kalman_filter | Kalman Filter program , which contains a C program
kandi X-RAY | kalman_filter Summary
kandi X-RAY | kalman_filter Summary
This is a Kalman Filter program, which contains a C program implementation of scalar and two-dimensional vector state quantities
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QUESTION
I was taught that giving concrete names to function parameters improves readability however what should I do if the function is an implementation of some mathematical formula where variable names are single letters by convention?
Is what I have done in the example a correct approach?
...ANSWER
Answered 2020-Jul-15 at 18:38There is nothing "wrong" with what you've done.
This is actually a good use of references: your function parameter names are descriptive and self-documenting (presumably), but then you also clearly map these to existing terminology from another domain. That makes your expression easy to read (presumably), and shouldn't cost you anything in terms of performance or maintainability.
It's also very similar to how you'd write the algorithm out in "real life". You start by listing the one-character variables and explaining what they are; then you use them in a formula. So, if your intention is to stick to the original algorithmic form, this is a great way to put it in your code.
And, yes, it could be described as giving a function parameter a new name. That's generally what references do: introduce a new name for a pre-existing thing.
Do note, however, that how acceptable this pattern is will be completely subjective, and if you're employing it in many places in your project, you may raise a few eyebrows.
Also, if these single-letter names are completely conventional, and your target audience are all going to be domain experts forevermore, you may find that the original short names, despite being unclear in the programming sense, are actually easier for your readers to quickly understand at the callsite and in your interface documentation, than longer names that you've made up yourself.
QUESTION
I've installed python 3.6 alongside the default python 3.8 on my ubuntu 20.04 macbook pro 3,1 with
...ANSWER
Answered 2020-Jun-16 at 07:54I would recommend to use conda for that. You will avoid worrying about environment setup. When you activate a certain environment with conda activate
(please see below) all relevant environment paths are directed toward the directory of conda environment.
QUESTION
`Hello, I have installed OpenCV on the Raspberry a couple of times. However, since everything is constantly evolving (OS, libraries, etc...). This time I am getting the following error:
...ANSWER
Answered 2019-Apr-09 at 22:47I have also been running into this error and was able to solve it using the following steps:
navigate to your
OpenCV
directory (runningcd ..
from yourbuild
directory).run the following command:
QUESTION
After fitting a local level model using UnobservedComponents
from statsmodels
, we are trying to find ways to simulate new time series with the results. Something like:
ANSWER
Answered 2018-Aug-28 at 10:06@Josef is correct and you did the right thing with:
QUESTION
I've been working on a program to access an iBeacon data over bluetooth on my Pi 3 running ubuntu mate 16.04 with out the use of sudo
so it can be called from another script. My code works fine when I initialise the class in the if__name__=="__main__":
section?? (not sure of the exact name)
Problem
when I created the ibeacon class
to allow the program to be called from another script using a single line I cannot seem to access the device even though the two setups are identical as far as I can see.
Here is the full code, if you want to run it you will need pctrl
and bluepy
to install them use sudo apt-get install python-prctl
and sudo pip install bluepy
and lastly change the permission of bluesy-helper executable using sudo chmod 4755 bluepy-helper
to remove the need for sudo to access the bluetooth module. I also added pi ALL= NOPASSWD: /home/pi/python/ibeacon.py
to the last line of visudo
but not sure if that is necessary.
when mode = 0
it will not work but, using mode = 1
will, I cannot nut it out, please help!
ANSWER
Answered 2018-Feb-12 at 10:12The ScanDelegate.update
method is trying to access a global variable called scanner
. This doesn't exist when mode is 0.
The reason you don't see this is because you wrap that method in a blank except, which catches all errors including the NameError that would be raised here. That's why you must never, ever do that; you should only catch the specific exceptions you are expecting to be able to deal with.
QUESTION
I am setting up Rodeo
with a few imports for the first time as newbie to python
:
ANSWER
Answered 2017-Aug-07 at 19:41You may have some incompatible or outdated versions of the dependencies.
Try updating the dependencies and see if that helps:
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