typed | wrapper around map interface { } to provide | JSON Processing library
kandi X-RAY | typed Summary
kandi X-RAY | typed Summary
It isn't always desirable or even possible to decode JSON into a structure. That, unfortunately, leaves us with writing ugly code around map[string]interface{} and []interace{}. This library hopes to make that slightly less painful.
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Top functions reviewed by kandi - BETA
- JsonReaderArray returns an array of typed array
- IntsOr returns the typed ints if the key is not present .
- JsonFileArray loads a json array from a file
- Must converts data to a Typed type .
- JsonFile returns a Typed struct .
- JsonReader returns a Typed struct
- JsonStringArray returns a slice of typed JSON array .
- JsonArray return Typed array array
- JsonString returns a Typed struct
- Json returns a Typed object .
typed Key Features
typed Examples and Code Snippets
function _isTypedArray(val) {
var type = Object.prototype.toString.call(val);
return type === '[object Uint8ClampedArray]' || type === '[object Int8Array]' || type === '[object Uint8Array]' || type === '[object Int16Array]' || type === '[obje
function P(a,b,c){if(void 0===c&&1===a.nodeType){var d="data-"+b.replace(O,"-$1").toLowerCase();if(c=a.getAttribute(d),"string"==typeof c){try{c="true"===c?!0:"false"===c?!1:"null"===c?null:+c+""===c?+c:N.test(c)?n.parseJSON(c):c}catch(e){}n.
Community Discussions
Trending Discussions on typed
QUESTION
In his paper Generics for the Masses Hinze reviews encoding of data type.
Starting from Nat
ANSWER
Answered 2022-Mar-14 at 18:05The difference is the category. Nat
is an initial algebra in the category of types. Rep
is an initial algebra in the category of indexed types. The category of indexed types has as objects type constructors of kind * -> *
, and as morphisms from f ~> g
, functions of type forall t. f t -> g t
.
Then Rep
is the initial algebra for the functor RepF
defined as follows:
QUESTION
Clang compiles this fine, but GCC and MSVC complain that operator=
cannot be defaulted:
ANSWER
Answered 2022-Mar-14 at 10:40Given the lack of any indications to the contrary, I'm going to answer my own question and say that, as far as I've been able to find relevant clauses in the standard, I think the code is legal and thus GCC and MSVC are complaining erroneously.
As someone pointed out above, there appears to be a bug report tracking this issue.
QUESTION
I'm trying to access appsettings.json in my Asp.net core v6 application Program.cs file, but in this version of .Net the Startup class and Program class are merged together and the using and another statements are simplified and removed from Program.cs. In this situation, How to access IConfiguration or how to use dependency injection for example ?
Edited : Here is my default Program.cs that Asp.net 6 created for me
...ANSWER
Answered 2021-Sep-30 at 11:13Assuming an appsettings.json
QUESTION
Whenever I am trying to run the docker images, it is exiting in immediately.
...ANSWER
Answered 2021-Aug-22 at 15:41Since you're already using Docker
, I'd suggest using a multi-stage build. Using a standard docker image like golang
one can build an executable asset which is guaranteed to work with other docker linux images:
QUESTION
Trying to install openssl on homebrew using:
...ANSWER
Answered 2021-Sep-03 at 15:29Seems a bug of openssl itself. https://github.com/openssl/openssl/issues/16487
~~What about export SDKROOT="/Library/Developer/CommandLineTools/SDKs/MacOSX.sdk "
?~~
Homebrew pre-build packages for some versions of macOS. But it keep dropping this pre-building support for old macOS. On macOS 10.12, you're building openssl
from the source code and Xcode command line tool is needed.
QUESTION
I've just upgraded the version I use for Hibernate to 5.6.1 and it seems it's now deprecating some Type-related annotations:
...ANSWER
Answered 2022-Jan-18 at 14:13It seems there is no replacement until Hibernate 6. Type and also TypeDef was marked as deprecated to mark it as removed in version 6, but so far not replacement exists. The ideology here is that deprecated does not indicate that already a new version exists, which might be not an intuitive meaning for most developers.
