DNA | Distributed Networks Architecture Blockchain | Blockchain library
kandi X-RAY | DNA Summary
kandi X-RAY | DNA Summary
DNA is a decentralized distributed network protocol based on blockchain technology and is implemented in Golang. Through peer-to-peer network, DNA can be used to digitize assets and provide financial service, including asset registration, issuance, transfer, etc.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of DNA
DNA Key Features
DNA Examples and Code Snippets
public static void main(String[] args) {
assertEquals(new ArrayList<>(),
findRepeatedDnaSequences("AAAAACCC"));
assertEquals(Arrays.asList("AAAAACCCCC", "CCCCCAAAAA"),
findRepeatedDnaSequences("A
public static List findRepeatedDnaSequences(String s) {
Map map = new HashMap<>();
for (int i = 0; i < s.length() - 9; i++) {
String cur = s.substring(i, i + 10);
map.put(cur, map.getOrDefault(cur, 0)
Community Discussions
Trending Discussions on DNA
QUESTION
I have a list of axis labels for various water properties. Some have chemical formulae that need subscript. However, I keep getting an error of: non-numeric argument to binary operator.
This is the code for the subscript.
...ANSWER
Answered 2022-Apr-14 at 12:44Your syntax is wrong here. If you want to use square brackets to indicate subscripts, that can only be done in the context of plotmath expressions:
QUESTION
I'm really struggling with this exercise about linked lists and node removal.
Basically, DNA sequences are said to be complementary when each base in one sequence has the corresponding complement in the other sequence at the same position. Base A bonds with T, and base C bonds with G. For example, the sequences ACGT and TGCA are complementary.
I have to implement a function which takes two linked lists: the first is the original DNA and the second is the edit sequence. The function must apply the edit method described earlier and return the new list.
For instance, we've got "A C G T A G A C G T T C T A" as the original DNA sequence and "G C A" as the bonding sequence. G matches with C, C matches with G and A matches with T (and vice-versa). Therefore, "C G T" is "G C A"'s reflex. Then we have to remove "C", "G" and T", following this exact order, from the original DNA sequence, which turns out to be the expected result stated below.
Also, two things: 1. I must ignore any subsequent matches generated as a result of any node removals. 2. I cannot use any headers besides stdlib.h and functions such as malloc() or calloc(). I am only allowed to use free().
Input:
...ANSWER
Answered 2022-Mar-22 at 03:09I should have written a code based on your current code for better communication but I thought it will be simpler not to use the recursion. Would you please try:
QUESTION
I have API that generate pdf file after saving values into database. My customer needed to generate this pdf and then send it by mail. He sended my photo of how should that pdf look like. I recreated it, it looks same as in that picture but it is hard to read because there are missing vertical lines. I looked trought docs and also tried to google, bud I did not found anyithing. Here is how my PDF looks like:
As you can see, vertical lines are missing and because of that is harder to read.
Is there any possibility to add vertical lines?
Here is my code:
...ANSWER
Answered 2022-Mar-14 at 19:50By definition simple PDF structure is not tabular there is one cell (the page) and that one column can be subdivide into two or more rows with null spaces between the text sub columns.
That is why tables are difficult to sub[ex]tract
So adding coloured rows in one area is fairly simple to make like a table, thus to make vertical sub dividers is more difficult, However that feature was added in January 2022 https://github.com/natancabral/pdfkit-table/files/7865078/document-5.pdf
For exsample see https://github.com/natancabral/pdfkit-table/issues/16#issuecomment-1012389097
QUESTION
Here is a DNA string that I want to split and then combine in groups of 3
...ANSWER
Answered 2022-Mar-10 at 01:43You may split every 3 characters in strsplit
.
QUESTION
I have a vector with equal sized 0/1 elements, dna. And a similar vector with same size, flip. If the flip = 1, I want to flip the corresponding figure in the dna vector. So 0 would change to 1 and 1 would change to 0. And without looping to make it fast. My real dataset has a lot of data. Below is some sample data:
...ANSWER
Answered 2022-Feb-16 at 00:15I think the logic you are describing is equivalent to a logical XOR. The difficult part is applying this to character strings. The following should work, and is st least vectorized per element so you don't need to iterate along individual characters:
QUESTION
I'm trying to drop duplicates and keep the row with the maximum values. I can do this separately per strategy.
