ripper | Images posted on the ViperGirls Forums | Collaboration library
kandi X-RAY | ripper Summary
kandi X-RAY | ripper Summary
VG-Ripper is a Utility that Downloads (Rips) all Images posted on the ViperGirls Forums, and PG-Ripper on all VB (vBulletin) Forums.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of ripper
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QUESTION
I have a dictionary of names (where the key is the name and the value is a list of aliases associated to that name), and a body of text. I want to find and count the number of times a pair of names are N words apart in the body of text.
For example :
...ANSWER
Answered 2022-Jan-02 at 17:59The main idea here is to (1) includes the name itself in the lookup array in found_names
, and then (2) convert your input string to a dictionary of indices; each index will have just one name attached to it, if the word in that particular index is a name (or an alias).
After this, (3) for each index we will check if any index greater than current one is found in range (given by N
); if so, we will increase the counter for the pair current name, other name.
QUESTION
I'm working on a database for adding bands, musicians, instruments, etc.
I have a table 'band' and a table 'musician'. They have a ManyToMany relationship (one band can have many musicians, a musician can be in many bands), with an extra table BandMusician that has an embeddedId BandMusicianId. I did it like this because I want the relationship between bands and musicians to have also other information, like the year the musician joined the band.
...ANSWER
Answered 2021-Dec-04 at 15:10I have the entities Band and Musician and a ManyToMany relationship between them with an association table BandMusician.
What I wanted was to create the entity Musician and the relationship (BandMusician) in the same request.
As far as I can gather it is not possible, because in order to create a record in the association table (BandMusician), I would have to have the musician (I'm creating in this request) already created.
I tried everything just to see if it was POSSIBLE and wasn't able to do it. But even if it was possible, it would be a very bad practice, since it would make the class too tightly coupled.
The clear solution was to create only the Musician with this request, and then send another request to create the connection between Band and Musician.
I also tried to create many entries in the BandMusician table with one request, which was also impossible, because the JsonDeserializer table doesn't seem to accept List<> as a return type. I was trying to avoid making a lot of requests to create the relationship entries (for a musician that is in five bands, for example), but it seems it is better to keep things clear and simple.
I now save one musician-band relationship per request:
QUESTION
I have a wordpress+nginx in a docker container that is working perfectly through the browser, but when I try to send an http request via curl without headers the response is always empty
...ANSWER
Answered 2021-Nov-17 at 16:04This has nothing to do with docker or wordpress or something else.
It is your nginx-configuration solely that rejecting the request:
You have Curl
in your http-agent comparison in nginx-server.conf
:
QUESTION
I am trying to run command
...ANSWER
Answered 2021-Aug-13 at 21:59Ruby 2.0.0 is very much past its end of life, so I'm assuming you have a specific reason you need install it. Otherwise, you are much better off installing a modern, supported version such as 2.7.x or 3.0.x.
Older versions of ruby were built with openssl@1.0
. After 1.0 went end of life, ruby-build
had a breaking change to require openssl@1.1
. This means that ruby versions < 2.4 can no longer be installed/built directly using ruby-build (i.e., rbenv). This GitHub issue has details.
Homebrew has removed its openssl@1.0
formula, but you can still install it via an rbenv tap. The following might work for you, though the comments in the issue report mixed results depending on the version of Command Line Tools being used.
QUESTION
I have been trying to populate a listView in a fragment. I want it populated manually.
I have gone through so many other stackoverflow questions on the same topic but none of them have worked for me.
Here is my onCreateView in my fragment file StoriesFragment.java
...ANSWER
Answered 2021-Apr-06 at 15:26Never mind, I fixed it. I'm extremely dumb.
In the adapter file, StoryAdapter.java, I was setting the text from getAppCount() to a textview, while the function returns an integer and not a string. It worked when I converted it to string.
QUESTION
I am working on a product page where the user has an option to filter on different boardgames. What I want to do is to give the user an option to filter on time, category of the game, number of players and age. When the user enters a checkbox on all 4 options there should be some games recommended based on the criteria. However when I check multiple boxes I get no result, what am I doing wrong? (I have more games in my file but post small amount)
Here's my code:
...ANSWER
Answered 2021-Mar-14 at 09:44So here is the problem :
QUESTION
After about a year of writing these files by hand, I'm looking for a way to generate QC files. I have tried just hard coding the commands in a list and just writing out the the command and its value as text, but this feels very brute force-ish, and I'm figuring there must be a more elegant way to populating the file. If it matters, my end goal turning this into an add-on for blender. EDIT: Adding example output/QC file
...ANSWER
Answered 2020-Aug-27 at 06:47As I alluded to in the comments, you could come up with a tree-like API for these objects.
For example,
QUESTION
How can I change E-Mail Sender Name into customer “Billing First & Last Name” using woocommerce_email_from_name
hook?
For Example: "My Shop" should be changed to "John Doe".
Based on Change sender name and email address for specific WooCommerce email notifications answer code, here is my function:
...ANSWER
Answered 2020-Jul-21 at 09:06The following will change the "From name" to customer billing full name on Woocommerce email notifications:
QUESTION
I have those two tables implementing some inheritance relationship via the Class Table Inheritance pattern:
...ANSWER
Answered 2020-Jun-26 at 12:26what suprises me is that I can insert
NULL
values
No you can't insert NULL
values.
Every time you execute this:
QUESTION
I'm new to John the Ripper, I was running in incremental mode which is taking a while (as expected) and I was wondering that if I aborted the cracking process (crt + c) and if a password was cracked it will still be saved? Or is there a better way to exit the cracking process.
...ANSWER
Answered 2020-Mar-27 at 02:11On Linux, saved passwords are stored in user/.john/john.pot
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