bench | A generic latency benchmarking library | Performance Testing library

 by   tylertreat Go Version: Current License: Apache-2.0

kandi X-RAY | bench Summary

kandi X-RAY | bench Summary

bench is a Go library typically used in Testing, Performance Testing applications. bench has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Bench is a generic latency benchmarking library. It's generic in the sense that it exposes a simple interface (Requester) which can be implemented for various systems under test. Several example Requesters are provided out of the box.
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              bench has a low active ecosystem.
              It has 287 star(s) with 18 fork(s). There are 13 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 5 open issues and 3 have been closed. On average issues are closed in 157 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of bench is current.

            kandi-Quality Quality

              bench has no bugs reported.

            kandi-Security Security

              bench has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              bench is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              bench releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            bench Key Features

            No Key Features are available at this moment for bench.

            bench Examples and Code Snippets

            bench entry point .
            javadot img1Lines of Code : 9dot img1License : Permissive (MIT License)
            copy iconCopy
            static void test2() {
                    IntStream.range(1, 4)
                        .mapToObj(num -> new Foo("Foo" + num))
                        .peek(f -> IntStream.range(1, 4)
                            .mapToObj(num -> new Bar("Bar" + num + " <- " + f.name))
                            .  
            Start bench benchmark .
            javadot img2Lines of Code : 8dot img2License : Permissive (MIT License)
            copy iconCopy
            public static void main(String[] args) throws Exception {
                    Options options = new OptionsBuilder()
                            .include(CollectionsBenchmark.class.getSimpleName()).threads(1)
                            .forks(1).shouldFailOnError(true)
                             
            Bench 64 128xMixRandom .
            javadot img3Lines of Code : 6dot img3License : Permissive (MIT License)
            copy iconCopy
            @Benchmark
                @BenchmarkMode(Mode.AverageTime)
                @OutputTimeUnit(TimeUnit.NANOSECONDS)
                public static void testL128X128MixRandom() {
                    generateRandomNumbers(RandomGenerator.of("L128X128MixRandom"));
                }  

            Community Discussions

            QUESTION

            How to limit options based on a based on another , without changing values
            Asked 2021-Jun-14 at 02:05

            I have two selects, I want to configure them so that only a certain amount of options show in the second select, depending on which first selection is chosen.

            I found some code from this post and I've tried to edit it for my situation, as I need too keep the values as they are, because I'm using them in a calculator that needs them like that.

            If any one could help me fix/finish this code so it works, it would be much appreciated!

            What I'm trying to achieve:

            • If the user selects combo-x1, bench-x1 option only shows
            • If the user selects combo-x2, bench-x1 option + bench-x2 option only shows
            • If the user selects combo-x3, bench-x1 option + bench-x2 + bench-x3 option only shows
            • If the user selects combo-x4 up to combo-8, all options show

            Here is the JSFiddle: https://jsfiddle.net/mbxz186q/

            But here is the code so far as well:

            ...

            ANSWER

            Answered 2021-Jun-14 at 02:05

            Don't need jquery or complex javascript for this, most of it can be done via css:

            Source https://stackoverflow.com/questions/67963642

            QUESTION

            Is there a better way to write this javascript? They are essentially show/hide functions (in 3 different ways)
            Asked 2021-Jun-11 at 02:23

            I'm still learning javascript, and I'm using three sets of code - but it seems like there could be a better way to write them.

            Set one:

            ...

            ANSWER

            Answered 2021-Jun-11 at 02:23
            You want automagic behavior for a custom microformat

            Let's look at one section of the first pattern:

            Source https://stackoverflow.com/questions/67930209

            QUESTION

            Does the Bizarro pipe ->.; have disadvantages making it not recommended for use?
            Asked 2021-Jun-08 at 07:01

            Since R-Version 4.1.0 the pipe |> is in the stable version. When passing the lhs into an argument other than the first the Examples of the manual show:

            ...

            ANSWER

            Answered 2021-Jun-07 at 09:16

            The main issue with the bizarro pipe is that it creates hidden side-effects and makes it easier to create subtle bugs. It decreases code maintainability.

            The issue, of course, is the persistent existence of . makes it all too easy to accidentally refer to this value later down the line: its presence masks mistakes if you at some point “forget” to assign to it and think you did. It’s easy to dismiss this possibility but such errors are fairly common and, worse, very non-obvious: you won’t get an error message, you’ll just get a wrong result. By contrast, if you forget the pipe symbol somewhere, you’ll get an immediate error message.

            Worse, the bizarro pipe hides this error-prone side-effect in two different ways. First, because it makes the assignment non-obvious. I’ve argued previously that -> assignment shouldn’t be used since it hides a side-effect, and side-effects should be made syntactically obvious (the side-effect here is assignment, and it should happen where it’s immediately spotted: in the first column of the expression, not hidden away at its end). This is a fundamental objection to the use of -> (or any other attempt to mask side-effects), not limited to the bizarro pipe.

            And because . is by default hidden (from ls and from the inspector pane in IDEs), this makes it even easier to accidentally depend on it.

            Therefore, if you want to assign to a value instead of using a pipe, just do that. But:

            1. Perform right-to-left assignment, i.e. use name = value or name <- value, not value -> name.
            2. Use a descriptive name.

            I can’t stress enough that this is an actual source of subtle bugs — don’t underestimate it!

