ar_model | Auto Regression Model implemention C | Testing library
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Auto Regression Model implemention by C and verified by matlab
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QUESTION
I am working on a project where I need to take groups of data and predict the next value for that group using a time series model. In my data, I have a grouping variable and a numeric variable.
Here is an example of my data:
...ANSWER
Answered 2021-Jun-13 at 19:46You can groupby
first and then iterate. We can store the results in a dict
and after the loop convert it to a DataFrame:
QUESTION
I am very new to time series modeling and statsmodels and trying to understand the AR model in statsmodels. Suppose I have a data record y
of 1000 samples, and I fit an AR (1) model on y
. Then I generate the in-sample prediction from this model as y_pred
. I do this as
ANSWER
Answered 2021-Apr-26 at 00:35Per Wikipedia:
The autoregressive model specifies that the output variable depends linearly on its own previous values and on a stochastic term (an imperfectly predictable term).
In your model example, you have one predictor - lagged value of y
. In this simple case, the .predict()
method multiplies each lagged value by the value of the estimated linear slope parameter for that predictor and adds the estimated value of the intercept of that line. So y_pred[10]
will be equal to the product of the fitted slope parameter and y[9]
, with the value of the intercept estimate added.
Here is an example:
QUESTION
Using statsmodels 0.12.0 I am attempting to determine the optimal lag for a statsmodels.tsa.ar_models.AutoReg
model. I am using US population data with monthly timesteps and passing in a maximum lag of 12 to the statsmodels.tsa.ar_models.ar_select_order
object to evaluate.
ANSWER
Answered 2020-Oct-30 at 23:39The code above returns a numpy array of [ 1 2 3 4 5 6 7 8 9 10 11 12], which I am interpreting as "The optimal lag p is 12" as per this StackOverflow question: stackoverflow.
Yes, that's right. The reason it returns an array instead of just 12
is that it can also search for models that do not include all of the lags, if you set glob=True
. For example [ 1 2 3 12]
might be a common result for a monthly model that has some annual seasonal pattern.
However, evaluating on some metrics (RMSE) I find that my AutoReg fitted models with maxlag=12 are performing worse than lower order models. By trial and error I found that the optimal lag is 8. So I am having difficulty interpreting the resulting numpy array, I have been reading the resources on statsmodels.com/ar_select_order and statsmodels.com/autoregressions but they have not made it clearer.
This function is returning the model that is judged optimal using information criteria. In particular, the default is BIC or Bayesian information criterion. If you use other criteria, such as minimizing the out-of-sample RSME, then it is definitely possible to find that a different model is judged to be optimal.
QUESTION
I realize that this question has been asked before but the solutions are not relevant for the new statsmodel
version (0.12).
I have this dataset in pandas
, the name of the dataframe is train
:
ANSWER
Answered 2020-Sep-20 at 11:22No setting start=len(train)
is correct here. Note in this context that the indexing in Python starts at 0. Consequently, the last index available in your pandas series will be len(train)-1
.
An easy way to validate this is by comparing the forecast from .predict()
with the forecast computed by hand. Because I do not have access to your data, I will illustrate it with the sunspots example from the documentation. In there we estimate the following autoregressive model
QUESTION
I am comparing the results from arima_model and ar_model. Here is what I can't understand:
- Why are the resulting coefficients different? Is it because of the estimation method? (Different settings of the method property of fit() don't give identical results)
- After getting the coefficients and backtesting the fitted results I match those of the AR(1) but not of ARIMA(1). Why?
- What is ARIMA really doing in this simplest setting, isnt it supposed to be able to reproduce AR?
ANSWER
Answered 2020-Aug-13 at 07:29
- Why are the resulting coefficients different? Is it because of the estimation method? (Different settings of the method property of fit() don't give identical results)
AutoReg
estimates parameters using OLS which is conditional (on the first observation) maximum likelihood. ARIMA
implements full maximum likelihood and so uses the available information in the first observation when estimating parameters. In very large samples, the coefficients should be very close, and they are equal in their asymptotic limit. IN practice, they will always differ, although the difference should usually be minor.
