seashells | Golang port of the official seashells client | Chat library

Suppose I have the following SQL query:

I am trying to split a string into an array of letters, but keep some of the letters together. (I'm trying to break them into sound groups for pronunciation, for example). So, for example, all the "sh' combinations would be one value in the array instead of two.

It is easy to find an 's' in an array that I know has an "sh" in it, using firstIndex. But how do I get more than just the first, or last, index of the array?

The Swift documentation includes this example:

I am learning how to apply string operations in Python, How would I go about replacing the last occurrence of a substring?

Question/Code given to debug:

The replace_ending function replaces the old string in a sentence with the new string, but only if the sentence ends with the old string. If there is more than one occurrence of the old string in the sentence, only the one at the end is replaced, not all of them. For example, replace_ending("abcabc", "abc", "xyz") should return abcxyz, not xyzxyz or xyzabc. The string comparison is case-sensitive, so replace_ending("abcabc", "ABC", "xyz") should return abcabc (no changes made).

I'm trying to create a Python function that takes a sentence, turns it into a list, and determines whether a given letter appears in any word in that list, regardless of letter case. I would like the function then to return just a list of those words that have that letter, with each word’s letters in their original cases.

I have been able to return those words, but all letters are now in lower case, even if they were originally upper case. How do I return the words with their letters in their original cases?

What I’ve written:

I'm trying to figure out a way so that the text that gets printed on the screen with the print() function also gets spoken at the same time. I am currently using the pyttsx3 module, but I don't see how I can do that.

I didn't knew much about what I can try in this scenario. The code below is just an example code.

I'm trying to get the running count of words in a list by preserving the order of the elements

I want to match word without special characters(dot, quotes, etc.) or whitespaces. The text I have

"üstlenmeyeceğimizin üst "ürünlerin daha sağlıklı ve zamanında ulaşabilmesi süstlenmeyeceğimizin şehirlerarası otobüs şirketleriyle çalıştığımızı fakat ısrarınız üstüne oluşabilecek gecikme veya sorunları üstlenmeyeceğimizin teyidini alarak kargoyla gönderim sağladık." üstlenmeyeceğimizin ğtest atest üstlenmeyeceğimizind. test test üst şüst a ğüst .üst üst.büst she sells seashells tüst atest ni ani grüst asla ısrar etmedim ve ürünlerin sağlığı için i yi olduğuna dair bi r bilgilendirme yapılmadı.

I want to select üst from this text but there is some different situations like below.

I don't want match words listed below

• ğüst
• şüst
• üstlenmeyeceğimizin
• "üstlenmeyeceğimizin

I want select those listed words

• .üst
• üst (there is whitespace before word)
• "üst

I wrote this regex: [^a-zçğşöü]üst(?![a-zçğşöü]) but this regex selects word with special characters. I don't want special characters.

Shortly I don't want select if word has any leading letters or whitespace but if there is any special character leading the word I want to select it without this special character

Seems to be very simple but I'm like, losing a lot of time on this... and no success...

If I have a string:

I'm using the String library in Python 3 to solve this HarvardX challenge, up to a point, but I don't think my solution is very good. Can you see a neater solution?

Here's my code: