fizzbuzz | FizzBuzz test , with different optimisations | Performance Testing library

 by   qrdl C Version: Current License: MIT

kandi X-RAY | fizzbuzz Summary

kandi X-RAY | fizzbuzz Summary

fizzbuzz is a C library typically used in Testing, Performance Testing applications. fizzbuzz has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Optimisation of classic FizzBuzz test.
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              fizzbuzz has a low active ecosystem.
              It has 78 star(s) with 4 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 2 have been closed. On average issues are closed in 2 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of fizzbuzz is current.

            kandi-Quality Quality

              fizzbuzz has no bugs reported.

            kandi-Security Security

              fizzbuzz has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              fizzbuzz is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              fizzbuzz releases are not available. You will need to build from source code and install.

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            fizzbuzz Key Features

            No Key Features are available at this moment for fizzbuzz.

            fizzbuzz Examples and Code Snippets

            Print Fizzbuzz .
            javadot img1Lines of Code : 13dot img1no licencesLicense : No License
            copy iconCopy
            public static void fizzbuzz(int n) {
            		for (int i = 1; i <= n; i++) {
            			if (i % 3 == 0 && i % 5 == 0) {
            				System.out.println("FizzBuzz");
            			} else if (i % 3 == 0) {
            				System.out.println("Fizz");
            			} else if (i % 5 == 0) {
            				System  
            Creates a FizzBuzz thread .
            javadot img2Lines of Code : 10dot img2no licencesLicense : No License
            copy iconCopy
            public static void main(String[] args) {
            		int n = 100;
            		Thread[] threads = {new FizzBuzzThread(true, true, n, "FizzBuzz"), 
            							new FizzBuzzThread(true, false, n, "Fizz"), 
            							new FizzBuzzThread(false, true, n, "Buzz"),
            							new NumberThre  

            Community Discussions

            QUESTION

            Fizzbuzz a little different from normal. strange error
            Asked 2021-Jun-13 at 15:31

            So I have a hackerRank different type of fizzBuzz function that is as follows:

            The only constraints:

            0 < n < 2 x 10^5.

            But for simplicity, I am not using the constraints here so the answer won't be so big. Here it is:

            if n is multiple by both 5 and 3 print('FizzBuzz')

            if n is multiple by 3(but not 5) print('Fizz')

            if n is multiple by 5(but not 3) print('Buzz')

            if n is neither print(n)

            The prints should be one value per line

            So far ok, here is the code I wrote in Python 3

            ...

            ANSWER

            Answered 2021-Jun-13 at 15:20

            As you can see this is the same evaluation as your code but with optimized approach, FizzBuzz questions are to test on how to write an efficient algorithm. Just because the code is working it doesn't mean it shouldn't be optimized.

            In here you can see I'm checking every interval and appending the string by words. If you use modulo(%) operator, then it uses more cpu clocks, I know it is nothing for current generation computers, but it's good practice with problems like this

            Source https://stackoverflow.com/questions/67959672

            QUESTION

            Swift Combine, how to cancel the execution
            Asked 2021-Jun-13 at 02:31

            I'm new to Combine and I'm trying to understand it by solving the "old" problems

            My goal is to make the process cancelable, but even I called the .cancel() method right after (or with sort delay) the printFizzbuzz() method, the code still keeping running(around 3 secs) until finishing

            I've tried the code below in the new Xcode project, still the same

            ...

            ANSWER

            Answered 2021-Jun-06 at 21:57

            The problem is that your publisher is too artificially crude: it is not asynchronous. An array publisher just publishes all its values at once, so you are canceling too late; and you are blocking the main thread. Use something like a timer publisher instead, or use a flatmap with a delay and backpressure.

            Source https://stackoverflow.com/questions/67863183

            QUESTION

            Iterate over range in Elixir to call a function with those numbers
            Asked 2021-Jun-12 at 14:14

            I have the following code in Elixir:

            ...

            ANSWER

            Answered 2021-Jun-12 at 14:14

            One cannot pipe to an anonymouse function. Also, you want to pipe values, one by one, not the whole range, so you need an iterator there.

