xenia | Xbox 360 Emulator Research Project | Emulator library

by xenia-project C++ Version: Current License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(5)Vulnerabilities Install Support

kandi X-RAY | xenia Summary

xenia is a C++ library typically used in Utilities, Emulator, Discord applications. xenia has no bugs, it has no vulnerabilities and it has medium support. However xenia has a Non-SPDX License. You can download it from GitHub.

Xenia is an experimental emulator for the Xbox 360. For more information, see the main Xenia wiki. Interested in supporting the core contributors? Visit Xenia Project on Patreon. Come chat with us about emulator-related topics on Discord. For developer chat join #dev but stay on topic. Lurking is not only fine, but encouraged! Please check the FAQ page before asking questions. We've got jobs/lives/etc, so don't expect instant answers. Discussing illegal activities will get you banned.

Support

Quality

Security

License

Reuse

Support

xenia has a medium active ecosystem.

It has 6900 star(s) with 1007 fork(s). There are 431 watchers for this library.

It had no major release in the last 6 months.

There are 205 open issues and 698 have been closed. On average issues are closed in 147 days. There are 62 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of xenia is current.

Quality

xenia has 0 bugs and 0 code smells.

Security

xenia has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

xenia code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

xenia has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

xenia releases are not available. You will need to build from source code and install.

Installation instructions are available. Examples and code snippets are not available.

It has 6313 lines of code, 176 functions and 44 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

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xenia Key Features

No Key Features are available at this moment for xenia.

xenia Examples and Code Snippets

No Code Snippets are available at this moment for xenia.

Community Discussions

Trending Discussions on xenia

I want to make a statement for select data from MySQL database. But output just show the last row data from table

Pivot table with minimum in SAS

Stress Test POST with Multiple Body using Apache JMeter

how to get the last result after looping at C#

How to add information to the x-axis label of the plotted graph in Python?

QUESTION

I want to make a statement for select data from MySQL database. But output just show the last row data from table

Asked 2021-Dec-28 at 20:26

This is my PHP code:

...

ANSWER

Answered 2021-Dec-28 at 18:09

Push each row of results onto an array, and encode that.

Source https://stackoverflow.com/questions/70510394

QUESTION

Pivot table with minimum in SAS

Asked 2021-Apr-30 at 02:07

I have a table that looks like this :

...

ANSWER

Answered 2021-Apr-30 at 02:07

You will need to pre-process the data so that there is only one value per cell (i.e. per combination of country+class). At that point PROC REPORT with a stacked across column specification will display the names in the cells. A sneaky trick is also needed in order to force REPORT into this layout mode.

Example:

Source https://stackoverflow.com/questions/67326883

QUESTION

Stress Test POST with Multiple Body using Apache JMeter

Asked 2021-Feb-23 at 07:19

How can I stress test POST multiple Body with specified body data?

Here are my Body Data:

...

ANSWER

Answered 2021-Feb-23 at 05:08

You can parametrize band/model and try to read in form csv file so your body will be as below

Source https://stackoverflow.com/questions/66326606

QUESTION

how to get the last result after looping at C#

Asked 2020-Mar-01 at 05:56

Hello i'm new at C# and programming so i get stuck for hours to get the last result from my looping result here my code :

...

ANSWER

Answered 2020-Mar-01 at 05:46

You can use IEnumerable.Last():

var last = strlist.Last();

Remember to include Linq:

using System.Linq;

Source https://stackoverflow.com/questions/60472347

QUESTION

How to add information to the x-axis label of the plotted graph in Python?

Asked 2020-Feb-07 at 15:06

import pandas as pd
import matplotlib.pyplot as plt

my_funds = [10, 20, 50, 70, 90, 110]
my_friends = ['Angela', 'Gabi', 'Joanna', 'Marina', 'Xenia', 'Zulu']
my_actions = ['sleep', 'work', 'play','party', 'enjoy', 'live']
df = pd.DataFrame({'Friends': my_friends, 'Funds':my_funds, 'Actions': my_actions})

...

ANSWER

Answered 2020-Feb-07 at 15:00

A solution could be to create a new column in your DataFrame:

Source https://stackoverflow.com/questions/60115776

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install xenia

See the Quickstart page.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: