gophernotes | The Go kernel for Jupyter notebooks and nteract | Code Editor library
kandi X-RAY | gophernotes Summary
kandi X-RAY | gophernotes Summary
gophernotes is a Go kernel for Jupyter notebooks and nteract. It lets you use Go interactively in a browser-based notebook or desktop app. Use gophernotes to create and share documents that contain live Go code, equations, visualizations and explanatory text. These notebooks, with the live Go code, can then be shared with others via email, Dropbox, GitHub and the Jupyter Notebook Viewer. Go forth and do data science, or anything else interesting, with Go notebooks!. Acknowledgements - This project utilizes a Go interpreter called gomacro under the hood to evaluate Go code interactively. The gophernotes logo was designed by the brilliant Marcus Olsson and was inspired by Renee French's original Go Gopher design.
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QUESTION
I don't understand the point of the out cell. It seems to be a char count?! Any way to get rid of this altogether?
I am using gophernotes (notebooks for golang)
...ANSWER
Answered 2022-Feb-20 at 19:50This is actually expected. In the official documentation it says
Println formats using the default formats for its operands and writes to standard output. Spaces are always added between operands and a newline is appended. It returns the number of bytes written and any write error encountered.
Thus, what you are seeing is the actual output followed by the number of bytes and the error, which is just nil
in your case (no error as expected).
QUESTION
I have the following problem. I'm assembling an array of dict. However, the append command is putting only the last record. Note that for increments the variable i
and cycles through the list.
The GITHUB API request returns 100 records in the items
list, so I go through this list taking only the information I'm interested in and form a dict for each record and add that record to the list.
The print()
command at the end of the code shows an array with all data equal to the last data in the items array.
ANSWER
Answered 2021-Jun-02 at 01:34You need to move the dictionary creation inside the loop like this because since you append the variable itself to the list as soon as you change the values of the keys it will update for all copies of that dictionary because it points to the same dictionary so all those values in the list will just take the values of the last values you pass to each of the dictionary's keys
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