gprolog | GNU Prolog is a native Prolog compiler | Translation library

 by   didoudiaz C Version: v1.5.0 License: Non-SPDX

kandi X-RAY | gprolog Summary

kandi X-RAY | gprolog Summary

gprolog is a C library typically used in Utilities, Translation applications. gprolog has no bugs, it has no vulnerabilities and it has low support. However gprolog has a Non-SPDX License. You can download it from GitHub.

GNU Prolog
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              gprolog has a low active ecosystem.
              It has 72 star(s) with 4 fork(s). There are 8 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 9 open issues and 21 have been closed. On average issues are closed in 54 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of gprolog is v1.5.0

            kandi-Quality Quality

              gprolog has no bugs reported.

            kandi-Security Security

              gprolog has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              gprolog has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              gprolog releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            gprolog Key Features

            No Key Features are available at this moment for gprolog.

            gprolog Examples and Code Snippets

            No Code Snippets are available at this moment for gprolog.

            Community Discussions

            QUESTION

            Unit testing in GNU Prolog
            Asked 2021-Jan-30 at 01:43

            I'm trying to migrate my SWI Prolog application into the GNU Prolog. Unfortunately I have a problem with unit tests. In SWIPL we can simply use plunit module and write the test cases like the following one:

            ...

            ANSWER

            Answered 2021-Jan-30 at 01:43

            You can use lgtunit. Its main features are summarized here. Most of your tests could be run as-is or easily converted. Using your example:

            Source https://stackoverflow.com/questions/65844487

            QUESTION

            Why does my implementation of Dijkstra's algorithm fail under this undefined case?
            Asked 2021-Jan-17 at 08:26

            I am trying to write an implementation of Dijkstra's Algorithm in Prolog (specifically, GNU Prolog). To begin, I made a fact connection that describes the connected vertices of the graph below.

            It now seems like my implementation works for around half of my test cases, namely these:

            ...

            ANSWER

            Answered 2021-Jan-17 at 08:26

            The main idea of dijkstras algorithm is to create a boundary between visited and unvisited nodes. Everything happens in the boundary. The boundary are simply pairs of nodes and their distances from the start node. In each step the node from the unvistied set with the smallest total distance from the start is transfered to the vistied set. To do this all "connections" from any visited nodes to unvisited nodes are checked: distance to the vistited node + connection value is the total distance. This way you can get the minimal distance from start to goal. Please note that this (mostly deterministic) algorithm works with those two sets rather than a concrete path. However if you want to have a path you have to keep track of the source node for each node in the visited set as well.

            Your code seems to have multiple issues and I found it way easier just to implement my own solution. One of the problems is that the start node appears in the unvistied list. You can use the following code as a reference to debug your code:

            Source https://stackoverflow.com/questions/65745898

            QUESTION

            How do I read a line of input from a user, until an EOF is hit, in GNU Prolog?
            Asked 2020-Dec-22 at 04:11

            I have been reading the GNU Prolog documentation to figure out how to read a line of input until an end_of_file atom is reached. Here is my pseudocode for writing such a goal:

            ...

            ANSWER

            Answered 2020-Dec-22 at 04:11

            You are using peek_char/1 to get the next character, but that predicate does not consume the character from the stream (it just "peeks" the stream). Therefore an infinite recursion undergoes in your code that ends with a global stack overflow.

            You should use get_char/1 to read and consume the character from the stream, and reverse/2 the list of collected chars:

            Source https://stackoverflow.com/questions/65400385

            QUESTION

            Why does my Prolog S-expression tokenizer fail on its base case?
            Asked 2020-Dec-17 at 09:25

            To learn some Prolog (I'm using GNU Prolog) and grok its parsing abilities, I am starting by writing a Lisp (or S-expression, if I'm being exact) tokenizer, which given a set of tokens like ['(', 'f', 'o', 'o', ')'] should produce ['(', 'foo', ')']. It's not working as expected, which is why I'm here! I thought my thought process shined through in my pseudocode:

            ...

