corc | Stackless coroutine compiler for C | Android library

by jeremycw C Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(6)Vulnerabilities Install Support

kandi X-RAY | corc Summary

corc is a C library typically used in Mobile, Android applications. corc has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Stackless coroutine compiler for C.

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Quality

Security

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Support

corc has a low active ecosystem.

It has 44 star(s) with 5 fork(s). There are 7 watchers for this library.

It had no major release in the last 6 months.

corc has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of corc is current.

Quality

corc has no bugs reported.

Security

corc has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

corc is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

corc releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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corc Key Features

No Key Features are available at this moment for corc.

corc Examples and Code Snippets

No Code Snippets are available at this moment for corc.

Community Discussions

Trending Discussions on corc

I have this error: Ambiguous use of 'locationManager'

How to add a name column of character vectors to a data frame in R

How to maintain original row names when binding rows from different data frames?

Convert a data frame of numerics to string equivalents based on a reference range

Return a string by reference from tbl_df of numerics in R

Is there a faster way to create a data.frame of weighted scores?

QUESTION

I have this error: Ambiguous use of 'locationManager'

Asked 2019-May-27 at 18:36

I'm trying to make a Geofence in Swift 4, but I have a problem, I have an error when calling locationManager, I do not understand why I get this error

this is the error:

Ambiguous use of locationManager

I tried to correct it by placing self.locationManager.startUpdatingLocation () and other different methods but none worked

Here I declare my variable locationManager:

...

ANSWER

Answered 2019-May-27 at 18:36

If locationManager is an instance property use it directly

Source https://stackoverflow.com/questions/56330168

QUESTION

How to add a name column of character vectors to a data frame in R

Asked 2017-Aug-27 at 06:07

I have a data frame built as such:

...

ANSWER

Answered 2017-Aug-27 at 04:55

We can create the vector with paste and cbind it to the original dataset

Source https://stackoverflow.com/questions/45901803

QUESTION

How to maintain original row names when binding rows from different data frames?

Asked 2017-Aug-26 at 21:47

How can I preserve one of the grouping names when using dply::summarise? Or, is there a better way to preserve one of the group names? I am probably going about this rather inefficiently.

I have a data.frame (df) as such:

...

ANSWER

Answered 2017-Aug-26 at 21:47

Updated Answer

Here's an updated answer, based on the comment thread. We summarise by AU and BU separately and store the results in a list. We then show how to combine the summaries into a single data frame and to output the summary as a table.

Source https://stackoverflow.com/questions/45897691

QUESTION

Convert a data frame of numerics to string equivalents based on a reference range

Asked 2017-Aug-24 at 14:16

I have a data.frame of numeric scores related to groups (y) measured across different factors (x) with resulting scores. Similar to the table below.

...

ANSWER

Answered 2017-Aug-23 at 21:07

cut is a great function for dividing numbers into intervals and giving them explanatory names.

Source https://stackoverflow.com/questions/45848766

QUESTION

Return a string by reference from tbl_df of numerics in R

Asked 2017-Aug-23 at 06:39

I have a tbl_df (tibble) named 'control.scores' that has a column called "Overall", which is some value between 1.00 and 4.00.

...

ANSWER

Answered 2017-Aug-23 at 06:03

We can consider to use case_when from the dplyr. Notice that I changed the range of your classification a little bit because there are gaps in your original classification. For example, 3.505 will have no any associated classes based on your original classification. dt2 is the final output.

Source https://stackoverflow.com/questions/45831570

QUESTION

Is there a faster way to create a data.frame of weighted scores?

Asked 2017-Aug-23 at 02:10

I'm trying to find a better and faster way to put together a table of summary statistics comprised of weighted averages. Using dplyr to summarise and then bind_rows I end up with a table like this. These numbers are simple averages The averages are calculated for each factor for each group.

Dataframe: au.scores

...

ANSWER

Answered 2017-Aug-23 at 02:10

Overall.Group1 is Group1+Group4+Group5, Group2 is Group2+Group4+Group5 and Group3 is Group3+Group4+Group5 factors.

Your description of how overall scores are calculated is different from your formula for group1.overall, which uses Group1 <- Group1+Group2+Group3 instead. In the approach below, I'm going by the description. You can tweak that if necessary:

Source https://stackoverflow.com/questions/45809017

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install corc

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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