Impatient | Ai n't nobody got time for data | SQL Database library

 by   tuespetre C# Version: Current License: MIT

kandi X-RAY | Impatient Summary

kandi X-RAY | Impatient Summary

Impatient is a C# library typically used in Database, SQL Database, Nodejs applications. Impatient has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Ain't nobody got time for data.
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            kandi-support Support

              Impatient has a low active ecosystem.
              It has 112 star(s) with 11 fork(s). There are 12 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 6 open issues and 1 have been closed. On average issues are closed in 8 days. There are 4 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Impatient is current.

            kandi-Quality Quality

              Impatient has 0 bugs and 0 code smells.

            kandi-Security Security

              Impatient has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Impatient code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Impatient is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Impatient releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.
              Impatient saves you 347 person hours of effort in developing the same functionality from scratch.
              It has 830 lines of code, 0 functions and 314 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Impatient
            Get all kandi verified functions for this library.

            Impatient Key Features

            No Key Features are available at this moment for Impatient.

            Impatient Examples and Code Snippets

            For the impatient
            pypidot img1Lines of Code : 17dot img1no licencesLicense : No License
            copy iconCopy
            from decorator import decorator
            @decorator
            def warn_slow(func, timelimit=60, *args, **kw):
                t0 = time.time()
                result = func(*args, **kw)
                dt = time.time() - t0
                if dt > timelimit:
                    logging.warning('%s took %d seconds', func.__na  

            Community Discussions

            QUESTION

            Scala Inheritance - How declaring fields as final solve construction order problem
            Asked 2021-May-24 at 16:04

            I am referring book "Scala for the Impatient" for learning purpose. I found some example of construction order problem and solution of early definition.

            The book has tried to showcase the problem with following class :

            ...

            ANSWER

            Answered 2021-May-24 at 16:04

            Your book is correct but not completely. There is a type of expression in Scala called Constant Value. It is inlined everywhere it is used:

            The final modifier must be present and no type annotation may be given. References to the constant value x are themselves treated as constant expressions; in the generated code they are replaced by the definition's right-hand side e.

            So in short,

            1. It requires final keyword
            2. It requires no type annotation

            Then they are inlined in the class definition and therefore it is 2 in your Ant class.

            In other cases where you supply a type definition like final override val range: Int = 2, then it is not considered a constant value and not inlined. Therefore it is initialized according to the regular order of inheritance.

            Source https://stackoverflow.com/questions/67653124

            QUESTION

            How to fix Traceback module error in Python?
            Asked 2021-May-18 at 17:32

            I am trying to making a python autogenerated Email app but there is a problem when running the code the traceback error shows up but I did write the code as my mentor write it down. This is the code that I used:

            ...

            ANSWER

            Answered 2021-May-18 at 03:10

            Try and set the encoding to UTF-8

            For example:

            file = open(filename, encoding="utf8")

            For reference check this post:

            UnicodeDecodeError: 'charmap' codec can't decode byte X in position Y: character maps to

            Source https://stackoverflow.com/questions/67579384

            QUESTION

            Issue in function without errors
            Asked 2021-May-08 at 05:27

            Recently I've tried to challenge myself by trying to make a quiz game, however, as expected I've stumbled upon a error already and I can't resolve it. Well, there's no errors, but it's not working as intended, any suggestions on what to modify ?

            Also, I'm a very beginner to C++ (still learning), so this might seem very dumb to others since I can already assume the problem is trivial.

            Here's the code:

            ...

            ANSWER

            Answered 2021-May-05 at 14:34

            This line of code can't be true :

            Source https://stackoverflow.com/questions/67403067

            QUESTION

            The tkinter windows freezes after playing a sound effect when user clicks on "continue"
            Asked 2021-Apr-28 at 11:00

            When I was trying to play a "yay" sound effect after the user has passed the test, I will show the credits. However, considering that some users are impatient and they don't want to see it, I made a tkinter window to show the option of whether to see or not. But when the user clicks on "continue", the tk windows freeze (Freezed window) and after a while, it is normal again.
            This may not be a very big problem. However, if it is compiled to exe file, it may cause sudden exit without warning and this is not a good user experience. So is there any way to stop the freeze?
            This is part of the codes in which the window freezes.

            ...

            ANSWER

            Answered 2021-Apr-28 at 10:58

            Don't let it block the main thread:

            Source https://stackoverflow.com/questions/67298813

            QUESTION

            How can I run my python code on google and give access to public or other users without using any money
            Asked 2021-Mar-18 at 05:45

            I have made a program using python language which tells your Horoscope. I made that on Jupyter-notebook, Anaconda. I opened it on word its code is: {

            ...

