nle | The NetHack Learning Environment | Reinforcement Learning library

Use a for...of to iterate over the array, and then push the value to a new array.

You are looking at a MIME part with Content-Transfer-Encoding: quoted-printable. The proper way to decode that is to traverse the MIME structure and interpret the parts as you go. But there is no need to do that explicitly; Python's email library already does exactly that for you.

Your example code is obviously broken; you can't nest single quotes; though Perl provides the convenience operator q() so you can easily work around this. The formatting has other errors, too. Probably you mean something like

I just figured it out myself:

dup2() creates a duplicate of the connection's file descriptor into STDIN_FILENO, leaving it open only in stdin after close(), thus reading stdin with getch, getchar or any other functions was basically waiting for the client to send something.

Removing both solved my problem: getch() now works properly.

This works as described:

I'm not sure whether the "\n" are literal or a representation of the LF character, but I'll assume the former and you can adjust the formula, if necessary. The solution involves splitting the lines, iterating through the lines and filtering the lines containing '%' and joining the lines again. Use the following formula in the "Edit Cells -> Transform" dialog:

forEach(value.split('\\n'),l,if(l.contains('%'),'',l)).join('\\n')

To break it down:

• value.split('\\n') yields an array of split lines
• forEach(array,l,f) iterates through the array assigning each line to the variable l and applying function f
• if(l.contains('%'),'',l)) returns the empty string if l contains a percent ('%') otherwise the original string
• array.join('\\n') joins your filtered lines back together again

You can use

This Stack Overflow question and its top-voted answer may be helpful. It's an old answer, but most of the resources given there are still useful. In particular, I can see that you're still having trouble with some basic aspects of Haskell syntax, and working through multiple tutorials from that question will definitely help you with this.

Haskell's type system is extremely unforgiving, in that a program must be precisely type correct in order to compile. At the same time, the type system is also extremely powerful and complex. The end result is that simple syntax errors can be totally misinterpreted by the compiler as attempts to use powerful type-level features, and the resulting type errors can be completely baffling. Beginners run up against this all the time, but even experienced Haskell programmers run into type errors that they really don't understand, and everyone has to do a little trial-and-error to figure things out sometimes.

Anyway, your specific issues are:

1. You accidentally used getTrackSale when you meant to use getSale, so you passed a single parameter to a function that expected three parameters. That's what the error message was about.
2. When calling a haskell function with multiple arguments, the correct syntax is f x y z, not f (x y z). The expression f (x y z) is completely misinterpreted by the compiler as an attempt to apply the "function" x to the arguments y and z, and then pass the result as a single parameter to f!

If you fix getTrackSale to read:

You write