unionfind | idiomatic implementation of a weighted Union Find | Natural Language Processing library
kandi X-RAY | unionfind Summary
kandi X-RAY | unionfind Summary
An idiomatic implementation of a weighted Union Find data structure with path compression in go.
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- Root returns the position of the union .
- NewThreadSafeUnionFind returns a new ThreadSafeUnionFind .
- New creates a new UnionFind .
unionfind Key Features
unionfind Examples and Code Snippets
Community Discussions
Trending Discussions on unionfind
QUESTION
I have a cypher projection that used algo.unionFind in Neo4j. However, that algorithim has been deprecated. My query was:
CALL algo.unionFind('MATCH (n) WHERE n.dtype=\"VALUE\" RETURN id(n) AS id','MATCH p=(n)-[]-(m) WHERE n.dtype=\"VALUE\" AND m.dtype=\"VALUE\" RETURN id(n) AS source, id(m) AS target', {write:true, partitionProperty:\"partition\", graph:'cypher'}) YIELD nodes, setCount, loadMillis, computeMillis, writeMillis
I was hoping to find an equivalent approach with the Graph Data Science Library that runs the query and writes a new property partition
in my nodes.
Any help would be greatly appreciated!
...ANSWER
Answered 2021-Jan-20 at 10:45The algorithm has been renamed to gds.wcc.write
in the new GDS library.
QUESTION
i faced a paradox to analyse this function, Why the time complexity of this function is N^2 and not N?
...ANSWER
Answered 2021-Jan-13 at 09:57Provided your array access ids[x]
is in constant time O(1)
, the time complexity of the union
method is linear in the length of the array ids
. So
QUESTION
I am practicing a classic algorithm problem in go "number of islands". I want to solve it using unionfind. Although I can tweak and make it work, I would like to know the best way to structure my code.
Here is the main program.
...ANSWER
Answered 2021-Jan-08 at 21:38When you do this:
QUESTION
I implemented the following union-find algorithm using this example:
...ANSWER
Answered 2020-Jun-05 at 10:03QUESTION
I am trying to include Opencv to my native C code in an android studio project through Cmake. I did some research online and downloaded the FindOpenCV.cmake file from online and added it to the app directory of my android project. This is also where the CMakeLists.txt is located. I imported OpenCV onto my Android Studio project as a module using this tutorial: https://www.learn2crack.com/2016/03/setup-opencv-sdk-android-studio.html, and when I run:
...ANSWER
Answered 2019-Oct-24 at 14:24UPDATE 21-Oct-19: Deprecated Git/Simpler Way in favor of new AndroidOpenCVGradlePlugin
UPDATE 22-May-18: Added missing step number 6.
UPDATE 10-May-17: New solution provides proper integration of OpenCV into application with CMake and Android Gradle plugin 2.3.1. Tested using Android Studio 2.3.1.
UPDATE 11-May-17: An additional solution has been provided
There are two ways of including OpenCV.
Using AndroidOpenCVGradlePlugin
Visit https://github.com/ahasbini/AndroidOpenCVGradlePlugin for more details.
Git/Simpler Way
Visit https://github.com/ahasbini/Android-OpenCV for more details.
Manual/Advanced Way
To include OpenCV libraries into Android Studio Project, its best to create a new Library Module in the project and port the files from OpenCV Android SDK bundle into it:
- Create a new module by selecting File>New Module.
- Select "Android Library", and then enter the details:
- Library name:
OpenCV
- Module name:
opencv
- Package name:
org.opencv
- Library name:
- Once the new module created, copy the contents of
path_to_opencv_sdk/sdk/java/src
directory intopath_to_your_project/opencv/src/main/java
. - Under
main
, create the following directly path:aidl/org/opencv/engine
and movemain/java/org/opencv/engine/OpenCVEngineInterface.aidl
into it. - Copy the contents of
path_to_opencv_sdk/sdk/java/res
intopath_to_your_project/opencv/src/main/res
. - Create
sdk
folder insidepath_to_your_project/opencv/src/
and copypath_to_opencv_sdk/sdk/native
folder into it. - Within the
opencv
module, createCMakeLists.txt
file and add the following lines in the following order:
QUESTION
I am using Kruskal's Algorithm to find the Minimum Spanning Tree. I just followed the algorithm that has been provided during the lecture and I should keep the format of having Edge class. sorted is not working so I can't figure out if the logic is wrong.
