bitset | Bitset implementation for Ruby | Data Migration library

by tyler C Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | bitset Summary

bitset is a C library typically used in Migration, Data Migration applications. bitset has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A fast Bitset implementation for Ruby. Available as the bitset gem.

Support

Quality

Security

License

Reuse

Support

bitset has a low active ecosystem.

It has 48 star(s) with 14 fork(s). There are 6 watchers for this library.

It had no major release in the last 6 months.

There are 4 open issues and 2 have been closed. On average issues are closed in 1579 days. There are 2 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of bitset is current.

Quality

bitset has 0 bugs and 0 code smells.

Security

bitset has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

bitset code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

bitset is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

bitset releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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bitset Key Features

No Key Features are available at this moment for bitset.

bitset Examples and Code Snippets

No Code Snippets are available at this moment for bitset.

Community Discussions

Trending Discussions on bitset

C++ ValueError bitset::_M_copy_from_ptr when string and bitset are correct size

Handling Long data with BitSet in Java

How to split bitset of any size into list of 64 bits bitsets?

Initializing very large C++ std::bitset at compile time

Class to calculate performance of a function

std::bitset constexpr >64bit value

Adding a letterhead to an RMarkdown PDF

Why is bitset throwing out_of_range error?

Declaring an array of std::bitset using std::string

Reverse order of boost::dynamic_bitset

QUESTION

C++ ValueError bitset::_M_copy_from_ptr when string and bitset are correct size

Asked 2021-Jun-03 at 23:38

I have a string which should represent a 32 bit integer, so i'm creating a bitset to print the bits:

...

ANSWER

Answered 2021-Jun-03 at 23:38

Constructor of std::bitset with string argument expects the string to contain only 0s and 1s. Probably your string contains values like a instead of 1100001. So if you want the 32 bits of 4 bytes of your input string to be put into a bitset, you have to convert the string to a sequence of 32 ones and zeros first.

Source https://stackoverflow.com/questions/67826257

QUESTION

Handling Long data with BitSet in Java

Asked 2021-May-13 at 15:20

I have a large data set with range 0 to Long.MAX_VALUE,
and would like to search for any duplication using BitSet.

While Java BitSet doesn't allow long for its functions.
Is it possible to achieve with BitSet?

...

ANSWER

Answered 2021-May-13 at 15:20

BitSet could be used by seeing which bits were previously set. That would then constitute a duplicate value. However, you can't set a bit position greater than Integer.MAX_VALUE (and it would be infeasible to handle such a large range for longs). So it would not work for the range you suggested. And I presume you would still want to record the duplicates.

I would use a Map to do a frequency count. Then you can just determine the exact count of each value provided. And locating the next Key of a map is comparable to calculating which internal long value holds the desired bit. So I don't believe performance is a factor here.

If you simply want to eliminate duplicates, then just put them in a Set

Based on your comment, check out this simple test for holding one large value in a BitSet.

Source https://stackoverflow.com/questions/67519974

QUESTION

How to split bitset of any size into list of 64 bits bitsets?

Asked 2021-May-04 at 20:59

I have a bitset of any size and I would like to know the fastest way to get a list of 64 bits bitsets from my original bitset ?

For example, from bitset<10000> b('010001110 ...'), I would like to get a list of 64 bits bitsets containing the 1st 64th bits, then the next 64th bits from my original bitset, and so on.

...

ANSWER

Answered 2021-May-04 at 20:59

Sadly, there isn't any functionality to efficiently do this operation straight from the STL. You'd have to go bit by bit or you can shift and mask, as explained in this answer.

However, giving credit to this

You can use boost::dynamic_bitset, which can be converted to a range of "blocks" using boost::to_block_range.

Source https://stackoverflow.com/questions/67391891

QUESTION

Initializing very large C++ std::bitset at compile time

Asked 2021-Apr-30 at 09:43

I want to store a static constant bitset of 2¹⁶ bits, with a specific sequence of 1s and 0s that never changes.

