DeadLock | Unlock files and folders | File Utils library
kandi X-RAY | DeadLock Summary
kandi X-RAY | DeadLock Summary
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of DeadLock
DeadLock Key Features
DeadLock Examples and Code Snippets
public static void main(String[] args) {
DeadlockExample deadlock = new DeadlockExample();
new Thread(deadlock::operation1, "T1").start();
new Thread(deadlock::operation2, "T2").start();
}
Community Discussions
Trending Discussions on DeadLock
QUESTION
I'm trying to use a separate process to stream data by concurrent futures. However, on the otherside, sometimes the other party stops the datafeed. But as long as I restart this threadable
then it would work again. So I design something like this, to be able to keep streaming data without intervention.
ANSWER
Answered 2022-Apr-01 at 13:13Your code seems to suggest that it is okay to have two instances of threadable
running concurrently, at least for some overlap period and that you unconditionally want to run a a new instance of threadable
after 3600 seconds has expired. That's all I can go on and based on that my only suggestion is that you might consider switching to using the multiprocessing.pool.Pool
class as the multiprocessing pool, which has the advantage of (1) it is a different class than what you have been using as for no other reason is likely to produce a different result and (2) unlike the ProcessPoolExecutor.shutdown
method, the Pool.terminate
method will actually terminate running jobs immediately (the ProcessPoolExecutor.shutdown
method will wait for jobs that have already started, i.e. pending futures, to complete even if you had specified shutdown(wait=False)
, which you had not).
The equivalent code that utilizes multiprocessing.pool.Pool
would be:
QUESTION
I'm creating a project to learn React Native. I'm using typescript on this project. I added react-navigation : To make react-navigation working, I had to do :
...ANSWER
Answered 2022-Feb-05 at 12:14The new version, of react-native-gesture-handler send warning if you use an old API version, but also if one of your package/library use it.
To disable the warning, you can ignore logs.
in your app.js / app.tsx
QUESTION
I have a server to handle events, this server has a mutex lock
and a events
table(map structure). When the server receives a new event, it will acquire lock
to prevent data race, store this event in the events table, and start a goroutine to monitor this event has done. If I run the program with -race
flag, it will output data race
.
ANSWER
Answered 2022-Feb-26 at 03:47As per the comments your code attempts to read and write to a map simultaneously and, as per the go 1.6 release notes:
if one goroutine is writing to a map, no other goroutine should be reading or writing the map concurrently
Looking at your code there appears to be no need for this. You can create the channels in advance; after they are created you are only reading from the map
so there is no issue:
QUESTION
I am building an airport model with passengers spawning, shopping/eating and departing.
Most passengers rush to their GateArea (Polygonal Node) and wait there until they feel it is appropriate to engage in discretionary activities. When they think about leaving the GateArea they generate a "Eat"- or "Shop"- Goal" and are transferred into a PedGoTo-Block that is linked to the according shop. At this point I sometimes get the error:
...ANSWER
Answered 2022-Feb-22 at 15:32Assuming that there really aren't any obstacles other than other pedestrians, then the parameter that can help improve your situation is the diameter of the pedestrian. Reducing it means that pedestrians can get closer to each other.
You can also change the diameter dynamically at any point of your simulation using ped.setDiameter( x ). So for example, you can set it to 0 at that specific point in time until the pedestrian leaves that area and change it back to 0.5.
Following the discussion in the comments, it appeared that the issue was not the diameter. Nonetheless, I am keeping it above as it might be the issue for someone facing a similar problem.
The real issue was that the modeler asking the question was making the agent leave the pedestrian flow chart using remove(agent)
. Once the agent is sent back to the flowchart using an Enter
block, AnyLogic no longer recognizes that agent as a pedestrian present in the pedestrian network.
As such, instead of using Enter
block, pedEnter
should be used. The latter requires as input the location of the pedestrian's appearance. Since in your case the pedestrian is not really moving, just leaving the flowchart for modeling purposes, you can specify the location as the agent's current location as shown below.
QUESTION
I'm having trouble wrangling go routines and getting them to communicate back to a channel on the main go routine. To simplify, my code looks something like this:
...ANSWER
Answered 2022-Jan-27 at 15:03You can wait for the group and close the channel in a separate go routine. If the channel is closed, your range over the channel will end after the last sent value has been received.
If you just wait, nothing will receive from the channel. Since the channel is unbuffered, the performTest
goroutines won't be able to send. For an unbuffered channel, the send operation will block until it has been received. Therefore, the deferred wg.Done
call would never happen, and your program is deadlocked. Since Done
is only called after the forever-blocking send has been performed.
