steno | A collection of stuff I did related to steno | Keyboard library
kandi X-RAY | steno Summary
kandi X-RAY | steno Summary
This repo contains everything I designed and implemented that's related to stenography. You can find the PCB files for my steno keyboard in the pcb/ directory, and the custom steno firmware and the dictionary compiler in the qmk/ and compiler/ directories. Check out the boards and the firmware (dictionary compiler needed).
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QUESTION
Can someone please tell me why the #sidebar
doesn't get sticky with this code? When I test the sticky property on main, #searchbar
and #localnav
it works fine, but not on #sidebar
. I have tested adding padding-bottom
to sidebar, main to test if that should help but it doesn't.
Please see code snippet.
...ANSWER
Answered 2018-Mar-18 at 10:26Well position: sticky
works within its parent element's height
and your sticky
positioned div's parent main
does not have any height because of the inner floated divs, thats why position:sticky
not working...
So try to put a in-flow element just after floated div using :after
pseudo element
QUESTION
I have a tool that analyze some ruby projects having Gemfile and Gemfile.lock files. This tool given in input the path where ruby project is, list all its dependencies.
My problem is that I only need to print production dependencies excluding development and test. Today I find out that my code does not exclude them and I do not know how to modify it for my purpose. How I can remove development and test dependencies from the list?
Here a simplified version of the ruby code I use to list dependencies:
...ANSWER
Answered 2017-Jun-21 at 21:05How about this
QUESTION
On the stenographic keyboard, there are the keys STKPWHRAO*EUFRPBLGTSDZ
. The user presses several keys, then the keys are registered all at once when lifted. It's similar to playing chords on a piano. Example strokes are KAT
, TPHOEUGT
.
I have a regex which tests for valid steno chords. It can be any number of these keys but they must be in that order. My solution is qr/S?T?K?P?W?H?R?A?O?\*?E?U?F?R?P?B?L?G?T?S?D?Z?/
but since this regex gets called hundreds of times, the variable length might be a speed bottleneck. Each step forward in the regex is a bigger and bigger set of possibilities due to all the ?
Is there a faster regex approach to this? I need the regex to fail if keys are out of order.
...ANSWER
Answered 2017-Mar-24 at 22:20the variable length might be a speed bottleneck
You shouldn't work like that
First, write and debug your program
then, if it isn't fast enough for it's purpose, profile your program to find where the bottlenecks are
then optimise the bottlenecks
For goodness sake don't spend ages trying to guess where the bottlenecks are and optimising them before your code is complete, as you will more than likely find that you have guessed wrongly and wasted a lot of time
In any case, the regex engine is written in C and is pretty damn fast. I doubt very much whether the short pattern that you have written will take a significant amount of time to test
Each step forward in the regex is a bigger and bigger set of possibilities due to all the
?
That isn't true either. At each point in the regex there is only one character to test. The next character in the string either matches it or it doesn't. Either is fine, and the regex engine just goes on to the next step in the pattern. The matching process will be pretty much constant regardless of the string to be matched.
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