            ANSWER

            Answered 2020-Dec-17 at 08:59

            How about this. I think that's what you want to do, but let's use Definite Clause Grammars (which are just horn clauses with :- replaced by --> and two elided arguments holding the input character list and remaining character list. An example DCG rule:

            Source https://stackoverflow.com/questions/65332359

            QUESTION

            Search for path is gprolog
            Asked 2020-Dec-01 at 19:58

            I'm trying to create a function in GProlog that I think is rather simple but I'm having issues writing it.

            The idea is to assume a weighted directed graph is described by means of a predicate edge/3, such that edge(X,Y,C) is true is there is an edge from vertex X to vertex Y of cost C. For instance, to the right is a graph and its description using edge/3: edge(a, c,1). edge(a,d,3). edge(b,d,2). edge(c,e,5). edge(e, c,2). edge(e,f,2). edge(d,f,10).

            The objective is to define a predicate cheaperPath/3, such that cheaperPath(X,Y,N) is true if there is a path from X to Y of total cost less than N. The predicate is supposed to be called with X, Y and N all instantiated, for example to the query cheaperPath(a,f,7) the anwer should be no.

            Here is what I have done for now in Gprolog but the loop seems to be going on and on:

            ...

            ANSWER

            Answered 2020-Dec-01 at 19:58

            You should reduce the bound when you take an edge, so:

            Source https://stackoverflow.com/questions/65097608

            QUESTION

            Is !/0 supposed to cut through (\+)/1 or not?
            Asked 2020-Nov-07 at 22:53

            On the one hand:

            ...

            ANSWER

            Answered 2020-Nov-07 at 22:53

            Just an artifact of the SICStus Prolog top-level. Try e.g.

            Source https://stackoverflow.com/questions/64732339

            QUESTION

            GNU Prolog simple program doesn't work as expected
            Asked 2020-Sep-23 at 16:21

            EDIT : I've just compiled gprolog from sources.

            It works fine. The version 1.4.5 in the Debian repo is bugged.

            It's my first program in GNU Prolog (gprolog) without any success. :-(

            I found these exercises in a Prolog tutorial.

            ...

            ANSWER

            Answered 2020-Sep-23 at 13:38

            It seems that invoked with a file name, gprolog validates it but does not load its content into the interpreter. In order to load the file content you have to use the --consult-file command line option:

            Source https://stackoverflow.com/questions/64028978

            QUESTION

            How can prolog take minutes to check for answers within a bunch of possible combinations only?
            Asked 2020-Jun-15 at 16:24

            The following sample program generates a schedule while matching certain conditions.

            Conditions:

            1. assigns one employee per shift
            2. no employee should work consecutive shifts
            3. do not assign employee for personal holidays

            The program provides valid solutions, but takes about 4 minutes although there should be only 128 possible combinations (combine 2 employees on 7 shifts). The program was executed using gprolog implementation within a single core virtual machine.

            How is this possible? What is happening?

            ...

            ANSWER

            Answered 2020-Jun-15 at 16:24

            takes about 4 minutes although there should be only 128 possible combinations (combine 2 employees on 7 shifts)

            It's true that this should be the search space, but you explore a lot more. Consider the first two answers from your predicate:

            Source https://stackoverflow.com/questions/62384379

            QUESTION

            Making a sublist out of a list of lists
            Asked 2019-Dec-11 at 13:30

            I'm trying to make a sublist out of a list of lists in gprolog. Say I have a list like this:

            ...

            ANSWER

            Answered 2019-Dec-09 at 12:48

            I have attached my approach below. Iterate through the list until it's empty. If 'q' is present in the head then add that to a list. If not present do nothing keep iterating.

            Source https://stackoverflow.com/questions/59242527

            QUESTION

            Is there way I could fix this error ? Undefined symbols for architecture x86_64: (gnu-prolog)
            Asked 2019-Nov-07 at 03:35

            My program runs fine on swi prolog but when i try run it using gnu-prolog. It does not run successfully. Im getting this error which I have no idea how to fix.

            This is my first error

            gprolog [myprojectname]

            ...

            ANSWER

            Answered 2019-Nov-07 at 03:35

            The writeln/1 predicate is not a standard predicate and is not supported in GNU Prolog. Replace it with a combination of the standard predicates write/1 and nl/0.

            Source https://stackoverflow.com/questions/58741123

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            Install gprolog

            You can download it from GitHub.

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