            Use function capture &/1:

            Source https://stackoverflow.com/questions/67945589

            QUESTION

            How to loop through 2 arrays as arguments with for, for of, or forEach
            Asked 2021-Jun-12 at 01:39

            I am somewhat new to Javascript so I'll try my best to explain this properly. I'm using vanilla JS on the fizz buzz loop, but I'm trying to do it slightly differently, I think.

            I've put both sets of numbers in 2 separate arrays, and successfully did it with a for loop by counting up to 20, but I didn't use the arrays to do it. However, I want to use the variables passed as arguments to check if the values are true so the appropriate response can be printed, either fizz, buzz, or fizzbuzz.

            My code for the for loop is:

            ...

            ANSWER

            Answered 2021-Jun-07 at 21:14

            You can test if the number you're iterating is inside of any of the arrays with the function some. For example,

            Source https://stackoverflow.com/questions/67878441

            QUESTION

            Docker Compose networks: create if not exists across multiple files and service definitions?
            Asked 2021-Jun-03 at 13:54

            Docker Compose here. I'm looking at the Docker networking guide and trying to understand how to perform the equivalent of a "CREATE TABLE IF NOT EXISTS" with a Docker network. Meaning, in SQL, you can usually tell the RDBMS to create a table if it doesn't already exist.

            Here, from inside a Docker Compose file, I want to tell Docker to create a network if it doesn't already exist, and then connect my services (containers) to it.

            Is this possible to do? Ideally it could be flexible such that I could have several different Docker Compose files (docker-compose-a.yml, docker-compose-b.yml and docker-compose-c.yml), and all of them defined various services (containers), but all of them were configured to create (unless already created previously) and use the same "fizzbuzz" network.

            Any ideas?

            ...

            ANSWER

            Answered 2021-Jun-03 at 13:54

            There's no way at the moment to create network if does not exist.

            You can read more here.

            Update 1

            As you said in comments, you can add this to your docker-compose files (each one) in order to be in the same network.

            First of all create a network by this command:

            Source https://stackoverflow.com/questions/67810437

            QUESTION

            Passing optional console arguments to function in python
            Asked 2021-May-31 at 15:31

            I'm writing a function that takes three optional arguments from the console.

            ...

            ANSWER

            Answered 2021-May-31 at 15:31

            QUESTION

            The push method is not working in JavaScript
            Asked 2021-May-30 at 03:23

            I am new to javascript and I was just messing around and practicing my codes but array push method isn't working. It's output is just [1], every time I run it. Here is my code:

            ...

            ANSWER

            Answered 2021-May-30 at 03:19

            .push() method is working as intended, you are only calling fizzBuzz() once, hence the [1] result.

            In order to push an increment of count into output you can use a loop clause

            Source https://stackoverflow.com/questions/67757353

            QUESTION

            FizzBuzz using limited number of conditions and StringBuilder
            Asked 2021-May-20 at 19:45

            All of you know the trivial fizzbuzz question during the first junior interviews. In my case, it was more than write a solution. There were more requirements:

            1. Only two if\else statements.
            2. StringBuilder required.
            3. No Map, Collection.
            4. No ternary operator.
            5. Only Java core (8 or 11).
            6. You have only 5 minutes (in my case, but for you it doesn't matter).

            My solution with three if statements:

            ...

            ANSWER

            Answered 2021-May-20 at 13:58

            I'd say your solution with the map was very close, and nobody said "no arrays" :)

            Source https://stackoverflow.com/questions/67619938

            QUESTION

            Spring Boot controller test loading entire application context
            Asked 2021-May-12 at 16:03

            Spring Boot here. I currently have the following REST controller:

            ...

            ANSWER

            Answered 2021-May-12 at 16:03

            You need another context for testing. I'm suggesting you to have a separate Test config:

            Source https://stackoverflow.com/questions/67504825

            QUESTION

            OSError: [Errno 27] File too large idk why
            Asked 2021-May-10 at 10:49

            Here is my code:

            ...

            ANSWER

            Answered 2021-May-10 at 10:31

            Your code doesn't increment count, so it writes to stdout a lot of copies of the same line.

            Source https://stackoverflow.com/questions/67468692

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install fizzbuzz

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/qrdl/fizzbuzz.git

          • CLI

            gh repo clone qrdl/fizzbuzz

          • sshUrl

            git@github.com:qrdl/fizzbuzz.git

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