chili | Simple expression evaluation engine for Go | Parser library
kandi X-RAY | chili Summary
kandi X-RAY | chili Summary
Currently in development, Unstable (API may change in future). Simple expression evaluation engine. Expression is one liner that evalutes into single value.
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Top functions reviewed by kandi - BETA
- joinImpl is a helper function to create a string with delimiter
- putDataToEnv marshals data to environment variables .
- TruthFullness returns true if value is a fullness .
- Eval evaluates the given expression .
- GetType returns the type of value .
- logical operation .
- sliceImpl impl .
- concatImpl concatenates arguments into a string .
- minImpl impl
- maxImpl returns the maximum value
chili Key Features
chili Examples and Code Snippets
package main
import (
"fmt"
"github.com/5anthosh/chili"
)
func main() {
expression := "val > 50 ? 'Greater than or 50' : 'Smaller than 50'"
values := map[string]interface{}{
"val": 60,
}
result, err := chili.Eval(e
Community Discussions
Trending Discussions on chili
QUESTION
I am working on a project in which I need to post a new Course to my API. I tested this with POSTMAN and API works just fine, however when I try to post data using react fetch data is corrupted. While sending single strings like dishName: "pizza" works just fine and is shown in database I cannot manage to send an array of objects. I tried to do it in many ways like:
...ANSWER
Answered 2021-May-27 at 21:44You are setting the ingredients
state as a string, so you are basically 'stringify' a string which will result in JSON SyntaxError
. If you want to send an array that way you must specify the array bracket [
and ]
in order to make it a valid array.
To solve it just change:
QUESTION
I have a dataframe with prices in $. I want to do calculations on it but the $ makes it impossible. I'm trying to remove it using df.iloc[:, 4].replace("$", " ", regex=True)
but unfortunately nothing changes. If I add inplace=True
then whe whole word disappears. What am I doing wrong? Tried many stackoverflow posts but nothing works. I cant use str.replace()
because its about the whole column not one word.
My code:
...ANSWER
Answered 2021-Apr-16 at 15:53df.iloc[:, 4].replace("\$", " ", regex=True)
QUESTION
I am currently trying to remove from a list when I press a button. I have tried this:
...ANSWER
Answered 2021-Mar-20 at 19:21setCurrentSelection
does the job of "setting" currentSelection
(thus the name), so you don't need to also assign it with the =
. Just use:
QUESTION
const id = [1, 4, 10]
const data =[{id: 1, name: Banana}, {id: 2, name: Mango}, {id: 3, name: Chili}, {id: 4, name: WaterMelon}, {id: 10, name: WaterMelon}]
...ANSWER
Answered 2021-Jan-29 at 02:44Use filter()
with includes()
:
QUESTION
Can anyone assist me in solving the problem below.
- I have a table in sqlalchemy called 'Person'.
- Each person has a unique 'name'.
- 'Person' table has a relationship to 'Pet' table based on the 'name' field.
I would like everyone in the Person table have the possibility to have a pet with the same name of somebody else, but one person cannot have two pets with the same name, but I am not sure how to model/code that.
Person: Zbyszek
- Pet: Flufi - age: 3
- Pet: Chili - age: 2
Person: Jon
- Pet: Chili - age: 4
code:
...ANSWER
Answered 2021-Jan-22 at 12:44You can't have the unique=True
tag on the pets if there can be more than one pet with that name, even if they belong to different people. There is no problem in removing it and I don't see why you would need the name to be unique anyway since you obviously want the possibilty of multiple pets with the same name. Since the ID of the pet is unique the name doesn't have to be.
If you now want only one of each pet name available to one person, you to set that as a table argument for the pet. So that no two pets with the same owner can also have the same name.
Updated pet class:
QUESTION
I am trying to change the price of middle
in a second element of the document from 15.00 to 17.00:
ANSWER
Answered 2021-Jan-17 at 13:07You can try arrayFilters, The filtered positional operator $[]
identifies the array elements that match the arrayFilters
conditions for an update operation.
- try
$exists
operator to check is field available
QUESTION
I'm trying to get a data from an online JSON, so getting the json and printing it works without issue, but when I want a particular data, my IDE give me this error
...ANSWER
Answered 2021-Jan-13 at 18:21You are getting an array at the top level instead of a JSON object. You should use JSONArray instead of JSONObject to parse the inital response object.
QUESTION
I am creating a program which generates a random list of songs, and has a function such that if a user wants to save a song from the random generated list, the user should click the button next to it. Then the user can print the songs he/she saved on a new window, and then I add a function using pickle so that if the user closes and reruns the program the previously saved items are retained and can be reprinted. But an error, how can I implement this correctly
This is the code:
...ANSWER
Answered 2021-Jan-11 at 02:39import pickle
lst = [1,2,3]
with open("test.dat", "wb") as msg:
pickle.dump(lst, msg)
with open("test.dat", "ab+") as msg:
pickle.dump(lst, msg)
with open("test.dat", "rb") as msg:
print (pickle.load(msg))
QUESTION
i have a list of doritos.
...ANSWER
Answered 2020-Nov-28 at 17:29you can try like this:
QUESTION
This code works, but NOT as expected. For example, typing: red displays "Red Hot Chili Peppers", but continuing with red hot, and it disappears. I am not sure, how a new RegExp
should be applied in this code. I managed to come this far with the filtering.
ANSWER
Answered 2020-Nov-11 at 07:20As commented:
No need for this: Object.keys(item) and item[key] === "string" as its an array of string
Your structure is an array of string. So you can directly consume the value and use String methods to validate it
If you have a complex data structure, like nested objects, then using Object.keys
and then looping on them makes more sense as you do not know what keys you might need.
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