            Another issue is that its use breaks editor support for auto-formatting code. This is a “solvable issue” in some IDEs via plugins but the solution, as it were, solves an issue that should not even exist. To clarify what I mean, if you’re using the bizarro pipe you’d presumably want a hanging indent, i.e. something along these lines:

            Source https://stackoverflow.com/questions/67868289

            QUESTION

            Get index path of particular elements from a array in flutter
            Asked 2021-Jun-07 at 18:00

            I have a array of workout list. which has body parts name and the exercise list for the same body part. I want to get the index path of particular body part . let cosider the following example . Lets say i want to get the indexpath of "Arm". How to do this can anybody help me ?

            ...

            ANSWER

            Answered 2021-Jun-07 at 09:20

            You can do something like this:

            Source https://stackoverflow.com/questions/67868804

            QUESTION

            fast c++ sign function
            Asked 2021-Jun-04 at 14:39

            In my code I'm doing a sign check on a double numerous times in a loop and that loop is typically run several million times over the duration of the execution.

            My sign check is a pretty rudimentary calculation using fabs() so I figured there must be other ways of doing it that are probably quicker since "dividing is slow". I came across a template function and copysign() and created a simple program to run a speed comparison. I've tested the three possible solutions with the code below.

            ...

            ANSWER

            Answered 2021-Jun-03 at 20:59

            Your tests are invalid because you're doing blocking I/O inside the timing.

            However, we can use quick-bench to analyze: https://quick-bench.com/q/gt2KzKOFP4iV3ajmqANL_MhnMZk. This shows the timings are all virtually identical. What about the compiler-generated assembly code?

            Source https://stackoverflow.com/questions/67824110

            QUESTION

            Flatlist doesn't add values React Native
            Asked 2021-Jun-03 at 21:46
            export class mondayExercises extends Component {
              constructor(props) {
                super(props);
                this.state = {
                  sets: [],
                };
              }
            
              static getDerivedStateFromProps(props, state) {
                if (props.route.params?.set) {
                  return {
                    sets: [...state.sets, props.route.params.set],
                  };
                }
                return null;
              }
            
              render() {
                return (
                  
                     (
                          
                            
                              {item.title}
                                  
                                  
                                  
                            
                          
                        )}
                        keyExtractor={(item, index) => item.key.toString()}
                      />
            
            
            ...

            ANSWER

            Answered 2021-Jun-03 at 21:46

            You need to destructure the argument to the renderItem function, as it is an object with an item field:

            Source https://stackoverflow.com/questions/67828893

            QUESTION

            In SystemVerilog testbench generator class - how to generate infinitely long data stream
            Asked 2021-Jun-02 at 19:33

            In all the SystemVerilog test benches I could find on the internet the generator class always generates a fixed amount of samples and sends them to the mailbox. Driver reads the mailbox and generates an appropriate sequence by manipulating interface signals

            One such generator, taken from [1] (chapter 1.3, paragraph 4) and reduced to essentials, is for example this:

            ...

            ANSWER

            Answered 2021-Jun-02 at 16:15

            What you are asking for is exactly how the UVM sequence/driver mechanism works. The generator does not do any randomization until the driver is ready and asks for an item to drive.

            But you can get close to what the UVM does simply by constructing your mailbox with a bound of 1. Then the put(trans) in the main loop blocks until after the driver has performed a get(). Then there will always be one transaction in the mailbox waiting for the next drive cycle.

            Source https://stackoverflow.com/questions/67808454

            QUESTION

            React Native touchableOpacity and ScrollView not working as expected on ios or android
            Asked 2021-May-30 at 23:14

            I'm creating a list with ScrollView and trying to use touchable opacity on all of the rendered items. There is only 6 items in the list but I can only get touchableOpacity to work on the last 2 items.

            I'm using touchableOpacity in a components folder and then importing it into a ScrollView on another screen. Any idea what I'm doing wrong or how I can fix the issue?

            component code below

            ...

            ANSWER

            Answered 2021-May-30 at 23:14

            You need to refactor your spacings and find a better combination: you have fixed height for every FlatBench but you are putting them in a fluid height container and doing negative margins. So the FlatBench height and its (very big) margin are covering each other.

            If you remove the following lines you can achieve your layout with positive margins on (bottom, bottomItem, topItem)

            FlatBench style fix:

            Source https://stackoverflow.com/questions/67766024

            QUESTION

            Ubuntu terminal ssh to same ip after device changed
            Asked 2021-May-26 at 19:18

            I ssh to a device that gets attached to a test bench with the following:ssh root@1.2.3.4

            Because the actual device has been changed since the last time I connected to that IP I get:WARNING: REMOTE HOST IDENTIFICATION HAS CHANGED! all as expected. The warning tells me that I can easily fix this with ssh-keygen -f "/home/myuser/.ssh/known_hosts" -R "1.2.3.4"

            I do find it repeating the same thing over and over, there must be some way to improve this. I know this IP and it is internal to my company.

            I started working on trying to use something like !!:s/find/replace but the spaces in the replace is making my life difficult.

            What is the easiest way to automate this, maybe create an alias?

            Thank you Jack

            ...

            ANSWER

            Answered 2021-May-26 at 19:18

            I asked a senior dev at my company and he suggested that I just update my ~/.ssh.config file. I added:

            Source https://stackoverflow.com/questions/67709111

            QUESTION

            Top level await not working with ESM in Node.js
            Asked 2021-May-22 at 00:26

            I'm using this benchmark however when running src/bench.js Node throws this error:

            ...

            ANSWER

            Answered 2021-May-22 at 00:26

            Support for top level await (without passing a command line argument to enable it as an experimental feature) was introduced in Node.js 14.8.0.

            The version of Node.js you are using is too old.

            Source https://stackoverflow.com/questions/67645064

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install bench

            You can download it from GitHub.

            Support

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