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QUESTION
switch(arg0.getKeyCode()) {
//if keycode is 'd' key
case 68:
break;
case 65:
System.out.println("stuff for left key using a");
break;
case 87:
shark.MoveUp();
break;
case 38:
shark.MoveUp();
break;
case 82:
new Game();
break;
}
...ANSWER
Answered 2021-Jun-14 at 22:15i'd highly recommend on using JFrame.dispose() ONthe old Game as long as it expanding JFrame. If not you can add a method to the Game class that will dispose the JFrame it contains. A method as such will look like that:
QUESTION
Unity2D How to make game object to face opposite from the position of another game object? I have a fish that is going always forward and randomly rotating to make semi random movement, and i want that in range of player(shark) the fish change direction opposite to shark and start moving faster(trying to escape). I have speed increase already but i doknt know how to make the opposite direction.
...ANSWER
Answered 2021-Jun-13 at 14:55Notice: at the part when I am saying to add/subtract 90 (you’ll know when you get there), try adding 90, if that doesn’t work, try subtracting 90 to get the right result.
To make it move fully the opposite direction, you should do a few things. First, I will tell you about Mathf.Atan2(float y, float x)
. Atan2 is arctangent. Arctangent takes a position, and finds the amount of rotations to rotate at that object, in radians. Then, you would want to multiply by Mathf.Rad2Deg
, or radians to degrees. It converts radians to degrees, which unity uses. Then, you would add some degrees to face the opposite direction.
Here is a way to make an object look away from the the mouse:
QUESTION
I'm trying to create a simple quiz with struct. But my program here is very repetitive. How can I modify it and make it more efficient? Especially to check if the answers are correct I do not want to declare a separate variable and store it as int correct
. Thank You.
ANSWER
Answered 2021-Jun-11 at 09:50The only thing you can do is define the correct
variable in the struct itself. You can use a loop for decreasing the repetitiveness but obviously the question and the answers will have to be stored, it cannot be simplified further.
QUESTION
Lately I have started implementing TLS for the sport as a fun project and I'm currently trying to self make and send locally a client hello TLS packet (a minimal one).
When observed via the loopback interface in Wireshark it appears as pure data instead of a tls layer with all of the various fields and after lots of trying I decided to ask here the following questions:
- What's the difference between my self made packet and a real TLS client hello one?
- How does Wireshark selectively makes one appear as a TLS layered instead of pure data, is there an identifier field in the packet that declares it as pure data or a TLS layered one?
- How can I make my packet to appear as a client hello TLS packet instead of pure data?
Here is my server and client that send basically my c code output (remember that they are not made for real TLS handling but just to show the packet in Wireshark):
server.py
...ANSWER
Answered 2021-Jun-01 at 21:45For starters, the TLS length field is wrong. Wireshark's TCP dissector indicates that the TCP payload length is 78 bytes; yet the TLS length is 165 (0x00a5), and thus can't be correct. Also, the handshake length is wrong too. Try changing this:
QUESTION
I have a data frame called animals
containing different sized columns that have some common and uncommon elements among each other as shown below:
ANSWER
Answered 2021-Jun-01 at 00:49We can use intersect
QUESTION
I have a dataframe which has a column of lists. I want to group the rows which have similar lists, irrespective of the order of the items in the list. Each list can occur multiple times within the column. I want the grouped lists sorted according to number of occurences within the column.
...ANSWER
Answered 2021-May-31 at 12:32data = [['a', ['tiger', 'cat', 'lion']], ['b', ['dolphin', 'goldfish', 'shark']], ['c', ['lion', 'cat', 'tiger']], ['d', ['bee', 'cat', 'tiger']],\
['e', ['cat', 'lion', 'tiger']], ['f', ['cat', 'bee', 'tiger']], ['g', ['shark', 'goldfish', 'dolphin']]]
df = pd.DataFrame(data)
df.columns = ['ID', 'animals']
df1 = df.assign(temp=df.animals.apply(lambda x: ''.join(sorted(x))))
df = df1.assign(temp2 =df1.groupby(df1['temp'].values)['temp'].transform('count')).sort_values(['temp2','temp'], ascending=False).drop(['temp','temp2'], 1)
QUESTION
I am trying to find out that how bitbake search for recipe in build process ? For example, I have a recipe something like below:
...ANSWER
Answered 2021-May-26 at 10:28You have two different files: a .bb
and a .bbappend
.
A .bb
is the base recipe of one (or multiple) packages. It generally describe how to fetch, configure, compile, install files in a package for your target.
A .bbappend
file is an 'append' file. It allows a meta (here meta-petalinux) to modify an existing recipe in another meta without copying it. A .bbappend
can modify any steps of the bb file: source fetch, configure, compile, install...
You can for example create your own bbappend of Gstreamer, to enable pango (disbaled by default on my Yocto). The bbappend filename is gstreamer1.0-plugins-base_%.bbappend
and only contains PACKAGECONFIG_append = "pango"
The Yocto Manual can give you more information on bbappend files here.
QUESTION
I am using the ActiveMQ Artemis Broker and publishing to it through a client application.
Behavior observed:
- When my client is IPV4 a TLS handshake is established and data is published as expected, no problems.
- When my client is IPV6 , I see frequent re-connections being established between the client and the server(broker) and no data is being published.
Details:
- When using IPV6 the client does a 3 way handshake and attempts to send data. It also receives a Server Hello and sends application data.
- But the connection terminates and again reconnects. This loop keeps occurring.
- The client library, network infrastructure, and broker are all completely the same when using IPv4 and IPv6.
The client logs say:
...ANSWER
Answered 2021-May-26 at 08:36The issue was caused due to a LB setting which had a default connection time out of 30 secs , lesser than the connection timeout set by the client.
QUESTION
My dataset, sharks for example, contains a variable of the species name, classified as a factor, and a variable month, also classified as a factor. What I want to do is create a separate bar chart for each month to show the number of each species caught in that month. Alternatively, a single stacked bar chart to show all 12 months. I've started a ggplot code, however, I don't know what to use as the y variable, as that should be the count for each species.
...ANSWER
Answered 2021-May-26 at 04:47You can use count
to find the count of Species in each month. Try -
QUESTION
I have combined 3 JSON files into a single array using flat(), and then looped through the array to output its contents in the console. It outputs an array of arrays created from the 3 JSON files below.
Here's the console output:
...ANSWER
Answered 2021-May-24 at 11:39I'm not sure if this is exactly what you wanted, cause you didn't specify exact output, but I think you get a point how can it be done.
Object.entries
/ Object.keys
/ Object.values
is something what you are looking for:
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