persister | Go process used to abstract database interaction | Database library

by trandoshan-io Go Version: Current License: GPL-3.0

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | persister Summary

persister is a Go library typically used in Database, MongoDB applications. persister has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Persister is a Go written program designed to persist/archivate crawled resources.

Support

Quality

Security

License

Reuse

Support

persister has a low active ecosystem.

It has 8 star(s) with 4 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 8 have been closed. On average issues are closed in 13 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of persister is current.

Quality

persister has no bugs reported.

Security

persister has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

persister is licensed under the GPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

persister releases are not available. You will need to build from source code and install.

Top functions reviewed by kandi - BETA

kandi has reviewed persister and discovered the below as its top functions. This is intended to give you an instant insight into persister implemented functionality, and help decide if they suit your requirements.

handle messages
Basic example
getResource fetches the resource data for the given URL
extractTitle extracts the title from the body .

Get all kandi verified functions for this library.

persister Key Features

No Key Features are available at this moment for persister.

persister Examples and Code Snippets

No Code Snippets are available at this moment for persister.

Community Discussions

Trending Discussions on persister

Error Relation does not exist when dll-auto = create

Unable to locate persister: com.package.model.Bus

Using enums in a spring entity

NServiceBus: How does saga concurrency with SQL persister work?

How to test object initialisation within a super constructor?

how to get data from manyToMany entities

org.postgresql.util.PSQLException: ERROR: relation "users" does not exist - SpringBoot, Hibernate, Postgresql

Spring Data JPA : DataIntegrityViolationException

Liferay: Error is occured while executing an index Actions

Unable to build Hibernate SessionFactory - could not instantiate test object

QUESTION

Error Relation does not exist when dll-auto = create

Asked 2021-Jun-08 at 09:17

My Entity class:

...

ANSWER

Answered 2021-Jun-08 at 09:17

Instead of:

Source https://stackoverflow.com/questions/67751000

QUESTION

Unable to locate persister: com.package.model.Bus

Asked 2021-Jun-04 at 13:17

I am desperately trying to migrate a Spring MVC 4.3.4.RELEASE application with Hibernate 4.3.8.Final to the latest version of Spring Boot, i.e. Spring Boot 2.5

The idea is to turn it into a Restful API and to drop all views.

Note : I did not create a custom configuration on the new spring-boot project.

My architecture looks like :

The controller
The DTO
The service
The DAO
The entity

Here is my pom.xml file :

...

ANSWER

Answered 2021-Jun-04 at 13:17

In ApplicationConf you tell Hibernate to scan the com.package.repository package but your Bus entity class seems to be in the com.package.model package.

Try changing:

Source https://stackoverflow.com/questions/67829558

QUESTION

Using enums in a spring entity

Asked 2021-Jun-03 at 22:34

How should you setup a Spring entity that uses an Enum?

I have set up a spring-boot project and provided the code below so hopefully, someone can tell me the correct way this should be done.

I have a Spring entity setup

...

ANSWER

Answered 2021-Jun-03 at 17:29

You need to add @Enumerated annotation on the enum field.

Source https://stackoverflow.com/questions/67825729

QUESTION

NServiceBus: How does saga concurrency with SQL persister work?

Asked 2021-Jun-01 at 07:03

I'm using NServiceBus with SQL Persistance and MSSQL Server.

I want to be sure that I don't get invalid data in my database in high concurrent scenarios.

From the docs I know that the SQL persister uses pessimistic concurrency since version 4.1.1. But I'm not sure how it works exactly because under "Starting Saga" and "Changes to Saga state" only optimistic concurrency is mentioned.

Does each saga instance only handle one message at a time and all the remaining messages are waiting in the queue to be handled by the saga?

Also is it possible to configure the concurrency to use optimistic concurrency instead of pessimistic concurrency for the SQL persister?

...

ANSWER

Answered 2021-Jun-01 at 07:03

Both optimistic concurrency control and pessimistic locking result in a saga instance to only being able to handle 1 message.

Might multiple messages be handled then with :

Optimistic concurrency control: The 2nd+ writer will fail and the message will be retried.
Locking: THe lock ensures that multiple messages on the same saga instance will be delayed. Sometimes this can result in a deadlock due to lock escalation and then the message will be retried.

Regarding pessimisitic vs optimistic, you cannot choose. The latest version uses pessimistic locking. See https://docs.particular.net/persistence/sql/saga-concurrency:

Starting in version 4.1.1 conflicts cannot occur because the persistence uses pessimistic locking. Pessimistic locking is achieved by performing a SELECT ... FOR UPDATE or its dialect-specific equivalent.

Up to and including version 4.1, SQL persistence uses optimistic concurrency control when updating or deleting saga data.

Source https://stackoverflow.com/questions/67719545

QUESTION

How to test object initialisation within a super constructor?