- After getting the coefficients and backtesting the fitted results I match those of the AR(1) but not of ARIMA(1). Why?
The two models use different representations. AutoReg(1)
's model is Y(t) = a + b Y(t-1) + eps(t)
. ARIMA(1,0,0)
is specified as (Y(t) - c) = b * (Y(t-1) - c) + eps(t)
. If |b|<1
, then in the large sample limit c = a / (1-b)
, although in finite samples this identity will not hold exactly.
- What is ARIMA really doing in this simplest setting, isnt it supposed to be able to reproduce AR?
No. ARIMA
uses the statsmodels Statespace framework which can estimate a wide range of models using Gaussian MLE.
ARIMA
is essentially a special case of SARIMAX
and this notebook provides a good introduction.
QUESTION
In statsmodels v0.10.1
there was no need to choose the number of lags in Autoregressive AR(p) model. If you chose not to specify the number of lags, the model would have chosen the best one for you which was ideal for running the model automatically. In the new version 0.11.1
this model is now called AutoReg, and it seems that the lags are now mandatory. Is there a way to make this model in the new version choose the best number of lags for you?
ANSWER
Answered 2020-Aug-10 at 09:24It is now a standalone function, statsmodels.tsa.ar_model.ar_select_order
QUESTION
I ran this line of code and got the error mentioned in title. Can someone tell me what is happening?
...ANSWER
Answered 2020-Jun-08 at 20:03Your request might return 404. If that's the case, you can't decode the error pages. Therefore the following code might be a better choice:
QUESTION
i want to write a program in python that iterate over each row of a data-matrix in a .csv file and then pass each row as an input to time-series-analysis model and the output(which is going to be a single value) of each row analysed over model will be stored in a form of coloumn. till now i had tried iterating over rows ,passing it through model and printing each output:
...ANSWER
Answered 2020-Mar-13 at 10:27Use that instead:
QUESTION
I am interested to get the values of the AR(p) part from any ARIMA model in R.
For example, suppose I estimate the following ARIMA model
I am interested to get these values defined as:
What I do is this:
...ANSWER
Answered 2020-Feb-12 at 19:13I will attempt an answer here. Unfortunately, writing formulas in SO is really cumbersome. So, firstly, I think you need to make a distinction between the "epsilon" of your DGP (data generation process), also called shocks or errors (which are unobservable) and the model residuals. Shocks are unobservable because you don't know the true values of the model parameters (in this case the AR and MA parameters) - you can only estimate them. So there is a difference (in a simple AR(1) model without a constant for ease of writing using a "hat" notation for estimates) between y_t - phi_1*y_{t-1} and y_t - \hat{phi_1}*y_{t-1} - the former being the "shock" and the latter being the "residual". Typically you would also have as notation \hat{y_t} = \hat{phi_1}*y_{t-1} and so residual defined as e_t = y_t - \hat{y_t}.
Now so, given that, I think what you would like to get is y_t - e_t - \hat{phi}*e_{t-1}, \hat{phi} being the estimated MA1 parameter. The following is an example where I have explicitly fitted an ARMA(2,1) without a constant to the LakeHuron
time series. I have looked at the model residuals using residuals
(resid
in df
) and also calculated by hand (resid2
in df
) - they differ a bit due to approximating initial conditions that the residuals
method makes which I didn't really dig into. You will see that the values get closer and closer as t
increases and the influence of the initial conditions diminishes (this is due to the fact that we have a stationary ARMA model). In the same way I have calculated the "AR_fit" as I call it once as ar_1 * y_{t-1} + ar_2 * y_{t-2} (ar_fit1
in df
) and a second time as y_t - e_t - ma_1 * e_{t-1} (ar_fit2
in df
). Again, you will see that the values converge as t
increases (due to the same initial conditions used to calculate the residuals using the residuals
function).
QUESTION
I have a working C++ library and I'm trying to expose a function to R through Rcpp, I have the following directory setup
...ANSWER
Answered 2018-Dec-06 at 12:46In the list of object files that are linked there is one file missing: rcpp_functions.o
. You could add this to OBJECTS
in the Makevars
file:
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