Is there any reason of naming parent in the constructor of Edge class.
...ANSWER
Answered 2019-Aug-15 at 13:16You are confusing the function sorted(iterable[, key][, reverse]) with the list method sort(*, key=None, reverse=None).
Where sorted according to the documentation does: "Return a new sorted list from the items in iterable." While sort according to documentationd does: This method sorts the list in place, using only < comparisons between items. Exceptions are not suppressed - if any comparison operations fail, the entire sort operation will fail (and the list will likely be left in a partially modified state).
So for your code to work you need to change: sorted(edge_list, key=lambda vertex: vertex.weight) to edge_list.sort(key=lambda vertex: vertex.weight)
This assuming that everything else is correct in your code
QUESTION
I need some help to figure out union-find problem.
Here is the question.
...There's an undirected connected graph with n nodes labeled 1..n. But some of the edges has been broken disconnecting the graph. Find the minimum cost to repair the edges so that all the nodes are once again accessible from each other.
Input:
n, an int representing the total number of nodes.
edges, a list of integer pair representing the nodes connected by an edge.
edgesToRepair, a list where each element is a triplet representing the pair of nodes between which an edge is currently broken and the cost of repearing that edge, respectively
(e.g. [1, 2, 12] means to repear an edge between nodes 1 and 2, the cost would be 12).Example 1:
Input: n = 5, edges = [[1, 2], [2, 3], [3, 4], [4, 5], [1, 5]],
edgesToRepair = [[1, 2, 12], [3, 4, 30], [1, 5, 8]]Output: 20
There are 3 connected components due to broken edges: [1], [2, 3] and [4, 5]. We can connect these components into a single component by repearing the edges between nodes 1 and 2, and nodes 1 and 5 at a minimum cost 12 + 8 = 20.
ANSWER
Answered 2019-Aug-13 at 01:57You're supposed to use Kruskal's algorithm to find a minimum cost spanning tree consisting of the existing edges and broken (repaired) edges:
https://en.wikipedia.org/wiki/Kruskal%27s_algorithm
Just consider the existing edges to have 0 cost, while the broken edges have their repair cost.
QUESTION
I tried to run the following command in Neo4j however it gives the error Unknown function 'algo.getNodeById'. I am using Neo4j desktop (3.4.0) and I am running this command in Neo4j browser:
...ANSWER
Answered 2019-Jan-30 at 21:43Some of the older versions of algorithms don't have algo.getNodeById()
included. If you can try to use the latest graph algorithms, not sure how this works with Neo4j Desktop, but I would try to reinstall them. You could also upgrade your Desktop version.
If none of this is available remember that algo.getNodeById()
just matches the node by its internal ID and you can get the same functionality by using the following.
QUESTION
I want to find a query in cypher that returns the (weakly) connected components in graph with between 20 and 30 elements and with at least of 10 elements with the property "prop"=True.
...ANSWER
Answered 2019-Jan-25 at 18:34One of the problems you have is that count(*)
will always be 1 as you are also aggregating by each node. Remember that Neo4j has implied grouping, where it will group by all elements in the row.
One can get the count of nodes with prop=True
with a simple sum(CASE WHEN ...)
statement
Solution:
QUESTION
I have partitioned my graph into ~400,000 connected components using the algo.unionFind function from the Neo4j Graph Algorithms library.
Each node n within the same connected component has the same n.partition value. However, now I want to assigned each connected component a UUID so that each node n in a connected component will have n.uuid populated with a component UUID. What is the most efficient way of doing this?
Currently I am getting a list of all n.partition values and then going through each partition and running a Cypher query to update all nodes of that partition to have a generated UUID. I'm using the Python wrapper py2neo and this process is quite slow.
Edit:
The Cypher queries I am currently using are:
...ANSWER
Answered 2018-Oct-16 at 15:12The best way would be to install the APOC plug-in to Neo4j so that you can use the UUID function apoc.create.uuid()
in Cypher. (so that it can be generated, and assigned, in the same transaction)
To create 1 uuid per partition, you will need to use WITH to store the uuid in a temporary variable. It will be run per row, so you need to do it once you have one partition
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