Asked 2021-Jun-01 at 00:03

I have a BasePersister that builds a complex persistence client in it's constructor, using Dagger:

...

ANSWER

Answered 2021-Jun-01 at 00:03

Moving the client instantiation within the base class constructor was ideal because in my PersisterFactory, I can simply invoke statements like new SpecialPersister(); the constructor doesn't take any arguments, doesn't need Dagger to instantiate and the factory is completely unaware of any clients.

I'm having trouble testing these child classes and I'm suspecting it has to do with my design choice of secretly instantiating clients within the base constructors.

This design choice is the issue. If you want the code to be testable without making calls on the real client, you will need to be able to stub your client. One option for this is to pass the PersistenceClient in at instantiation.

Since you are using a factory pattern, your factory can provide it without worrying about the details elsewhere in your code. It should know how to create Persister objects, regardless of if it needs to know the details about the client - coupling at this level should be encouraged. You may also want your factory to take the argument, as well, so that a Persister from the factory can be tested.

Source https://stackoverflow.com/questions/67781058

QUESTION

how to get data from manyToMany entities

Asked 2021-May-26 at 22:34

I have two entities user and movie. I want to display movies for the users. Users are going to see the movies they added. I connected these two enetities with manyToMany and i am trying to get the data but i am having this error.

...

ANSWER

Answered 2021-May-26 at 22:34

You probably want:

Source https://stackoverflow.com/questions/67713484

QUESTION

org.postgresql.util.PSQLException: ERROR: relation "users" does not exist - SpringBoot, Hibernate, Postgresql

Asked 2021-May-24 at 12:14

I am using Spring Boot with Hibernate, JPA and Postgresql database. I am trying to create new user and save it. I have the following code:

UserEntity.java

...

ANSWER

Answered 2021-May-24 at 12:14

For PostgreSQL you need to use GenerationType.SEQUENCE instead of GenerationType.IDENTITY.

Then:

Source https://stackoverflow.com/questions/67670990

QUESTION

Spring Data JPA : DataIntegrityViolationException

Asked 2021-May-19 at 19:54

I have three entities Blog, Comments, ParentChildComment. Comment is mapped using ManyToOne relationship to Blog. ParentChildComment has two columns to store id value of parent_comment and child_comment (this is done to store the info regarding which comment is a reply to another one) and both these columns are mapped using OneToOne relationship to Comment table which I guess is the sourcee of problem. PROBLEM When deleting a blog, comments are deleted due to cascade delete, but the parent_child table is still referncing to table comments which throw error org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [fkf3i44d11sgikshmo17q4fq1a4]; nested exception is org.hibernate.exception.ConstraintViolationException The whole trace :

...

ANSWER

Answered 2021-May-19 at 19:54

before invoking blogRepository.deleteById you should delete also ParentChildComment whose comments are in the Blog's collection of comments.

Source https://stackoverflow.com/questions/67608760

QUESTION

Liferay: Error is occured while executing an index Actions

Asked 2021-May-18 at 06:15

I am using Liferay 7.3.5 and trying to create an elasticSearch method and have created the required classes KeywordQueryContributor, ModelDocumentContributor, ModelIndexerWriterContributor, SearchRegistrar and ModelSummaryContributor.

Now, from the control panel --> configuration --> Search, I am trying to execute the model, but this error appears .

...

ANSWER

Answered 2021-Apr-27 at 12:51

The last line of the code you provide looks like getCompanyId() is there, so I see two ways to hunt this down:

Database (make sure the table for TKPRIME has a field companyId. Include capitalization in your check)
Java (if the interface (TKPRIME) has this method, but the implementation (TKPRIMEImpl) doesn't: execute the buildService target again. ServiceBuilder requires rebuilding every now and then - and will show you any mismatches.

Note: If you introduced companyId after your first deployment of the new entity, you might need to create an Upgrade routine to alter your database. Only development systems may automate that (and I'm not even sure if they do by default)

Source https://stackoverflow.com/questions/67234729

QUESTION

Unable to build Hibernate SessionFactory - could not instantiate test object

Asked 2021-May-17 at 17:07

I have a very strange error happening

I have a program developed in Java WEB using Hibernate to connect to the MySQL Database The program is working correctly on several computers here but there is a computer that the program does not work!

I already tried to change the version of the server, the JDK and even the IDE and even then on this computer the program is not working

The error mentions that "could not instantiate test object" but I'm not doing any tests on any classes / objects on any computer where the project is working

Log

...

ANSWER

Answered 2021-May-05 at 10:37

Looks like the constructor of Tabcadastro throws a RuntimeException. Did you recompile your code? Are you using some kind of Java Agent that transforms the constructor somehow?

Source https://stackoverflow.com/questions/67369090

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install persister

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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