RandomChoice | An simple library for making those hard
kandi X-RAY | RandomChoice Summary
kandi X-RAY | RandomChoice Summary
A little helper library that given an (optionaly weighted) list of methods chooses one at random. Useful if you are making a game or something I guess. You can also optionally weight each action.
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Trending Discussions on RandomChoice
QUESTION
I understand that the computer is generating a random choice from the choices array, but for some reason I don't see the connection from the original choices array. Is the choices array being changed or another reference created? I just don't get it.
...ANSWER
Answered 2021-May-16 at 03:16The choices array there is just the same array, same memory address, the exact same thing.
The choices[...] means "evaluate ..., then get the N-th index of choices (N = value of ...)"
In this case, it's saying:
- Get a random decimal number between 0 and 1
- Multiply it by the # of choices
- Floor the number (2.9 => 2, etc)
- Get that index in the array
You could also write it like this:
QUESTION
I am trying to create a Twitter bot that tweets a random caption and corresponding image from a json file every 30 minutes. So far I have:
...ANSWER
Answered 2021-Mar-04 at 00:42You need something like:
QUESTION
as i know class type parameter is always passed as reference. but whenever i pass a class type variable which is class member as parameter. it always works like call by value.
...ANSWER
Answered 2021-Feb-01 at 14:43When used in a method's parameter list, the ref keyword indicates that an argument is passed by reference, not by value. The ref keyword makes the formal parameter an alias for the argument, which must be a variable.
So I'll try to explain the makes the formal parameter an alias as simple as possible.
Without refImagine the stageTerrain from private MapEntity stageTerrain = new MapEntity(); as a box holding an address.
Imagine the mapEntity from public void RandomChoice(MapEntity mapEntity) as another NEW box.
- If you change a property of the mapEntity before assigning a new object, it will also change the value of the calling variable.
When you call the RandomChoice the mapEntity is a new box holding the same memory address as the stageTerrain box.
Now mapEntity = stageTerrains[Random.Range(0,selectedList.Count)]; will assign the selected value only to the New box.
Imagine the mapEntity from public void RandomChoice(ref MapEntity mapEntity) as an alias for an already existing box that will hold the memory reference just with a different name. (thus the alias statement)
When you call the RandomChoice the mapEntity is the stageTerrain box.
QUESTION
Question is:
...Create a text file named team.txt and store 8 football team names and their best player, separate the player from the team name by a comma. Create a program that reads from the text file and displays a random team name and the first letter of the player’s first name and the first letter of their surname.
ANSWER
Answered 2021-Jan-19 at 14:34The issue is with this line:
QUESTION
Question: Create a text file named team.txt and store 8 football team names and their best player, separate the player from the team name by a comma. Create a program that reads from the text file and displays a random team name and the first letter of the player’s first name and the first letter of their surname.
...ANSWER
Answered 2021-Jan-13 at 12:52I think this should do it:
QUESTION
I am have a issue here, I am trying to create this Rock, Paper, Scissors game and am having trouble with button choices for the user to pick. I am having no luck with getting the code to update the playerTurn.currentPick property to update what the player chose on the button click. I create a function called choiceBtn which is suppose to update the property with what the user chooses. I am a newbie in coding as you can tell but any help would be appreciated. Below is my JS code and I will attached the HTML code as well if it would help.
...ANSWER
Answered 2021-Jan-12 at 01:34You were on the right track. There were just a couple of issues around defining your on click events. I removed these from the function they were in so that they could be defined at the start of the run. There was also an issue with moving the player choice to the current pick variable. Your paper and scissors were being moved to the variable name.
The snippet shows the onClick events working, but there does appear to be further work needed in checking the results of the game. It's not always correct about who wins
QUESTION
I am writing a simple transformation for a dataset which contains many pairs of images. As a data augmentation, I want to apply some random transformation for each pair but the images in that pair should be transformed in the same way.
For example, given a pair of two images A and B, if A is flipped horizontally, B must be flipped horizontally as A. Then the next pair C and D should be differently transformed from A and B but C and D are transformed in the same way. I am trying that in the way below
ANSWER
Answered 2020-Dec-25 at 13:35I dont know of a function to fix the random output. maybe try a different logic, like creating the randomization yourself to be able to reuse the same transformation. logic:
- generate a random number
- based on the number apply a transformation on both images
- generate another random number
- do the same for the other two images try this:
QUESTION
cy.get("#severities").then(($optionsArray) => {
expect($optionsArray.get(0)).to.have.property('childElementCount', 6)
let optionVal = new Array()
optionVal = $optionsArray.children()
var randomChoice = optionVal[Math.floor(Math.random() * optionVal.length) + 1]
addAppointment.selectSeverity(randomChoice.text)
})
ANSWER
Answered 2020-Dec-01 at 11:03To wait for options to load, insert a .should() between the .get() and the .then(). Or perhaps even changing .then() to .should() will do the trick.
The key thing with .should() is that it retires the preceding command until it's criteria succeed, so it's ideal for waiting for async data.
So
QUESTION
I am making a small game and I have two variables; one for the player's choice and another for the computer's random choice. The player can choose between attack1, attack2, and attack3. And so will the computer (using Math.random()).
I want to increase the score of the winner if they choose an option that beats the computer's option. And increase the number of draws if they choose the same.
I have written an if-else statement that accomplishes this but I think it should be possible to make it shorter or better. Let's call the attacks rock, paper, and scissors so it's easy to see who would win:
THE WHOLE JS CODE IS IN THE CODE SNIPPET AND JSFiddle
...ANSWER
Answered 2020-Nov-10 at 15:09You could turn the choices into numbers alone, and then just check whether the difference between the computer's and the player's, modulo 3, is 0, 1, or 2:
QUESTION
I am working on a project for an introductory CompSci course in java and I am stuck. We have to fill out the methods for a rock, paper, scissor game called stick, fire, water. I thought I filled it out correctly, but every time I run it, my program says it is a tie. It displays both my choice and the computer choice, but it says it is a tie and it doesn't increment the rounds played (or either my score or the computer's score, but since it is a tie that would not happen anyways, although I am sure it is still messed up).
...ANSWER
Answered 2020-Oct-07 at 22:36There are numerous suspicious things about your code, but the specific issues you describe are likely related to the fact that your playRound() method declares local variables shadowing most of the class's instance variables:
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