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QUESTION
This ANTLR4 parser grammar errors a 'no viable alternative' error when I try to parse an input. The only rules I know of that matches the part of the input with the error are the rules 'retblock_expr' and 'block_expr'. I have put 'retblock_expr' infront of 'block_expr' and put 'non_assign_expr' infront of 'retblock_expr' but it still throws the error.
input:
print(do { return a[3] })
full error:
line 1:11 no viable alternative at input '(do { return'
parser grammar:
...ANSWER
Answered 2021-Mar-27 at 14:13Your PRINT
token can only be matched by the blk_expr
rule through this path:
There is no path for retblock_expr
to recognize anything that begins with the PRINT
token.
As a result, it will not matter which order you have elk_expr
or retblock_expr
.
There is no parser rule in your grammar that will match a PRINT
token followed by a LPR
token. a block_expr
is matched by the program
rule, and it only matches (ignoring wsp) block_expr
or retblock_expr
. Neither of these have alternatives that begin with an LPR
token, so ANTLR can't match that token.
print(...)
would normally be matched as a function call expression that accepts 0 or more comma-separated parameters. You have no sure rule/alternative defined. (I'd guess that it should be an alternative on either retblock_expr
or block_expr
That's the immediate cause of this error. ANTLR really does not have any rule/alternative that can accept a LPR
token in this position.
QUESTION
When I run my grammar (lexer and parser) in powershell, it produces these errors:
...ANSWER
Answered 2021-Mar-23 at 10:50Both global
and a
are listed in your grammer under kwr
rule.
kwr
is mentioned in the inl
rule which isn't used anywhere. So your parser don't know how to deal with inl
and don't know what to do with two inl
chained together (global a
)
QUESTION
I wonder if Greenplum PXF can take advantage of HDFS short circuit read when we place pxf and datanode on the same host. We did a prelimiary test, however, it seems that pxf does not leverage the short circuit read. There is almost nothing after googling, so we are not sure if we miss something. We use Greenplum 6.4 (community version), pxf 5.11.2 and CDH 6.3.
Any references, suggestions or comments are very appreciated.
...ANSWER
Answered 2020-Apr-22 at 15:56The old version of PXF with hawq actually resides with data nodes and utilizes short-circuit read. THe current PXF has changed to reside with Greenplum segment hosts and acts like a hdfs client. I think you can tweak pxf source codes and setup pxf on datanodes with short-circuit read. However, you speed up the hdfs<->pxf communication, but slow down pxf<->greenplum segment communication.
QUESTION
I need to use image processing with LockBits instead of GetPixel/SetPixel to decrease the processing time. But in the end it saves not all changes.
Steps to reproduce the problem:
- Read all the bytes from initial bmp file;
- Change all these bytes and save it to a new file;
- Read saved file and compare its data with data you tried to save.
Expected: they are equal, but actually they are not.
I noticed that (See output):
- all the wrong values are equal to 0,
- indexes of wrong values are like: x1, x1+1, x2, x2+1, ...,
- for some files it can work as expected.
One more confusing thing: my initial test file is gray, but in HexEditor among the expected payload values we can see values "00 00". See here. What is that mean?
I have read and tried lots of LockBits tutorials on Stack Overflow, MSDN, CodeProject and other sites as well, but in the end it works the same.
So, here is the code example. Code of MyGetByteArrayByImageFile
and UpdateAllBytes
comes directly from msdn article "How to: Use LockBits" (method MakeMoreBlue
) with small changes: hardcoded pixel format replaced and every byte is changing (instead of every 6th).
Content of Program.cs
:
ANSWER
Answered 2018-Jul-30 at 00:14The only thing missing from your question is a sample input file, which based on your output I infer is a 54 x 23 pixel 24bpp bitmap.
The bytes that don't match the value you have set are padding bytes.
From Wikipedia:
For an image with a width of 54 pixels with 24 bits per pixel, this gives
Floor ((24 * 54 + 31) / 32) * 4
= Floor (1327 / 32) * 4
= 41 * 4
= 164
In this example, 164
is the value of the Stride
property, note that this is 2
bytes more than the raw RGB values you may expect of 54 * 3
= 162
.
This padding ensures that each row (line of pixels) starts on a multiple of 4
.
When I inspect the raw bytes of the file after it has been saved, on my machine all of the bytes match the magic number
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