exp | Experimental Upspin packages
kandi X-RAY | exp Summary
kandi X-RAY | exp Summary
This repository contains components that are experimental or under development. See the master repository for more information.
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Top functions reviewed by kandi - BETA
- upsync syncs up to wd .
- newHandler returns a new http . Handler .
- newServer returns a new server .
- readers finds readers for the given entry .
- do runs the upspin client .
- formatIssue formats an issue .
- NewClient returns a new Client instance .
- NewWatcher creates a new Watcher
- Main entry point .
- New creates a new server instance
exp Key Features
exp Examples and Code Snippets
def solution(data_file: str = "base_exp.txt") -> int:
"""
>>> solution()
709
"""
largest: float = 0
result = 0
for i, line in enumerate(open(os.path.join(os.path.dirname(__file__), data_file))):
a, x =
Community Discussions
Trending Discussions on exp
QUESTION
I have recently upgraded my Intel MacBook Pro 13" to a MacBook Pro 14" with M1 Pro. Been working hard on getting my software to compile and work again. No big issues fortunately, except for floating point problems in some obscure fortran code and in python. With regard to python/numpy I have the following question.
I have a large code base bur for simplicity will use this simple function that converts flight level to pressure to show the issue.
...ANSWER
Answered 2022-Mar-29 at 13:23As per the issue I created at numpy's GitHub:
the differences you are experiencing seem to be all within a single "ULP" (unit in the last place), maybe 2? For special math functions, like exp, or sin, small errors are unfortunately expected and can be system dependend (both hardware and OS/math libraries).
One thing that could be would might have a slightly larger effect could be use of SVML that NumPy has on newer machines (i.e. only on the intel one). That can be disabled at build time using NPY_DISABLE_SVML=1 as an environment variable, but I don't think you can disable its use without building NumPy. (However, right now, it may well be that the M1 machine is the less precise one, or that they are both roughly the same, just different)
I haven't tried compiling numpy using NPY_DISABLE_SVML=1
and my plan now is to use a docker container that can run on all my platforms and use a single "truth" for my tests.
QUESTION
I am trying to do a simple function to check the differences between factorial and Stirling's approximation:
...ANSWER
Answered 2022-Mar-24 at 23:19It appears that Julia integers are either 32-bit or 64-bit, depending on your system, according to the Julia documentation for Integers and Floating-Point Numbers. Your exponentiation is overflowing your values, even if they're 64 bits.
Julia looks like it supports Arbitrary Precision Arithmetic, which you'll need to store the large resultant values.
According to the Overflow Section, writing big(n)
makes n
arbitrary precision.
QUESTION
I've written and optimized a Shiny app, and now I'm struggling with the IT section of the organization where I work to have it published on their servers. Currently, they are claiming that the app is not W3C compliant, which is true, according to the W3C validator.
The errors I'm trying to solve, with no success, are:
Bad value “complementary” for attribute “role” on element “form”.The value of the “for” attribute of the “label” element must be the ID of a non-hidden form control.
Such errors can be seen also in very minimal shiny apps, like:
...ANSWER
Answered 2022-Mar-04 at 08:05The following only deals with the first of the errors you mention (as this one is pretty clear thanks to @BenBolkers comment), but hopefully it points you to the right tools to use.
I'd use htmltools::tagQuery to make the needed modifications - please check the following:
QUESTION
I recently upgraded my OS from Debian 9 to Debian 11. I have a bunch of servers running a simulation and one subset produces a certain result and another subset produces a different result. This did not used to happen with Debian 9. I have produced a minimal failing example:
...ANSWER
Answered 2022-Feb-28 at 13:18It’s not a bug. Floating point arithmetic has rounding errors. For single arithmetic operations + - * / sqrt the results should be the same, but for floating-point functions you can’t really expect it.
In this case it seems the compiler itself produced the results at compile time. The processor you use is unlikely to make a difference. And we don’t know whether the new version is more or less precise than the old one.
QUESTION
I am learning how to write a Maximum Likelihood implementation in Julia
and currently, I am following this material (highly recommended btw!).
So the thing is I do not fully understand what a closure is in Julia nor when should I actually use it. Even after reading the official documentation the concept still remain a bit obscure to me.
For instance, in the tutorial, I mentioned the author defines the log-likelihood function as:
...ANSWER
Answered 2022-Feb-03 at 18:34In the context you ask about you can think that closure is a function that references to some variables that are defined in its outer scope (for other cases see the answer by @phipsgabler). Here is a minimal example:
QUESTION
Model:
...ANSWER
Answered 2021-Dec-28 at 19:47If you want to do it without knowing the formula then that implies numeric differentiation. Now the input is missing from the question so let us use the example in the Note at the end so that it can actually be run -- next time please provide a complete runnable example. Then use numeric differentiation from the numDeriv package.
QUESTION
I want to dynamically build a LINQ query so I can do something like
...ANSWER
Answered 2021-Dec-20 at 15:27Do you need to create an expression and compile it? Unless I'm missing some nuance to this, all you need is a function that returns a Func
.
QUESTION
I have a joint probability density f(x,y,z)
and I wish to find the conditional distribution X|Y=y,Z=z
, which is equivalent to treating x
as data and y
and z
as parameters (constants).
For example, if I have X|Y=y,Z=z
being the pdf of a N(1-2y,3z^2+2)
, the function would be:
ANSWER
Answered 2021-Dec-07 at 18:16I have managed to solve my own problem using solve()
from Symbolic Toolbox. There were two issues with my original approach: I needed to set up n
simultaneous equations for n
parameters, and the solve()
doesn't cope well with exponentials:
QUESTION
I have an angularfire authentication service which works absolutely fine - except it wont refresh the token.
My refresh code:
...ANSWER
Answered 2021-Nov-30 at 14:21Firebase handle the token refresh process, so there is no need to manually refresh the token. Firebase auth state can be read from 'authState' property.
QUESTION
Using this data...
...ANSWER
Answered 2021-Oct-01 at 00:40I don't understand your data/analysis (e.g. why do you use exp()
on hogs.fit and what are the letters supposed to be?) so I'm not sure whether this is correct, but nobody else has answered so here is my best guess:
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