lexical | building parsers using the Go programming language | Parser library
kandi X-RAY | lexical Summary
kandi X-RAY | lexical Summary
A set of parsing tools for Go inspired by Sprache.
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Top functions reviewed by kandi - BETA
- Main entry point .
- countHouses returns the number of houses in a file
- many iterates over a function and returns a Result .
- implements b .
- all combines multiple results into multiple parallel .
- stringUntil iterates over the input until it reaches the given delimiter .
- Retreat moves the cursor to the end .
- parseStringInsensitive is similar to Parse except that the string s is case insensitive .
- parseString parses a string and returns a SuccessResult .
- WithStringConcatCombiner concatenates multiple input strings together into a string .
lexical Key Features
lexical Examples and Code Snippets
Community Discussions
Trending Discussions on lexical
QUESTION
ANSWER
Answered 2021-Jun-16 at 01:14The difference in behaviour can be accounted for by this behaviour, described in (for instance) the following note in ECMAScript 2022 Language Specification sect 14.3.2.1
:
NOTE: If a VariableDeclaration is nested within a with statement and the BindingIdentifier in the VariableDeclaration is the same as a property name of the binding object of the with statement's object Environment Record, then step 5 will assign value to the property instead of assigning to the VariableEnvironment binding of the Identifier.
In the first case:
QUESTION
I am generating lexical analyzer with JLEX. I found a regular expression for string literal from this link and used it in .jflex file same of other expressions. but it gives me this error :
unterminated string at the end of the line
StringLiteral = \"(\\.|[^"\\])*\"
can anyone help me please, thanks.
...ANSWER
Answered 2021-Jun-15 at 20:46The regular expression you copied is for (f)lex, which uses a slightly different syntax for regular expressions. In particular, (f)lex treats "
as an ordinary character inside bracketed classes, so [^"\\]
is a character class matching anything other than (^
) a quotation mark ("
) or a backslash (\\
).
However, in JFlex, the "
is a quoting character, whether outside or inside brackets. So the "
in the character class is unterminated. Hence the error message.
So you need to backslash-escape it:
QUESTION
I have the following Raku code:
...ANSWER
Answered 2021-Jun-13 at 11:27This is a bug. Have made an issue for it: https://github.com/rakudo/rakudo/issues/4403
I suggest using the workaround in the meantime.
QUESTION
When defining a syntax, it is possible to match 1 or more times (+) or 0 or more times (*) similarly to how it is done in regex. However, I have not found in the rascal documentation if it is possible to also match a Symbol a specific amount of times. In regex (and Rascal patterns) this is done with an integer between two curly brackets but this doesn't seem to work for syntax definition. Ideally, I'd want something like:
...ANSWER
Answered 2021-Jun-13 at 10:25No this meta syntax does not exist in Rascal. We did not add it.
You could write an over-estimation like this and have a post-parse filter reject more than 5 items:
QUESTION
So i am trying to make e lexical parsher using Flex Code with a bit of Bison.I keep getting a warning about my rules than cannot be matched and i cannot find any error.I have also searched what that warning means,but i think i haven't declared a similar rule again.So there is no chance i think that any other rule overpasses other rules and cannot be matched.I keep getting an error from line 83 which is {COMMA} {return COMMA;},till the end of my code and i dunno why.Any ideas?
...ANSWER
Answered 2021-May-23 at 16:13In your rules, {UNKNOWN_TOKEN}
appears very early. Since it matches any token of any length not containing whitespace, it will match the same tokens as any following rule (and possibly more characters as well). Since (f)lex always choses the first rule if more than one rule is possible, none of the rules after {UNKNOWN_TOKEN}
will ever match.
I suggest you use fewer macros. (Or no macros at all.) They are not contributing anything to your code. They only make it unnecessarily long, and they are confusing you (I think) because macro definitions are not rules and the order of macro definitions does not affect the match, only the order of the rules themselves.
There are some other errors as well. For example, [\+\+]
does not match ++
. It is a character class, so it matches precisely one character. The only character it can match is +
because repeated characters in a set don't change the set. (There is no need to backslash-escape +
in a character class either. Inside brackets most characters lose their special meaning.) What you meant was "++"
.
QUESTION
My professor has given us a question after talking about the difference between lexical and dynamic scope. He presented us a simple evaluator (of a fictional language) coded in Haskell. The following is the code:
...ANSWER
Answered 2021-May-22 at 07:32Your code is incomplete:
QUESTION
I have two files with their own modules, Sub.js and Parent.js
Parent.js:
...ANSWER
Answered 2021-May-17 at 21:28When implementing such circular dependencies, make sure that the file you're using in other code doesn't contain top-level export
declarations that require the other file. In your case:
- If you import
Sub
in some other file, its top-levelexport
requiresParent
which requiresSub
, then it's impossible to resolve: the snake bites its own tail - If you import
Parent
in some other file, its top-levelexport
doesn't needSub
immediately (only whencreateSomething
is being called). In that case, theParent
export
fully resolves, then theSub
file is able to resolve its ownexport
as well.
QUESTION
Hello I see that similar questions have showed up before.
I'm following this tutorial. In this tutorial he prevents the default submit button tutorial by using
...ANSWER
Answered 2021-May-14 at 07:53Assuming the full error message is ReferenceError: can't access lexical declaration`X' before initialization.
Function declarations are hoisted.
Assignments to variables are not.
You can't read addTodo
before you assign a value to it.
Change the order of your source code.
QUESTION
If I defined a function that depends on (uses) a global variable in its module, what would happen if I exported it and tried to call it outside that module?
I have tried it and found that it just works normally, although I don't have access to that variable (it's not defined in my scope). So I want to make sure whether I understand this or not, is this just like the closure functions and the function gets its variables from the lexical scope?
PS: My question is related to the ES6 modules feature.
#Adding real simple Example
This is my html: simply nothing but a script
...ANSWER
Answered 2021-May-13 at 08:41QUESTION
The will
trait gives compile-time access to the Variable
on which it's called. Are there other ways to access the Variable
s that will be installed in a given lexical scope? (I know I can access the Scalar
s at runtime, but I'm trying to get at the Variable
s).
In particular, I would like to be able to do something like the following (which doesn't work):
...ANSWER
Answered 2021-May-11 at 17:30Not at present, however it should be possible in a future Raku language version. Work is taking place to define a standard AST for the Raku language (currently known as "RakuAST"), and to rewrite the compiler frontend to work in terms of it. Once that is done, it will be exposed in a number of places. Macros are the most obvious consumers, however it's also planned:
- To make the AST of a block or routine available from traits, in order that traits can inspect and perhaps even modify the AST
- To introduce custom compiler passes, which will be modules that are given access to the entire AST of the scope that they are imported into
The first of these would seem to satisfy your use case. Going on current proposed API it could look something like this:
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