talaria | highly available , and low latency time | Database library

If I understand correctly, you are trying to capture only one # symbol at the beginning of each line.

The regular expression that helps you solve the issue is: r"(?:^|\s)(?:[#]\ )(.*\n+##\ ([^#]*\n)+)". The brackets isolate the capturing or non capturing groups. The first group (?:^|\s) is a non capturing group, because it starts with a question mark. Here you want that your matched string starts with the beginning of a line or a whitespace, then in the second group ([#]\ ), [#] will match exactly one # character. \ matches the space between the hash and the h1 tag text content. finally you want to match any possible character until the end of the line so you use the special characther ., which identifies any character, followed by + that will match any repetition of the previous matched character.

This is probably the code snippet you are looking for, I tested it with the same sample test you used.