This was reverted now in the current 5.6.3-Final version series.
QUESTION
I am not using AWS AppSync for this app. I have created Graphql schema, I have made my own resolvers. For each create, query, I have made each Lambda functions. I used DynamoDB Single table concept and it's Global secondary indexes.
It was ok for me, to create an Book item. In DynamoDB, the table looks like this: .
I am having issue with the return Graphql queries. After getting the Items
from DynamoDB table, I have to use Map function then return the Items
based on Graphql type
. I feel like this is not efficient way to do that. Idk the best way query data. Also I am getting null both author and authors query.
This is my gitlab-branch.
This is my Graphql Schema
...ANSWER
Answered 2022-Jan-09 at 17:06TL;DR You are missing some resolvers. Your query resolvers are trying to do the job of the missing resolvers. Your resolvers must return data in the right shape.
In other words, your problems are with configuring Apollo Server's resolvers. Nothing Lambda-specific, as far as I can tell.
Write and register the missing resolvers.GraphQL doesn't know how to "resolve" an author's books, for instance. Add a Author {books(parent)}
entry to Apollo Server's resolver map. The corresponding resolver function should return a list of book objects (i.e. [Books]
), as your schema requires. Apollo's docs have a similar example you can adapt.
Here's a refactored author
query, commented with the resolvers that will be called:
QUESTION
C 2018 6.7.6.1 1 says:
If, in the declaration “T D1”, D1 has the form
* type-qualifier-listopt D
and the type specified for ident in the declaration “T D” is “derived-declarator-type-list T”, then the type specified for ident is “derived-declarator-type-list type-qualifier-list pointer to T”. For each type qualifier in the list, ident is a so-qualified pointer.
This question is about the final sentence, but let’s work through the first one first.
Consider the declaration int * const * foo
. Here T is int
, D1 is * const * foo
, type-qualifier-list is const
, and D is * foo
.
Then T D is int * foo
, and that specifies “pointer to int
” for the ident foo
, so derived-declarator-type-list is “pointer to”. (There is no overt explanation of derived-declarator-type-list in the standard, but 6.7.8 3, discussing typedef
, says it “is specified by the declarators of D.”)
Substituting these into the final clause of the first sentence tells us that T D1 specifies the type for foo
is “pointer to const
pointer to int
”. Fine so far.
But then the final sentence tells us that for each type qualifier in the list (which is const
), ident is a so-qualified pointer. So it says foo
is a const
pointer.
But it is not; we commonly interpret int * const * foo
to declare foo
to be a non-const
pointer to a const
pointer to int
.
Is this a mistake in the standard or is there another interpretation for the final sentence?
...ANSWER
Answered 2021-Dec-04 at 08:18With T as int
and D as * foo
, the "T D" does not give ident the type T, but pointer to T.
The second part of the if
:
If ... and the type specified for ident in the declaration “T D” is “derived-declarator-type-list T”
seems to make sure that the nesting is correct.
With two stars, you would have to use D2 - D1 - D before you reach the direct declarator.
The second example:
QUESTION
I'm playing with Rank-N-type and trying to type x x
. But I find it counter intuitive that these two functions can be typed in the same way.
ANSWER
Answered 2021-Nov-08 at 16:22The key is that x :: a -> b
is a function that can provide a value of any type, no matter what argument is given. That means x
can be applied to itself, and the result can be applied to x
again, and so on and so on.
At least, that's what it promises the type checker it can do. The type checker isn't concerned about whether or not any such value exists, only that the types align. Neither f
nor g
can actually be called, because no such value of type a -> b
exists (ignoring bottom and unsafeCoerce
).
QUESTION
Consider the example of a typed decorator bound to certain classes.
...ANSWER
Answered 2021-Nov-23 at 10:59What about this? It is shorter than the full signature:
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