average issues are closed in 1 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Regexp is current.

            kandi-Quality Quality

              Regexp has no bugs reported.

            kandi-Security Security

              Regexp has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Regexp does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              Regexp releases are not available. You will need to build from source code and install.

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            Regexp Key Features

            No Key Features are available at this moment for Regexp.

            Regexp Examples and Code Snippets

            copy iconCopy
            const escapeHTML = str =>
              str.replace(
                /[&<>'"]/g,
                tag =>
                  ({
                    '&': '&',
                    '<': '<',
                    '>': '>',
                    "'": ''',
                    '"': '"'
                  }[tag] || tag)
              );
            
            
            escapeHTML('
            copy iconCopy
            const get = (from, ...selectors) =>
              [...selectors].map(s =>
                s
                  .replace(/\[([^\[\]]*)\]/g, '.$1.')
                  .split('.')
                  .filter(t => t !== '')
                  .reduce((prev, cur) => prev && prev[cur], from)
              );
            
            
            const obj =   
            copy iconCopy
            const URLJoin = (...args) =>
              args
                .join('/')
                .replace(/[\/]+/g, '/')
                .replace(/^(.+):\//, '$1://')
                .replace(/^file:/, 'file:/')
                .replace(/\/(\?|&|#[^!])/g, '$1')
                .replace(/\?/g, '&')
                .replace('&', '?');
            
            
              

            Community Discussions

            QUESTION

            Regexp to match options which are delimited by spaces and also have spaces in their content
            Asked 2021-Jun-15 at 11:11

            I am parsing a Wordpress shortcode and want to use PCRE mainly with a view to finally getting my head around it.

            The following shortcode is one I wish to parse:

            ...

            ANSWER

            Answered 2021-Jun-15 at 11:11

            If you want to match attributes with single-quoted arguments you can use

            Source https://stackoverflow.com/questions/67984861

            QUESTION

            I have a question about regexp pattern matching for java
            Asked 2021-Jun-15 at 05:29

            I want to know the cause of regexp not working properly.

            ...

            ANSWER

            Answered 2021-Jun-15 at 05:29
            • ^[a-zA-Z]*$ Match at least 0 or more of lowercase/uppercase letters from beginning to the end. a+C+a+2+3 does not satisfy those requirements but an empty string does.
            • ^[0-9|*|+|/|-]*$ Match at least 0 or more of digits, *, +, / or - from beginning to the end; thus will match 1+2/33*4 and an empty string too.

            So, this might be the pattern you're looking for:

            Source https://stackoverflow.com/questions/67979564

            QUESTION

            Using regex on Python to find any numerical value in an expression
            Asked 2021-Jun-15 at 04:23

            I am trying to get all numerical value (integers,decimal,float,scientific notation) from an expression and want to differentiate them from digits that are not realy number but part of a name. For example in the expression below.

            ...

            ANSWER

            Answered 2021-Jun-15 at 04:23

            This should take care of it. (All the items are strings)

            Source https://stackoverflow.com/questions/67979579

            QUESTION

            Javascript Regex replace string with parameter
            Asked 2021-Jun-14 at 18:26

            I have a string like this:

            ...

            ANSWER

            Answered 2021-Jun-14 at 17:55

            Creating a regex using const regex = new RegExp(\\b{${i}}\\b, 'g') will generate a regex like /\b{0}\b/ and is not a valid expression.

            Also, you are not overwriting the value of message, and you do not need a new RegExp to do the replacements.

            You can use the counter between the curly braces to get the string to replace using {${i}}

            Source https://stackoverflow.com/questions/67974754

            QUESTION

            Lookahead in regular expressions
            Asked 2021-Jun-14 at 17:03

            I was taking freecodecamp.org course on JavaScript data structures, going through the RegExp chapter. I then came across the following assertion:

            "The regular expression /(?=\w{3,6})(?=\D*\d)/ will check whether a password contains between 3 and 6 characters and at least one number". (Here "check" meaning that regExp.test(password) returns true)

            This seems odd to me. First of all, looking around in Stack Exchange, I found in this post that states that A(?=B) is the definition of positive lookahead, and it makes no mention that A (the preceeding expression in the parenthesis) is optional. So, shouldn't freecodecamp's example have an expression before the first lookahead?

            I believe that this another example is quite similar to the previously mentioned, but simpler so I will mention it in case the explanation is simpler, too:

            Why does (?=\w)(?=\d), when checked against the string "1", returns true?, Shouldn't it look for an alphanumeric character followed by a numeric character?

            PS: After a thought, I hypothesized that my first example checks both lookahead patterns independently (i.e. first it checks whether the string is made of three to six characters, returns true, then checks whether there is an alpha numeric character, and finally since both searchings returned true, the whole regexp test returns true). But this doesn't seem to be coherent with the definition mentioned in the post I've linked. Is there a more general definition or algorithm which the computer "internally" uses to deal with lookaheads?

