enumer | A Go tool to auto generate methods for your enums | Generator Utils library
kandi X-RAY | enumer Summary
kandi X-RAY | enumer Summary
Enumer is a tool to generate Go code that adds useful methods to Go enums (constants with a specific type). It started as a fork of Rob Pike’s Stringer tool maintained by Álvaro López Espinosa. This was again forked here as (picking up where Álvaro left off.
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Top functions reviewed by kandi - BETA
- Main entry point .
- splitIntoRuns splits a list of values into a slice of runs .
- parsePackage parses a single package .
- Usize returns the number of bits for n .
- Usage prints the command line flags .
- isDirectory returns true if name is a directory
- init initializes flags .
enumer Key Features
enumer Examples and Code Snippets
Lines of Code : 63License : Non-SPDX (NOASSERTION)
Copytype Pill int
const (
Placebo Pill = iota
Aspirin
Ibuprofen
Paracetamol
Acetaminophen = Paracetamol
)
func (i Pill) String() string {
//...
}
func PillString(s string) (Pill, error) {
//...
}
func PillValues() []Pill {
//...
}
func PillS $ ./enumer --help
Enumer is a tool to generate Go code that adds useful methods to Go enums (constants with a specific type).
Usage of ./enumer:
Enumer [flags] -type T [directory]
Enumer [flags] -type T files... # Must be a single pac type MyType int
...
name := MyTypeValue.String() // name => "MyTypeValue"
name := MyTypeValue.String() // name => "my_type_value"
Community Discussions
Trending Discussions on enumer
QUESTION
We would like SwaggerUI, which is being generated by Swashbuckle, to show all controllers and methods when debugging as well as on our test environment, but hide some on integration and production environments. Note that the hidden controllers/methods will be functional in all scenarios but won't be documented in SwaggerUI.
To do this I've applied the principal described here.
Which results in following code:
Attribute definition:
...ANSWER
Answered 2021-Jun-14 at 11:35I found the solution in this blog post. Thanks @juunas for this
To solve my issue I've kept the code from the initial question to hide controller methods. To hide controllers I've implemented a IActionModelConvention:
QUESTION
I have searched a lot for this topic and already found some approach but I get some errors I can't find the reason of it.
Idea is to read the keys from the enum with QMetaEnum to fill the strings in a combobox later.
I have already the enum and also setup Q_Object and Q_Enum Macro in the class where the enum is. But I am getting "undefined reference to 'Planet:: metaObject() const'" error message by using the QMetaEnum.
Here is the planet.h
...ANSWER
Answered 2021-Jun-11 at 16:05Including QMetaEnum and deriving from QObject usually does the trick:
QUESTION
why my code does not read my specified keys from my enum.
The code itself compiles fine and the program runs without any runtime errors.
Header file with the enum:
...ANSWER
Answered 2021-Jun-12 at 16:15You're missing an important thing:
QUESTION
My aim is to get the display name attribute from my enumerables so that I can display their values on an index page without having strange formatting and instead clear, readable lines.
My enumerables look like this:
...ANSWER
Answered 2021-May-25 at 01:07Here is a demo to get display name with enum value:
EnumExtensions:
QUESTION
i create the below posted color enumeration in a separate file of .ts extension. i would like to know how to use or to call the enumeration in the for-loop in the posted code in such way that to be able to iterate throw it.
in other words, how to iterate through the enumeration posted below in a loop so that for ì = 0 RED is set and when i=7 LIMEis set.
the double question mart, as apparent, is to be replaced be the iteration through the enumeration.
code:
...ANSWER
Answered 2021-Jun-07 at 12:33AFAIK, enum in typescript is basically an object. So you could take the keys and iterate through it
QUESTION
In Elixir, if I have a string such as "José1 José2", how do I enumerate it? If I try to use Enum or for comprehensions, I get the following error:
...** (Protocol.UndefinedError) protocol Enumerable not implemented for "José1 José2" of type BitString
ANSWER
Answered 2021-Jun-05 at 03:47Strings in Elixir are UTF-8 encoded binaries. If you want to enumerate a binary, which is just a collection of bytes, you need to specify how.
String.graphemes/1 - this will give you a list of strings, where each string contains an individual Unicode grapheme. This is probably closest to what you mean if you want each "character".
QUESTION
Finding it difficult to put my problem into words..
I have a function to sort an enumerable with specific conditions and i have another enumerable specified with Enum.take(x, -1)
ANSWER
Answered 2021-Jun-02 at 13:23What I think you're trying to do is a list of one property sorted by another property. I think you could do something like this:
QUESTION
I am having an issue with OpenApi json data validation. Based on the OpenApi validation (or editor.swagger.io) my JSON file has unused models. I am supposed to get rid of the warnings and almost all of them comes from System.Reflection Namespace.
Example:
...ANSWER
Answered 2021-May-26 at 08:13It was caused by internal controller attributes and the error return type (it was set incorrectly). Nothing to do with open api/swagger itself.
QUESTION
I've defined a custom select component in Blazor like this:
ANSWER
Answered 2021-May-26 at 06:56The solution was as follows:
In BetterInputSelect:
QUESTION
So I'm trying to display a list of clubs in my index file. I can see in the debugger that this works like normal. It retrieves the data from the database, sends it through the Dal and Bll and ends like expected (With the right model and matching values) in MVC. The problem is that somehow the program expects there to be a diffrent model after looping through all the clubs. So say I have 5 clubs, it will put them all 5 in the table (the debugger shows this) and after the last one it wants to loop again, but with an another model: The UserModel. I can't find the reason why the program expects the UserModel suddenly.
ClubModel has no foreign keys or anything related to UserModel. UserModel has a foreign key called ClubID. This is the only relation I can think of, but since UserModel is not used in the View, Controller and Model I see no reason why the program suddenly expects a UserModel.
View:
...ANSWER
Answered 2021-May-26 at 00:49From the error message, there must be a view being rendered which has a @model UserModel, while the data passed in is of type List.
You are selecting the view via return View(...) without an explicit view name. So either the view selected by convention, or its layout, must have the mis-matched model.
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