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Intuitive syntax. In languages such as Python, JSON feels like a first class data type. We used all the operator magic of modern C++ to achieve the same feeling in your code. Check out the examples below and you'll know what I mean.
Trivial integration. Our whole code consists of a single header file json.hpp. That's it. No library, no subproject, no dependencies, no complex build system. The class is written in vanilla C++11. All in all, everything should require no adjustment of your compiler flags or project settings.
Serious testing. Our class is heavily unit-tested and covers 100% of the code, including all exceptional behavior. Furthermore, we checked with Valgrind and the Clang Sanitizers that there are no memory leaks. Google OSS-Fuzz additionally runs fuzz tests against all parsers 24/7, effectively executing billions of tests so far. To maintain high quality, the project is following the Core Infrastructure Initiative (CII) best practices.
Memory efficiency. Each JSON object has an overhead of one pointer (the maximal size of a union) and one enumeration element (1 byte). The default generalization uses the following C++ data types: std::string for strings, int64_t, uint64_t or double for numbers, std::map for objects, std::vector for arrays, and bool for Booleans. However, you can template the generalized class basic_json to your needs.
Speed. There are certainly faster JSON libraries out there. However, if your goal is to speed up your development by adding JSON support with a single header, then this library is the way to go. If you know how to use a std::vector or std::map, you are already set.
Python/Docker ImportError: cannot import name 'json' from itsdangerousAsked 2022-Mar-31 at 12:49
I am trying to get a Flask and Docker application to work but when I try and run it using my
docker-compose up command in my Visual Studio terminal, it gives me an ImportError called
ImportError: cannot import name 'json' from itsdangerous. I have tried to look for possible solutions to this problem but as of right now there are not many on here or anywhere else. The only two solutions I could find are to change the current installation of MarkupSafe and itsdangerous to a higher version: https://serverfault.com/questions/1094062/from-itsdangerous-import-json-as-json-importerror-cannot-import-name-json-fr and another one on GitHub that tells me to essentially change the MarkUpSafe and itsdangerous installation again https://github.com/aws/aws-sam-cli/issues/3661, I have also tried to make a virtual environment named
veganetworkscriptenv to install the packages but that has also failed as well. I am currently using Flask 2.0.0 and Docker 5.0.0 and the error occurs on line eight in vegamain.py.
Here is the full ImportError that I get when I try and run the program:
veganetworkscript-backend-1 | Traceback (most recent call last): veganetworkscript-backend-1 | File "/app/vegamain.py", line 8, in <module> veganetworkscript-backend-1 | from flask import Flask veganetworkscript-backend-1 | File "/usr/local/lib/python3.9/site-packages/flask/__init__.py", line 19, in <module> veganetworkscript-backend-1 | from . import json veganetworkscript-backend-1 | File "/usr/local/lib/python3.9/site-packages/flask/json/__init__.py", line 15, in <module> veganetworkscript-backend-1 | from itsdangerous import json as _json veganetworkscript-backend-1 | ImportError: cannot import name 'json' from 'itsdangerous' (/usr/local/lib/python3.9/site-packages/itsdangerous/__init__.py) veganetworkscript-backend-1 exited with code 1
Here are my requirements.txt, vegamain.py, Dockerfile, and docker-compose.yml files:
Flask==2.0.0 Flask-SQLAlchemy==2.4.4 SQLAlchemy==1.3.20 Flask-Migrate==2.5.3 Flask-Script==2.0.6 Flask-Cors==3.0.9 requests==2.25.0 mysqlclient==2.0.1 pika==1.1.0 wolframalpha==4.3.0
# Veganetwork (C) TetraSystemSolutions 2022 # all rights are reserved. # # Author: Trevor R. Blanchard Feb-19-2022-Jul-30-2022 # # get our imports in order first from flask import Flask # <-- error occurs here!!! # start the application through flask. app = Flask(__name__) # if set to true will return only a "Hello World" string. Debug = True # start a route to the index part of the app in flask. @app.route('/') def index(): if (Debug == True): return 'Hello World!' else: pass # start the flask app here ---> if __name__ == '__main__': app.run(debug=True, host='0.0.0.0')
FROM python:3.9 ENV PYTHONUNBUFFERED 1 WORKDIR /app COPY requirements.txt /app/requirements.txt RUN pip install -r requirements.txt COPY . /app
version: '3.8' services: backend: build: context: . dockerfile: Dockerfile command: 'python vegamain.py' ports: - 8004:5000 volumes: - .:/app depends_on: - db # queue: # build: # context: . # dockerfile: Dockerfile # command: 'python -u consumer.py' # depends_on: # - db db: image: mysql:5.7.22 restart: always environment: MYSQL_DATABASE: admin MYSQL_USER: root MYSQL_PASSWORD: root MYSQL_ROOT_PASSWORD: root volumes: - .dbdata:/var/lib/mysql ports: - 33069:3306
How exactly can I fix this code? thank you!
ANSWERAnswered 2022-Feb-20 at 12:31
I was facing the same issue while running docker containers with flask.
2.0.1 which solved my issue.
Check this for reference.
No vulnerabilities reported
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