I thought of using an initializer string as proposed by this post :

...

ANSWER

Answered 2021-Apr-28 at 16:58

You didn't really split the literal. It gets concatenated for compilation anyways. You are getting limited by the compiler. I don't think there's a way to increase this limit in MSVC.

You can split it into two literals, initialize two bitsets, shift 1st part and OR with the other.

Something like:

Source https://stackoverflow.com/questions/67298395

QUESTION

Class to calculate performance of a function

Asked 2021-Apr-18 at 23:41

I'm writing a class as follows:

...

ANSWER

Answered 2021-Apr-18 at 23:41

NOW you have made the problem clear! By writing this:

Source https://stackoverflow.com/questions/67153959

QUESTION

std::bitset constexpr >64bit value

Asked 2021-Apr-12 at 12:46

I want to have a bitset constexpr variable in my program. bitset can have unsigned long long value as a constructor which is 64bit value, I need 100 bit value. As per this Q&A, we can use constructor that takes a string as an argument and initialize it that way, but it won't be constexpr value. Is there any possible way?

...

ANSWER

Answered 2021-Apr-12 at 12:36

Unfortunately, constexpr std::bitset's constructors are limited to

default one,
and the one taking unsigned long long.

In addition, its mutators (set, operator[], ...) are not constexpr neither, so you cannot create a constexpr "factory".

You have to create your own bitset (or use one from another library).

Source https://stackoverflow.com/questions/67058057

QUESTION

Adding a letterhead to an RMarkdown PDF

Asked 2021-Apr-10 at 18:42

I'm trying to replicate a report using RMarkdown/LaTeX. Is it possible to add a letterhead to the top of a page in a similar way to the image I've attached? Hoping to find a solution where I can have a letterhead with a logo in it (and where I can easily customise the text and color of the letterhead too).

TIA

I'm using the standard article document class. Here is my YAML in RMarkdown

...

ANSWER

Answered 2021-Apr-08 at 08:56

To give you something to start with, you can use fancyhdr and tikz to design your own header:

Source https://stackoverflow.com/questions/66877489

QUESTION

Why is bitset throwing out_of_range error?

Asked 2021-Apr-10 at 15:22

I am implementing a bloom filter with help of bitsets in c++ for finding out malicious URLs. I have a bitset of 100 bits and a simple hash function. But still I get this error.

...

ANSWER

Answered 2021-Apr-10 at 15:22

After reading carefully I thought the reason could be signed characters. If signed characters are involved,

Source https://stackoverflow.com/questions/67021846

QUESTION

Declaring an array of std::bitset using std::string

Asked 2021-Apr-06 at 01:12

Im currently trying to declare an array of 17 std::bitsets, each 32 bits long. I'm doing it like this:

...

ANSWER

Answered 2021-Apr-06 at 01:12

You need to call the constructor of std::bitset like:

Source https://stackoverflow.com/questions/66959037

QUESTION

Reverse order of boost::dynamic_bitset

Asked 2021-Mar-30 at 22:20

Is there a clean way to return the reverse ordering of a boost::dynamic_bitset object?

For example: 01001100 becomes 00110010. The simplest solution I can think of is to convert the bitset to a string, reverse the string and convert it back to a bitset, but this seems a rather slow method that nullifies the speed of bitstring operations.

Thank you in advance!

...

ANSWER

Answered 2021-Mar-30 at 13:41

boost::dynamic_bitset doesn't have iterators, so a long range of comfy STL solutions like, off the top of my head, std::reverse or std::swap or their boost counterparts are not available, I reckon that a good way would be to make your own trivial reverse method:

Source https://stackoverflow.com/questions/66868386

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install bitset

Usually you want to do this:.

Support

The best way to contribute is to fork the project on GitHub, make your changes, and send a pull request. This is always much appreciated. If you want to mess around with the version numbers, gemspec, or anything like that feel free… But do it in separate commits so I can easily ignore them.

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