QUESTION
I am trying to start a sequence of MPI_Igather calls (non-blocking collectives from MPI 4), do some work, and then whenever an Igather finishes, do some more work on that data.
That works fine, unless I start the Igather's from different threads on each MPI rank. In that case I often get a deadlock, even though I call MPI_Init_thread to make sure that MPI_THREAD_MULTIPLE is provided. Non-blocking collectives do not have a tag to match sends and receives, but I thought this is handled by the MPI_Request object associated with each collective operation?
The most simple example I found failing is this:
- given np MPI ranks, each of which has a local array of length np
- start one MPI_Igather for each element i, gathering those elements on process i.
- the i-loop is parallelized using OpenMP
- then call MPI_Waitall() to finish all communication. This is where the program hangs when setting OMP_NUM_THREADS to a value larger than 1.
I made two variants of this program: igather_threaded.cpp (the code below), which behaves as described above, and igather_threaded_v2.cpp, which gathers everything on MPI rank 0. This version does not deadlock, but the data is not ordered correctly either.
igather_threaded.cpp:
ANSWER
Answered 2022-Jan-17 at 05:03In your scheme, because the collectives are started in different threads, they can be started in any order. Having different requests is not enough to disambiguate them: MPI insists that they are started in the same order on each process.
You could fix this by:
QUESTION
There is a code:
...ANSWER
Answered 2022-Jan-04 at 18:20You have three deadlocks:
- errValue := <-errCh // if no errors, i have panic - fatal error: all goroutines are asleep - deadlock!
- wg.Wait() # line 44
- errCh <- err # line 29
the second one never happend because of return statement or first deadlock. for fixing deadlock 1, we must read channel with non-blocking mode. for fixing deadlock 2, we must use wg.Done in each goroutine. for fixing deadlock 3, we must use buffered channel or somehow we must consume the channel. here for simplicity I choose buffered channel, but we can read errCh inside for loop and return error if we saw error.
QUESTION
Ok, I'm totally lost on deadlock issue. I just don't know how to solve this.
I have these three tables (I have removed not important columns):
...ANSWER
Answered 2021-Dec-26 at 12:54You are better off avoiding serializable isolation level. The way the serializable guarantee is provided is often deadlock prone.
If you can't alter your stored procs to use more targeted locking hints that guarantee the results you require at a lesser isolation level then you can prevent this particular deadlock scenario shown by ensuring that all locks are taken out on ServiceChange
first before any are taken out on ServiceChangeParameter
.
One way of doing this would be to introduce a table variable in spGetManageServicesRequest
and materialize the results of
QUESTION
My application is a sprint boot application that uses log4j2 and runs in a Wildfly server. After the zero day attak, we upgraded to the latest log4j2 version(2.16). But after the log4j upgrade, my application stops working once in a while. And when I looked at the threaddumps, I found that there is a deadlock created by log4j. Here is my log4j configuration. It was working fine before the upgrade.
...ANSWER
Answered 2021-Dec-23 at 16:03Found my answer in this thread https://developer.jboss.org/thread/241453. It is a log4j/jboss configuration issue. The fix is to either exclude jboss logging subsystem from jboss deployment configuration or get rid of the console appender. Thanks to Ralph Goers from Log4J team for guiding me towards the jboss thread.
I have closed the issue that I raised to https://issues.apache.org/jira/browse/LOG4J2-3274. The code snippet that I shared in this question was from log4j-1.2 compatibility adapter which doesn't has any impact in my code because I am already using the latest api version.
QUESTION
I'm reading The Little Go Book.
Page 76 demonstrates how you can deadlock with a single lock:
...ANSWER
Answered 2021-Dec-19 at 21:03In the first example, main sleeps long enough to give the child goroutine the opportunity to start and acquire the lock. That goroutine then will merrily exit without releasing the lock.
By the time main resumes its control flow, the shared mutex is locked so the next attempt to acquire it will block forever. Since at this point main is the only routine left alive, blocking forever results in a deadlock.
In the second example, without the call to time.Sleep
, main proceeds straight away to acquire the lock. This succeeds, so main goes ahead and exits. The child goroutine would then block forever, but since main has exited, the program just terminates, without deadlock.
By the way, even if main didn't exit, as long as there is at least one goroutine which is not blocking, there's no deadlock. For this purpose, time.Sleep
is not a blocking operation, it simply pauses execution for the specified time duration.
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