            ANSWER

            Answered 2021-Mar-18 at 05:38

            Colab is quite similar to jupyter notebook and is free to use. Just send the link to other once you add your code. https://colab.research.google.com/ is the link. A quick guide is: https://colab.research.google.com/github/jckantor/CBE30338/blob/master/docs/01.01-Getting-Started-with-Python-and-Jupyter-Notebooks.ipynb

            Source https://stackoverflow.com/questions/66685325

            QUESTION

            Implement a "Find all" algorithm that displays matched lines in a table, and jumps to line when table cell clicked
            Asked 2021-Mar-13 at 15:14

            I would like to implement functionality for being able to search a QPlainTextEdit for a query string, and display all matched lines in a table. Selecting a row in the table should move the cursor to the correct line in the document.

            Below is a working example that finds all matches and displays them in a table. How can I get to the selected line number in the string that the plaintextedit holds? I could instead use the match.capturedEnd() and match.capturedStart() to show the matches, but line numbers are a more intuitive thing to think of, rather than the character index matches.

            MWE (rather long sample text for fun) ...

            ANSWER

            Answered 2021-Mar-13 at 15:14

            In order to move the cursor to a specified position, it's necessary to use the underlying QTextDocument using document().
            Through findBlockByLineNumber you can construct a QTextCursor and use setTextCursor() to "apply" that cursor (including the actual caret position) to the plain text.

            Source https://stackoverflow.com/questions/66614639

            QUESTION

            How to add line breaker in array and make it right aligned
            Asked 2020-Dec-31 at 07:48

            I am noob in java script .Just made a small project that generates quotes. But i want that that the name of the person who gave the quote should be in next line and right aligned but cant figure out how to do that in an array line breaker tag does not work.

            HTML

            ...

            ANSWER

            Answered 2020-Dec-31 at 07:48

            Adding a tag can make a new line. Making the text aligned at the right need CSS.

            Source https://stackoverflow.com/questions/65517771

            QUESTION

            Accessing signed in user in dotnet 3.1 with HttpContextAccessor
            Asked 2020-Dec-17 at 08:02

            Okey, so i'm getting impatient here. :) I'm trying to access my signed in user through HttpContext.User by accessing the IHttpContextAccessor but no user is available, nor any claims. Dotnet core 3.1 is being used here. This is basically how I understand it: Sign in user with HttpContext.SignInAsync(... and then the context is available through the IHttpContextAccessor outside controllers. Now, the context is available but cant find any accessible user information from the signin. I do see that the cookies are correctly attached to the requests but there is some transformation not being done. Does anyone know what I am missing?

            ...

            ANSWER

            Answered 2020-Dec-14 at 05:47

            As far as I know, if we has used the cookie authentication and user has already login in, we could get the claims from the httpcontext accessor.

            I suggest you could firstly make sure the browser has set the authentication token via cookie to the server.

            Then I suggest you could make sure you have inject myclass as the scoped not Singleton.

            More details, you refer to below test codes to read the cookie.

            Myclass:

            Source https://stackoverflow.com/questions/65269320

            QUESTION

            How to ask for user input and return it in a new inventory
            Asked 2020-Nov-07 at 22:14

            I am 13, so please do not get impatient with me here as I might be making a dumb mistake or not thinking something in the right perspective.

            I want to make a Spigot plugin to increase my Java knowledge a little bit, by making a project that is fun and educational. I'm following a tutorial on how to make a GUI, but wanted to create it with a twist that is not too complex.

            I was poking around and found something that is similar to show an example of this LobbyCompass.

            Here is my "GuiConstruct" class

            ...

            ANSWER

            Answered 2020-Nov-07 at 22:10

            I maybe didn't understand your question, as it wasn't straight-forward. As I get it, you want to create command that opens up a GUI with specified name. There are multiple ways to do that... The simplest way is to implement method onCommand in plugin main class.

            Source https://stackoverflow.com/questions/64732738

            QUESTION

            How to let run only one instance of application at a time?
            Asked 2020-Oct-31 at 13:43

            I am working on a GUI application that uses JavaFX(not fxml) and exported as a JAR. For slow machine, impatient user click more than once on JAR, and multiple instances of application started.

            I'm looking for a solution to let only one instance can be run at a time on a system and if the user clicks again while the application is running nothing happens. I think it's called singleton but don't know how to implement it.

            ...

            ANSWER

            Answered 2020-Oct-31 at 12:10

            One easy solution that I've used is, when you start the application, it creates a file (I named it .lock but you can call it whatever you want), unless the file already exists, in which case the application terminates its execution instead of creating the file.

            Source https://stackoverflow.com/questions/64621511

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Impatient

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            gh repo clone tuespetre/Impatient

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