bender | An easy-to-use library for creating load testing applications | Performance Testing library
kandi X-RAY | bender Summary
kandi X-RAY | bender Summary
Bender does not provide any support for sending load from more than one machine. If you need to send more load than a single machine can handle, or you need the requests to come from multiple physical hosts (or different networks, or whatever), you currently have to write your own tools. In addition, the histogram implementation used by Bender is inefficient to send over the network, unlike q-digest or t-digest, which we hope to implement in the future. Bender does not provide any visualization tools, and has a relatively simple set of measurements, including a customizable histogram of latencies, an error rate and some other summary statistics. Bender does provide a complete log of everything that happens during a load test, so you can use existing tools to graph any aspect of that data, but nothing in Bender makes that easy right now. Bender currently provides helper functions for DHCPv6, DNS, HTTP, Thrift and TFTP. We appreciate Pull Requests for other protocols. The load testers we have written internally with Bender have a lot of common command line arguments, but we haven’t finalized a set to share as part of the library.
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Trending Discussions on bender
QUESTION
In Julia, I have a project where I have many calculations. Next is a tiny extract of what it could look like:
...ANSWER
Answered 2021-Jan-21 at 23:00You could write it yourself
QUESTION
I am using the Benders decomposition and solve a linear subproblem at each iteration. To save time, I generate the subproblem out of the benders while loop. At each iteration, I solve the master problem and update one of the subproblem constraints and then optimize the subproblem. Since my subproblem is a large problem, presolve during the model. optimize() may help the algorithm. In this respect, I set model.setParam("presolve",value) with value=-1,1,2 (currently none of these options help me with my problem). In the first iteration, in the presolve phase, rows and columns are removed and the model is solved in a reasonable time. However, in the second iteration, the log does not show any presolve phase and due to the problem structure, it can not solve the lp problem. My question is this: How can I force Gurobi to run the presolve phase while optimizing the problem during each iteration? I do not want to use p.model.presolve() and p.optimize() because with this, solver miss the dual information of the removed constraints in problem p and I cannot map the solution of p to the solution of the original problem. In the following, you can find the log of the small instance (I have the same problem in the large instances). As you can see in the second iteration, I don't have the presolve phase. I'm using Gurobi 9.0.1 with python 3.7.
log of the first iteration:
...ANSWER
Answered 2021-Jan-12 at 13:40Most likely, the solver is warm-starting from the previous optimization. This will happen if you just change a few parts of the model and don't construct a new model from scratch. Maybe, you can try to call Model.reset() to start a new optimization from scratch with full presolving.
It's hard to tell what you're doing without seeing the source code, though.
QUESTION
I have six letters [a,b,c,d,e,f]
and two users [bob,bender]
. They both have a different arrangement of the letters that represents them, think personality score-ish. Bob is [e,f,c,b,a,d]
and Bender is [b,a,d,f,e,c]
.
I also have a chart to put these on. Each letter, in order, has it's own bar on the chart and the ticks go up to 6.
Depending on where in the list the letter appears it has a number value assigned. The first letter gets a value of 6, the second a value of 5, and so on.
The final array needs to be in abc order, but with the correct value for each letter. Example: Bob would end up with [2,3,4,1,6,5]
.
How would you do this?
The only way I can figure is a ton of if statements and I'm trying to see if there's a better way.
I'm still new to Javascript.
...ANSWER
Answered 2020-Nov-16 at 22:33You could use Array.map()
and Array.indexOf()
.
QUESTION
I'm trying to invoke the List[T](IEnumerable)
directly adding an item to the initial List
like so, where T
is a PowerShell class I've written (the below example uses the class name Thing
:
ANSWER
Answered 2020-Sep-20 at 17:26I'm unsure why I'm unable to use my PowerShell class as the type
The array subexpression operator @()
returns its results as [object[]]
- a type which satisfies the argument type [IEnumerable[object]]
- which is why it always works when you use [object]
as the type parameter for the receiving collection type.
So, what to do about that?
If the array consists only of [Thing]
's, you can explicitly cast to a more specific collection type that implements [IEnumerable[Thing]]
:
QUESTION
First, some background on what I'm trying to do. I am writing a PowerShell script module that needs to set some variables and run some code when the module is imported. What ultimately needs to happen is dependent on the version of PowerShell the module is being imported into. For example, this needs to support 5.1 and later, but Invoke-RestMethod
does not support the-SkipCertificateCheck
parameter until PowerShell 6, meaning I need to check the version, create a dummy ICertificatePolicy that essentially always returns true
when validating, and store that in a global place somewhere I can reference it and set that policy if the user dictates they want to skip security checks when calling certain cmdlets. I have the following code so far:
ANSWER
Answered 2020-Sep-10 at 20:10In general, I'd strongly suggest not doing this at all. Blindly skipping certificate trust validation is a bad idea.
