tldextract | Extract root domain , subdomain name | Parser library
kandi X-RAY | tldextract Summary
kandi X-RAY | tldextract Summary
Extract root domain, subdomain name, and tld from a url, using the Public Suffix List.
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Top functions reviewed by kandi - BETA
- New returns a new TLDextract .
- download issues a GET to the given URL .
- Add a rule to the Trie
- subdomain returns the subdomain and d .
- SetNoValidate sets the NoValidate flag
tldextract Key Features
tldextract Examples and Code Snippets
Community Discussions
Trending Discussions on tldextract
QUESTION
I have scrapped content of the web (css, js and images)
now I want to edit downloaded HTML file to provide absolute path of images, js and css.
for example, the script need to find the source 'src', it must be absolutes path (contain domain) and not relatives (not contain domain).
change from: /static_1.872.4/js/jquery_3.4.1/jquery-3.4.1.min.js To https://es.sopranodesign.com/static_1.872.4/js/jquery_3.4.1/jquery-3.4.1.min.js and save it as index2.html
Here is my code so far:
...ANSWER
Answered 2022-Apr-09 at 09:44You can simply reassign that as the attribute to the bs4 object, as per the link I provided:
for example:
QUESTION
I new to pandas. I have a dataset like this one:
...ANSWER
Answered 2022-Mar-01 at 23:24you can do this:
QUESTION
Trying to update to php 8.1 and noticed this deprecated notice showing up in the error logs I'd like to take care of.
[14-Feb-2022 14:48:25 UTC] PHP Deprecated: Return type of TLDExtractResult::offsetExists($offset) should either be compatible with ArrayAccess::offsetExists(mixed $offset): bool, or the #[\ReturnTypeWillChange] attribute should be used to temporarily suppress the notice in /home/example/public_html/assets/tldextract/tldextract.php on line 299
I was able to suppress the warning, but would actually like to update the script so there are no issues in the future.
...ANSWER
Answered 2022-Feb-15 at 21:28Yes, you can specify return types that match those indicated for the various methods of the ArrayAccess
interface as shown in the manual. For example, like this for the specific method in the deprecation message in your question:
QUESTION
I was trying to check a few domain names but even some common one are returning this
the error occurs in "df['IPaddr'] = socket.gethostbyname(DN)"
socket.gethostbyname [Errno -2] Name or service not known
So I tried to try: but most of them are failing!
checked domain
Unexpected error:
AMD.com
Unexpected error:
AOL.com
...ANSWER
Answered 2021-Oct-21 at 03:14allow_permutations=True
doesn't look like a valid parameter for IPWhois
. Because you're using try
you might not be seeing the TypeError:
QUESTION
I am trying to access JSON data but getting the above error. My code is:
...ANSWER
Answered 2021-Oct-12 at 00:03json.loads expects a str hence the error
If you want to get the key-value pairs you can do this:
QUESTION
Running this snippet of code in python's interpreter, we get an IP address for gov.uk
.
ANSWER
Answered 2021-Oct-02 at 19:18gov.uk
, like .uk
, is an Effective TLD or eTLD.
I picked this up from the go package public suffix and the wikipedia page for Public Suffix List.
Mozilla created the Public Suffix List, which is now managed by https://publicsuffix.org/list/. It can be found in Mozilla's Documentation, but this term does not appear anywhere on https://publicsuffix.org/list/ at the time of writing.
QUESTION
I'm getting a "TypeError: a bytes-like object is required, not 'str'". I was using StringIO and I got an error "TypeError: initial_value must be str or None, not bytes" I'm using Python 3.7.
...ANSWER
Answered 2021-Jun-11 at 22:18The error basically says your string is byte string. To solve this, I think you can try to use .decode('utf-8')
QUESTION
I have been working on a small project which is a web-crawler template. Im having an issue in pycharm where I am getting a warning Unresolved attribute reference 'domain' for class 'Scraper'
ANSWER
Answered 2021-May-24 at 17:45Just tell yrou Scraper
class that this attribut exists
QUESTION
I have been currently working on creating a web crawler where I want to call the correct class that scrapes the web elements from a given URL.
Currently I have created:
...ANSWER
Answered 2021-May-24 at 09:02Problem is that k.domain
returns bbc
and you wrote url = 'bbc.co.uk'
so one these solutions
- use
url = 'bbc.co.uk'
along withk.registered_domain
- use
url = 'bbc'
along withk.domain
And add a parameter in the scrape
method to get the response
QUESTION
I have been working on a project where I want to gather the urls and then I could just import all the modules with the scraper classes and it should register all of them into the list.
I have currently done:
...ANSWER
Answered 2021-May-24 at 08:21Do as you did in __init_subclass__
or use cls.scrapers
.
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