However, when trying to do this based on two separate conditionals based on the strategy, the dataframe tends to overwrite one another when trying to apply these.
This is needed given that one strategy contains values that one strategy has and another does not; note these do share one common column though.
Current Data ...ANSWER
Answered 2022-Jan-13 at 11:01This can be done by using the pivot_longer()
function to bring the values from the RNA_Col
and DNA_Col
variables into one single column to be handled simultaneously, this column can then be used to repopulate the columns using ifelse()
.
QUESTION
I've got data with time (seconds) on the x axis and intensity (in relative fluorescent units, or rfu) on the y-axis. It's generated by watching fragments of DNA pass a camera - the bigger the DNA fragment the bigger the time. There are 23 fragments of known size (in DNA base pair units, bp), and therefore there should be 23 peaks. As I know the size of the DNA fragments in bp, I want to recalibrate the x-axis from time (seconds) to base pairs (bp) using a linear model.
Unfortunately there is quite a lot of noise in the data that produces spurious peaks. The only way to confidently tell the true ones from the false ones is that the false ones don't fit the expected pattern in DNA base pairs.
I've provided data from one sample at this link in a data frame called demo. Unfortunately it's too large to paste below.
https://1drv.ms/t/s!AvBi5ipmBYfrhf0v_kvWuN2foLyBgg?e=RWfdXZ
I can pick out all the peaks as follows.
...ANSWER
Answered 2022-Jan-04 at 18:39Before plotting, doing some data manipulation to pull out the maximum value for each of the 23 DNA fragment groups with base R max
function, and adding the max plot with additional geom_ layer for the max values.
Here is small reprex example that plots the max value for each group with "red".
QUESTION
Unambiguous DNA sequences consist only of the nucleobases adenine (A), cytosine (C), guanine (G), thymine (T). For human consumption, the bases may be represented by the corresponding char
in either uppercase or lowercase: A
, C
, G
, T
, or a
, c
, g
, t
. This representation is inefficient, however, when long sequences need to be stored. Since only four symbols need to be stored, each symbol can be assigned a 2-bit code. The commonly used .2bit
-format specified by UCSC does exactly that, using the following encoding: T = 0b00
, C = 0b01
, A = 0b10
, G = 0b11
.
The C code below shows a reference implementation written for clarity. Various open-source software that converts genomic sequences represented as a char
sequence typically uses a 256-entry lookup table indexed by each char
in sequence. This also isolates from the internal representation of char
. However, memory access is energetically expensive, even if the access is to an on-chip cache, and generic table look-ups are difficult to SIMDize. It would therefore be advantageous if the conversion could be accomplished by simple integer arithmetic. Given that ASCII is the dominating char
encoding, one can restrict to that.
What are efficient computational approaches to convert nucleobases given as ASCII characters to their .2bit
-representation?
ANSWER
Answered 2022-Jan-09 at 08:28If one stares at the binary codes for the ASCII characters for the nucleobases intently, it becomes clear that bits 1 and 2 provide a unique two-bit code: A
= 0b01000001
-> 0b00
, C
= 0b01000011
-> 0b01
, G
= 0b01000111
-> 0b11
, T
= 0b01010100
-> 0b10
. Analogous for the lowercase ASCII characters, which differ merely in bit 5. Unfortunately this simple mapping does not quite match the .2bit
-encoding, in that the codes for A and T are swapped. One way of fixing this is with a simple four-entry permutation table stored in a variable, likely assigned to a register after optimization ("in-register lookup-table"):
QUESTION
I have thousands of DNA sequences that look like this :).
...ANSWER
Answered 2021-Dec-18 at 15:40Using aregexec
, build a regex pattern with sprintf
, and finally removing the matches using gsub
. Putting it into a Vectorize
d function to avoid overloading the script with lapply
s or loops.
In the regex, the .*
refers to everything before (resp. after) the respective letters. Note, that you probably need to adapt the max.distance=
with your real data.
QUESTION
I was attempting to complete this problem as a newbie, and I'm seeing extra elements within my returned array after my loop.
...ANSWER
Answered 2021-Nov-07 at 03:44Reinitialize the array with new set of elements inside the function and before the loop.
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