p2 | p2 on the potion vm
kandi X-RAY | p2 Summary
kandi X-RAY | p2 Summary
p2 is a she. She is a perl5 and possible perl6/nqp backend, based on why the luck stiff's potion. See README.potion why potion is exciting. Homepage: For most small examples comparable performance to lua and C. For bigger examples optimizable via static types/early binding.
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Trending Discussions on p2
QUESTION
I have a dynamic query that adds WHERE clauses according to the parameters received:
...ANSWER
Answered 2021-Jun-15 at 23:39I found the answer with the following lines of code:
QUESTION
I am trying to reduce lines of code because I realized that I am repeating the same equations every time. I am programming a contour map and putting several sources of intensity into it. Until now I put 3 sources, but in the future I want to put more, and that will increase the lines a lot. So I want to see if it is possible to reduce the lines of "source positions" and "Intensity equations". As you can see the last equation is a logaritmic summation of z1, z2 and z3, is it possible to reduce that, any idea?
...ANSWER
Answered 2021-Jun-15 at 15:45You could iterate over certain parts in a loop.
I tried to keep the same format overall and just rearranged the code to show how you might do it.
QUESTION
I have a data frame with 1 column for participants and one column for my eeg triggers. Example:
ID trigger P1 SB P1 SB P1 resp P1 DH P1 Sc P1 resp P2 SB P2 resp P2 Sc P2 SB"resp" correspond to each time the participant has answered (pressed a button). If he answered after Sc, it is a hit, if he don't, it is a miss; if he answered after something else, it is a false alarm (fa); if he does not answer after something which is not Sc, it is a correct rejection (cr).
I would like to create a new data frame and to have, for each participant the total number of Sc, the number of hit, of miss, of fa and of cr, like the following:
ID Nb_Sc hit miss fa cr P1 100 99 1 1 99 P2 50 45 5 3 47But i don't know at all how I could do that. Does anyone has an idea and can help?
Thanks for reading.
...ANSWER
Answered 2021-Jun-15 at 15:33library(dplyr)
set.seed(100)
df <- data.frame(
ID = sample(c("P1", "P2"), 200, replace = TRUE),
trigger = sample(c("SB", "Sc", "resp", "DH"), 200, replace = TRUE)
)
QUESTION
So basically I am getting two string inputs in the form of coordinates as (x,y) and then I am adding the numbers from the inputted string (which are p1 and p2) to different variables and then adding those variables (which are x1,x2,y1,y2). So is there a way to add the variables together i.e perform arithmetic on the variables, (not concatenate)
...ANSWER
Answered 2021-Jun-15 at 13:14You can do this with std::stoi()
. Add a line to put these string
s into int
variables and do your arithmetic:
int x = stoi(x1);
QUESTION
I would like to standardize a dataframe by the value in one specific column. In other words, I would like to divide all the values in each row by the value in a specific column.
For example:
The dataframe is
Gene P1 P2 P3
A1 6 8 2
A2 12 6 3
A3 8 4 8
I would like to divide all the values in each row by the value in that row for column P3.
Gene P1 P2 P3
A1 6/2 8/2 2/2
A2 12/3 6/3 3/3
A3 8/8 4/8 8/8
The new dataframe would be:
Gene P1 P2 P3
A1 3 4 1
A2 4 2 1
A3 1 .5 1
Thank you for your help.
...ANSWER
Answered 2021-Jun-15 at 01:22Using tidyverse functions:
QUESTION
I use the example from the site, but I want to remove the points so that only the connection of the medians remains.
My code.
...ANSWER
Answered 2021-Jun-14 at 11:31ggstatsplot
won't directly allow you to remove them, but you can use some workarounds:
QUESTION
Hello i have a csv with about 2,5k lines of outlook emails and passwords
The CSV looks like
header:
username, password
content:
test1233@outlook.com,123password1
test1234@outlook.com,123password2
test1235@outlook.com,123password3
test1236@outlook.com,123password4
test1237@outlook.com,123password5
the code allows me to go into the accounts and delete every mail from them, but its taking too long for 2,5k accounts to pass the script so i wanted to make it faster with multithreading.
This is my code:
...ANSWER
Answered 2021-Jun-11 at 19:02This is not necessarily the best way to do it, but the shortest in writitng time. I don't know if you are familiar with python generators, but we will have to use one. the generator will work as a work dispatcher.
QUESTION
I've used Martin Prikryl's code for my Inno Setup project. This is the link to his code:
How to make Stop and Pause/Resume/Play music buttons in Inno Setup
I used it with some tweaks on it but the problem is that the music glitches when I finish it.
For example, if the music is working while installing something and when I finally finish the setup, I still hear the glitched Audio for about 3 seconds! It's very annoying!
I think the problem is that we need to unload Music dll's before the installer finishes, as we do with the skin.
I hope you understood my situation and thanks in advance!
This is my Full code (it's not well-arranged sorry) :
...ANSWER
Answered 2021-Jun-14 at 07:52If you want to stop the music, when the installer is closing, just use the same code you already have in StopButtonClick
from DeinitializeSetup
:
QUESTION
I want to save a Mat mRgba
as a picture with Imgcodecs.imwrite(Environment.getExternalStorageDirectory() + "/final-image.jpg", mRgba);
and in general it saves more that I want to. I want to save image without rectangle Imgproc.rectangle(mRgba, new Point(touchedYD, touchedXL), new Point(touchedYU, touchedXR), Util.WHITE, 2);
that is drawn on screen before saving. How to achieve that?
Here is my code.
Fragment:
...ANSWER
Answered 2021-Jun-12 at 21:36You may create a copy of mRgba
before drawing the rectangle.
Add a new private class member
mRgbNoRect
:
QUESTION
The given problem: Use friend function for getting the private variable and operator overloading for calculating the total number of goals by each side of the team. I'm completely new to C++ and unable to figure out how to fix this error. What I've tried:
...ANSWER
Answered 2021-Jun-12 at 10:41Not passing Player
as a reference in the operator solves the issue:
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