As I was (poorly) trying to explain in the comments, if you resolve the calling assembly (ie. System.Management.Automation.dll
), you might be able to use that to discover version information in the initializer using reflection:
QUESTION
I am working on MILP model (In DoCplex) and solver reaches the solution faster with Benders Method sometime and sometimes using Branch & Bound. Is there an easy way to run both solve methods parallel without changing variable names (cloning the model) on same model. And use output from one of the solve.
...ANSWER
Answered 2020-Aug-25 at 04:30You cannot solve the same model with two algorithms simultaneously. However, it should be easy to create the same model twice and then solve it concurrently in two different threads or processes. You will have to use the threading
or multiprocessing
Python modules for this.
One very simple and convenient way on a Unix-like operation system (like Linux or MacOS) would be to use os.fork() to create a new process for each solve and then control them from the initial process. fork()
implicitly clones the model, so it can save you some lines of programming.
QUESTION
I thought that today I finally understood what is typealias for.
I didn't.
Let's take a look at an example:
...ANSWER
Answered 2020-Aug-18 at 09:52typealias is literally for creating an "alias" (i.e. another name) for a type. You are not creating a new type, just another name for an existing type. From the Language Reference:
Type aliases do not create new types; they simply allow a name to refer to an existing type.
Therefore, once you declared the typealias,
Graph
and[String: [String]]
now refers to the same type. An extension onGraph
is equivalent to an extension on[String: [String]]
.For your desired behaviour, you need to create a new type. For a
Graph
, I think a struct would be appropriate:
QUESTION
I want to calculate relative optimality Gap of a MIP Problem also i want to abort runs at a certain run time. this method:
...ANSWER
Answered 2020-Aug-18 at 13:45There are different formulas to calculate the relative optimality gap. It depends on the solver you use, which one is applied. Some info about this can be found in the description of the GAMS option optCR . The solver manual of the solver you use could have more details about the formula actually applied.
EDIT after question was updated:
As you wrote mymodel.objval
returns the Final Solve
value. If you want to see the MIP Solution
value instead (as the Cplex link does it internally), you could deactivate the final solve. However, if Final Solve
and MIP Solution
are so much different as in your example this is often an indication for some problem (usually, they are (nearly) identical). Often, this indicates a poorly scaled model. Maybe you could improve the situation by tightening the Cplex tolerances (see Cplex options epopt
, eprhs
, epint
) and activating aggressive scaling (Cplex option scaind 2
). Activating mipkappastats
(https://www.gams.com/latest/docs/S_CPLEX.html#CPLEXmipkappastats) and quality
(https://www.gams.com/latest/docs/S_CPLEX.html#CPLEXquality) could give you more information. DataCheck=2
(https://www.gams.com/latest/docs/S_CPLEX.html#CPLEXdatacheck) might show some problems.
QUESTION
I don't have a deep understandin of how it works. I've been able to paralellize the following portion of code:
...ANSWER
Answered 2020-Aug-04 at 04:31In your code you solve multiple optimization problems in parallel. This is fine but there is a catch: By default a single CPLEX instance will use as many threads as your machine has cores and will try to keep them busy. So if you solve N models in parallel, then on each core N instances of CPLEX will compete for computing resources. This is usually not a good idea since CPLEX processes are more or less completely CPU bound.
One option to speed up your code would be to avoid that multiple CPLEX threads run on the same core. For example, if you have 12 cores and run 3 solves in parallel, then make sure that each of these solves uses only 4 threads.
In order to limit the number of threads for a single solve use parameter IloCplex::Param::Threads.
QUESTION
I have a pandas dataframe with multiple columns that I'm trying to merge into a single column, keeping the longer string. Unfortunately I'm getting lost with how to do this. There are a limited number of potential columns, there may two or more (two is the most likely scenario).
...ANSWER
Answered 2020-Jun-26 at 00:17We can try max
with key
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Install bender
[DHCPv6](https://github.com/pinterest/bender/blob/master/dhcpv6/TUTORIAL.md)
[DNS](https://github.com/pinterest/bender/blob/master/dns/TUTORIAL.md)
[HTTP](https://github.com/pinterest/bender/blob/master/http/TUTORIAL.md)
[TFTP](https://github.com/pinterest/bender/blob/master/tftp/TUTORIAL.md)
[Thrift](https://github.com/pinterest/bender/blob/master/thrift/TUTORIAL.md)
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