            ...

            ANSWER

            Answered 2021-Jun-14 at 16:03
            Definitions

            Lookaround are similar to word-boundary metacharacters like \b or the anchors ˆ and $ in that they don’t match text, but rather match positions within the text.

            Positive lookahead peeks forward in the text to see if its subexpression can match, and is successful as a regex component if it can. Positive lookahead is specified with the special sequence (?=...).

            Lookaround do not cosume text

            An important thing to understand about lookaround constructs is that although they go through the motions to see if their subexpression is able to match, they don’t actually “consume” any text.

            Examples

            Source https://stackoverflow.com/questions/67971883

            QUESTION

            Regex lookbehind/lookahead in Nashorn
            Asked 2021-Jun-14 at 14:49

            Here is what i want to do: I want to replace certain tokens in a string, but only if they are not inside another word. Example:

            ...

            ANSWER

            Answered 2021-Jun-14 at 14:49

            Assuming you want to replace pos only as a standalone word, just use word boundaries:

            Source https://stackoverflow.com/questions/67972392

            QUESTION

            RegExp for an identifier
            Asked 2021-Jun-14 at 07:27

            I am trying to write a regular expression for an ID which comes in the following formats:

            7_b4718152-d9ed-4724-b3fe-e8dc9f12458a

            b4718152-d9ed-4724-b3fe-e8dc9f12458a

            [a_][b]-[c]-[d]-[e]-[f]

            • a - optional 0-3 digits followed by an underscore if there's at least a digit (if there is underscore is required)
            • b - 8 alphanumeric characters
            • c - 4 alphanumeric characters
            • d - 4 alphanumeric characters
            • e - 4 alphanumeric characters
            • f - 12 alphanumeric characters

            I have came up with this regexp but I would appreciate any guidance and/or corrections. I am also not too sure how to handle the optional underscore in the first segment if there are no digits up front.

            /([a-zA-Z0-9]{0,3}_[a-zA-Z0-9]{8}-[a-zA-Z0-9]{4}-[a-zA-Z0-9]{4}-[a-zA-Z0-9]{4}-[a-zA-Z0-9]{12})+/g

            ...

            ANSWER

            Answered 2021-Jun-14 at 07:27

            Your regex looks good. To optionally match the first 3 digits with an underscore, you can wrap that group with ()?. Also you can force the presence of a digit before the underscore by using {1,3} instead of {0,3}.

            Unless you expect that multiple identifiers are following each other without space and should be matched as one, you can drop the last + (for multiple matches on the same line, you already have the g option).

            The final regex is ([a-zA-Z0-9]{1,3}_)?[a-zA-Z0-9]{8}-[a-zA-Z0-9]{4}-[a-zA-Z0-9]{4}-[a-zA-Z0-9]{4}-[a-zA-Z0-9]{12}

            See here for a complete example.

            If you also do not need to capture the individual 4-alphanumeric groups, you can simplify your regex into:

            ([a-zA-Z0-9]{1,3}_)?[a-zA-Z0-9]{8}-([a-zA-Z0-9]{4}-){3}[a-zA-Z0-9]{12}

            See here for an example.

            Source https://stackoverflow.com/questions/67966133

            QUESTION

            Error while trying to findNearLocation with Pageable in MongoDB and Spring
            Asked 2021-Jun-14 at 05:35

            I'm facing a strange error when I try to execute a find near with pageable in Mongodb and spring boot. My collection have 5 stores. When I call the method with the params: Page 0 and Page Size of 5 or below it works. But when I call it with a PageSize equals or greather than the total of stores I get this error. I noticed that the error occurs when the spring data mongo calls the method doCount internally but I have no idea what is wrong.

            Below is my code and the error:

            ----- Models ----

            ...

            ANSWER

            Answered 2021-Jun-13 at 12:13

            Guys I solved the problem. In my controller I was passing a GeoJsonPoint as parameter. When I changed to a Point it worked.

            ---- Before ----

            Source https://stackoverflow.com/questions/67953445

            QUESTION

            Iterate a MatchCollection backwards
            Asked 2021-Jun-13 at 22:27

            How can I iterate backwards a regexp's MatchCollection? The following code doesn't work (VBA-MSWORD)

            Set mtch = foundmatches(m) gives 'Invalid procedure call or argument (Error 5)'

            ...

            ANSWER

            Answered 2021-Jun-13 at 22:27

            Like this, as the Matches collection is zero-based

            Source https://stackoverflow.com/questions/67962954

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Regexp

            You can download it from GitHub.

            Support

            [Simplified documentation from MUSHclient help](http://www.gammon.com.au/scripts/doc.php?lua=string.find).
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            git@github.com:nickgammon/Regexp.git

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