fizzbuzz | FizzBuzz test , with different optimisations | Performance Testing library
kandi X-RAY | fizzbuzz Summary
kandi X-RAY | fizzbuzz Summary
Optimisation of classic FizzBuzz test.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of fizzbuzz
fizzbuzz Key Features
fizzbuzz Examples and Code Snippets
public static void fizzbuzz(int n) {
for (int i = 1; i <= n; i++) {
if (i % 3 == 0 && i % 5 == 0) {
System.out.println("FizzBuzz");
} else if (i % 3 == 0) {
System.out.println("Fizz");
} else if (i % 5 == 0) {
System
public static void main(String[] args) {
int n = 100;
Thread[] threads = {new FizzBuzzThread(true, true, n, "FizzBuzz"),
new FizzBuzzThread(true, false, n, "Fizz"),
new FizzBuzzThread(false, true, n, "Buzz"),
new NumberThre
Community Discussions
Trending Discussions on fizzbuzz
QUESTION
So I have a hackerRank different type of fizzBuzz function that is as follows:
The only constraints:
0 < n < 2 x 10^5.
But for simplicity, I am not using the constraints here so the answer won't be so big. Here it is:
if n is multiple by both 5 and 3 print('FizzBuzz')
if n is multiple by 3(but not 5) print('Fizz')
if n is multiple by 5(but not 3) print('Buzz')
if n is neither print(n)
The prints should be one value per line
So far ok, here is the code I wrote in Python 3
...ANSWER
Answered 2021-Jun-13 at 15:20As you can see this is the same evaluation as your code but with optimized approach, FizzBuzz questions are to test on how to write an efficient algorithm. Just because the code is working it doesn't mean it shouldn't be optimized.
In here you can see I'm checking every interval and appending the string by words. If you use modulo(%) operator, then it uses more cpu clocks, I know it is nothing for current generation computers, but it's good practice with problems like this
QUESTION
I'm new to Combine and I'm trying to understand it by solving the "old" problems
My goal is to make the process cancelable, but even I called the .cancel()
method right after (or with sort delay) the printFizzbuzz()
method, the code still keeping running(around 3 secs) until finishing
I've tried the code below in the new Xcode project, still the same
...ANSWER
Answered 2021-Jun-06 at 21:57The problem is that your publisher is too artificially crude: it is not asynchronous. An array publisher just publishes all its values at once, so you are canceling too late; and you are blocking the main thread. Use something like a timer publisher instead, or use a flatmap with a delay and backpressure.
QUESTION
I have the following code in Elixir:
...ANSWER
Answered 2021-Jun-12 at 14:14One cannot pipe to an anonymouse function. Also, you want to pipe values, one by one, not the whole range, so you need an iterator there.
Use function capture &/1
:
QUESTION
I am somewhat new to Javascript so I'll try my best to explain this properly. I'm using vanilla JS on the fizz buzz loop, but I'm trying to do it slightly differently, I think.
I've put both sets of numbers in 2 separate arrays, and successfully did it with a for
loop by counting up to 20, but I didn't use the arrays to do it. However, I want to use the variables passed as arguments to check if the values are true so the appropriate response can be printed, either fizz, buzz, or fizzbuzz.
My code for the for
loop is:
ANSWER
Answered 2021-Jun-07 at 21:14You can test if the number you're iterating is inside of any of the arrays with the function some. For example,
QUESTION
Docker Compose here. I'm looking at the Docker networking guide and trying to understand how to perform the equivalent of a "CREATE TABLE IF NOT EXISTS
" with a Docker network. Meaning, in SQL, you can usually tell the RDBMS to create a table if it doesn't already exist.
Here, from inside a Docker Compose file, I want to tell Docker to create a network if it doesn't already exist, and then connect my services (containers) to it.
Is this possible to do? Ideally it could be flexible such that I could have several different Docker Compose files (docker-compose-a.yml
, docker-compose-b.yml
and docker-compose-c.yml
), and all of them defined various services (containers), but all of them were configured to create (unless already created previously) and use the same "fizzbuzz
" network.
Any ideas?
...ANSWER
Answered 2021-Jun-03 at 13:54There's no way at the moment to create network if does not exist.
You can read more here.
Update 1
As you said in comments, you can add this to your docker-compose
files (each one) in order to be in the same network.
First of all create a network by this command:
QUESTION
I'm writing a function that takes three optional arguments from the console.
...ANSWER
Answered 2021-May-31 at 15:31Check out the argparse
module:
QUESTION
I am new to javascript and I was just messing around and practicing my codes but array push method isn't working. It's output is just [1], every time I run it. Here is my code:
...ANSWER
Answered 2021-May-30 at 03:19.push() method is working as intended, you are only calling fizzBuzz() once, hence the [1] result.
In order to push an increment of count into output you can use a loop clause
QUESTION
All of you know the trivial fizzbuzz
question during the first junior interviews. In my case, it was more than write a solution. There were more requirements:
- Only two
if\else
statements. StringBuilder
required.- No
Map
,Collection
. - No ternary operator.
- Only Java core (8 or 11).
- You have only 5 minutes (in my case, but for you it doesn't matter).
My solution with three if
statements:
ANSWER
Answered 2021-May-20 at 13:58I'd say your solution with the map was very close, and nobody said "no arrays" :)
QUESTION
Spring Boot here. I currently have the following REST controller:
...ANSWER
Answered 2021-May-12 at 16:03You need another context for testing. I'm suggesting you to have a separate Test config:
QUESTION
Here is my code:
...ANSWER
Answered 2021-May-10 at 10:31Your code doesn't increment count
, so it writes to stdout a lot of copies of the same line.
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