bitfield | Python fast integer set implementation | Machine Learning library
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kandi X-RAY | bitfield Summary
Python fast integer set implementation
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Trending Discussions on bitfield
QUESTION
Is it safe to create a reference const to a bitfield value? Have a look in the following example
...ANSWER
Answered 2021-Jun-15 at 10:17Is it safe to create a reference const to a bitfield value?
Yes, it's like the same as if you would write for example:
QUESTION
Here is an example from a ST CMSIS header:
...ANSWER
Answered 2021-Jun-10 at 09:04There's no apparent reason why. I very much doubt these libs are meant to be shared with 8- or 16 bitters, which would be the only sensible explanation.
A Cortex M will be 32 bit with 32 bit int
and 32 bit long
. And most importantly 32 bit hardware peripheral registers. So even if long
was 64 bit it would be senseless to shift a mask outside the register bounds.
The U
suffix is enough to prevent undefined behavior left shifts on a signed operand. Other sloppy libs use the bugged 1 << n
style, so maybe 1UL
was a quick fix to correct that bug - where 1U
would have worked just as fine.
QUESTION
I am trying to use static_assert for registers for a FPGA and defined the following unions of struct with bitfields and all variable. But whenever I try to compile static_assert won't compile and I get an error saying the variable doesn't name a type. If I try to forward declare, it doesn't solve the problem. I'm not sure what the right pattern is to get the static_assert to work. Any ideas of the correct way to write the following code?
so.h:
...ANSWER
Answered 2021-Apr-01 at 20:49Any ideas of the correct way to write the following code?
There is no correct way. It's not possible to use static_assert
to check if bitfields are in specific places.
You are using C++. Do not use an union. Write a normal class with accessors that access specific bits with masks - such way is clear, portable and guaranteed to work. Alternatively use a std::bitset
.
QUESTION
I have two functions, both are similar to this:
...ANSWER
Answered 2021-Jun-01 at 18:57I question the following assumption:
This didn't work. It is clear that the compiler is optimising-out much of the code related to z completely! The code then fails to function properly (running far too fast), and the size of the compiled binary drops to about 50% or so.
Looking at https://gcc.godbolt.org/z/sKdz3h8oP, it seems like the loops are actually being performed, however, for whatever reason each z++
, when using a global volatile z
goes from:
QUESTION
I have separated the code into files (*.c and *.h) and included them. I have guard headers and all the separated files were reported to being build:
...ANSWER
Answered 2021-May-30 at 07:57Sketch.cpp is compiled as as C++, including test.h. In order to support function overloading, class membership etc, C++ uses name mangling to encode these C++ features in the symbol name. As such the symbol name for some_test
in Sketch.cpp is not the same as that in test.c which is compiled as C and no name mabgling is applied..
The solution is to prevent name mangling for this symbol when the header is C++ compiled by specifying that the symbol has C linkage:
QUESTION
I am Trying to make a discord bot that automatically makes a mute role on a command without the ability to send messages/add reactions
Any ideas on how to fix this? Thanks
...ANSWER
Answered 2021-May-15 at 04:27RoleData.permissions
is a PermissionResolvable
or an array of PermissionResolvable
and not an object .
If you don't want to grant any permissions to the newly created role, you can do
QUESTION
So Im making a ticket command and when you say .new it will open a channel and store message.author
so it can dm you a transcript later on when you close it. When I log Console.log(message.author) and the stored person in the db, the message.author has User before the brackets and in the db it does not. Also the db has more lines while message.author has less:
ANSWER
Answered 2021-May-12 at 13:13The reason they have different amount of lines is because they are two different things. message.author
is a User
, but what's stored in the db is a GuildMember
. What's the difference?
The reason that message.author
has User
in front of it is that it's a class. What's in the db was originally a class, and would've been logged with GuildMember
in front of it, however you unfortunately cannot keep classes in quick.db
. Nor should you want to, as it would take up an insane amount of storage. Methods such as #send
are only available on the GuildMember
class (as opposed to the GuildMember
class turned into an object by quick.db), so you can't access it from the db.
Instead, store the user ID in the db, as it's a unique identifier and you can get the user from it without storing huge objects in a db. You can use client.users.fetch(id)
to get the user.
QUESTION
I want my bot to post a simple welcome message in a 'welcome' text channel for every new member.
I've read a lot of posts here and there but still having trouble with making it work as intended
Here is the code:
...ANSWER
Answered 2021-May-06 at 23:44Could you let us know what is being logged to the console from the console.log(member)
?
My best bet would be that the WELCOME_CHANNEL_ID is wrong and thus returning a bogus channel.
If that is not the case, then maybe the bot is not caching the channels, so use this:
QUESTION
I have a volatile struct/bitfield for a memory mapped register on an ARM processor. The particular peripheral must be accessed by words.
...ANSWER
Answered 2021-May-04 at 15:08I found that the following works to force word-wise reads and writes.
Structure:
QUESTION
I have a compile command:
...ANSWER
Answered 2021-Apr-27 at 18:50You can use -o /dev/null
to discard the output altogether, or you could send it to a temporary file which you then delete. If you're concerned with compile times, you can add -E
in order to only run the preprocessor, which is the minimum in order for -H
to work. That works because if you tell gcc to stop after preprocessing (-H
), it doesn't matter if you also tell it to stop after creating an object file (-c
). (That's an exception to the general rule that gcc uses the last of a set of conflicting options, which is designed to let you override options by adding to the end of a command-line.)
However, I can't help thinking that this is not really the best solution to your problem. It seems like you've hand-crafted a compiler invocation with a number of options, and then put it somewhere where it's difficult to modify. A better solution would be to use a makefile and set the value of the various standard makefile variables -- such as CFLAGS
, CPPFLAGS
, LDFLAGS
, LDLIBS
-- which are documented in the Gnu make manual. In simple cases, your Makefile
might consist only of lines which set these variables, since Gnu make has built-in rules for common targets.
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