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QUESTION
I'm trying to calculate the mean, standard deviation, median, first quartile and third quartile of the lognormal distribution that I fit to my histogram. So far I've only been able to calculate the mean, standard deviation and median, based on the formulas I found on Wikipedia, but I don't know how to calculate the first quartile and the third quartile. How could I calculate in Python the first quartile and the third quartile, based on the lognormal distribution?
...ANSWER
Answered 2021-Jun-08 at 20:07Given a log-normal distribution, we want to compute its quantiles. Furthermore, the parameters of the log-normal distribution are estimated from data.
The script below uses OpenTURNS to create the distribution using the LogNormal
class. It takes as inputs arguments the mean and standard deviation of the underlying normal distribution. Then we can use the computeQuantile()
method to compute the quantiles.
QUESTION
I face the following problem with GEKKO: some parameters (.Param) are changing (others not) when solving a model and I cannot determine why.
Background: I am currently trying to translate code from EViews (see gennaro.zezza.it) to python. I use GEKKO to simulate a system consisting out of 11 equations (for now). I do want to use parameters (instead of constants which seem to work perfectly fine) as I need to ('exogenously') change their value over time (and thus need an array).
Example: In the following example, an 'economic system' reacts to new government expenditures. Here, I particularly face problems with "m.alpha1" and "m.alpha2" - if they are introduced as ".Param" their value will change to 1.0 (instead of 0.6 and 0.4) when solving the model. How can I stop GEKKO from doing this? (Again, I want to be able to change, e.g., alpha1 to 0.7 after time x. E.g., lower and upper bounds won't help here.)
Thanks for your help!!
Code:
...ANSWER
Answered 2021-Jun-08 at 17:53The problem is that the name of the variable name='Propensity to consume out of income'
is over 25 characters long.
QUESTION
Matplotlib madness...
...ANSWER
Answered 2021-Jun-05 at 03:37It's not flattening it per se. But the scale of the second line/plot is much bigger than the first that it shows like it's flattened.
You will need to use multiple scales (multiple y axis).
Check out this example from the matplotlib documentation.
Basically, you will need to do something like this:
QUESTION
I have been asked to plot some histograms and KDEs using seaborn. We just want to focus on a range of the X axis, so I use ax.set_xlim(20_000, 42_460)
. In some cases most of the data is before 20.000 so the plot looks like this:
The full plot looks like this:
There is data, but since most of it is on the range (0,20.000) matplotlib adjusts the Y limit to it and in the range (20.000, 42.460) the data cannot be appreciated.
I would like to know a way to automatically adjust the Y limit so the data in the range (20.000, 42.460) is visible. I have been asked to not to plot just the range (20.000, 42.460), I have to plot the range (0, 42.460) and then zoom in the range (20.000, 42.460).
I have found Axes.relim()
that can take an argument visible_only=True
but it does not seem to work as I expected.
Other option could be to use a different library to calculate the histogram data, calculate then the Y limit and set it with ax.set_ylim(0, range_max)
but we are also plotting a seaborn KDE that has the same problem and that could be more complicated. Here it is an immage of a good plot:
EDIT:
To reproduce the plot use this data and this code:
...ANSWER
Answered 2021-May-30 at 21:29The fastest way to achieve what you want is to subset your DataFrame:
QUESTION
I tried implementing morphological erosion on digital images with Python. I uploaded a binary image and defined a structural element - ones(3,3). But when I run the code, the following error occurs:
RuntimeError: sequence argument must have length equal to input rank
Please assit. Below are my codes:
...ANSWER
Answered 2021-May-30 at 12:14Posting what I mentioned as a comment - You are trying to perform the erosion operation on a RGB image. You need to convert the RGB image to a binary image and then perform erosion with the structuring element.
QUESTION
Hi I'm very new to Python, and I'm trying to fix the labels because they overlap, (as seen in the picture). I figured the hspace and the wspace is the columns, but I'm not sure exactly how to adjust everything else in the labels, I don't want to mess with the x axis. Is there a way to make this plot look clearer?
Here's what I have:
...ANSWER
Answered 2021-May-25 at 13:47You can try to use plt.tight_layout
, adjusts subplot params so that the subplot(s) fits in to the figure area
QUESTION
I have a data frame in pandas and I would like to plot the error bars in different colors (The colors are given in a column 'Colors').
I'm using the errorbar function in matplotlib and my code works if the error is symmetric.
Here is my code:
...ANSWER
Answered 2021-May-25 at 13:46The problem arises because you are plotting length-1 data and errors. First, let's see the doc string:
xerr
,yerr
float or array-like, shape(N,) or shape(2, N), optionalThe errorbar sizes:
- scalar: Symmetric +/- values for all data points.
- shape(N,): Symmetric +/-values for each data point.
- shape(2, N): Separate - and + values for each bar. First row contains the lower errors, the second row contains the upper errors.
- None: No errorbar.
When you give yerr = [min_val, max_val]
, it is interpreted as a shape(N,) array - which as you can see, it then thinks are symmetric values for each point. But since you only have one data point (N=1
), it gets confused.
Instead, you want to give your errors as a shape(2, N) list or array. For example:
QUESTION
The gallery of matplotlib
has a 2D scatter plot with two adjacent histograms for the marginal distribution of x
and y
values at the top and right, respectively. I want to modify that to show the histogram of y
values on the left (instead of the right) but also oriented towards the scatter plot.
All I managed so far was to merely move it from the right to the left (see below), but not re-orientate it towards the scatter plot. How can I achieve that?
Here is my code:
...ANSWER
Answered 2021-May-25 at 10:29This can be achieved by setting the y-axis limit in the opposite direction.
QUESTION
I am very new to Python. I am trying to run this script:
https://scikit-image.org/docs/0.12.x/auto_examples/segmentation/plot_local_otsu.html
But, I'm getting this error:
...ANSWER
Answered 2021-May-25 at 08:50As you can see from the link, the example is from the outdated 0.12.x
version(s) of skimage
, whereas 0.18.0
is current stable version. And, as the error message indicates, the error comes from this line:
QUESTION
ANSWER
Answered 2021-May-21 at 17:16Since I spent some time on this, I thought I share this so that others can easily adapt this approach:
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