p2. | - Simple and secure PDF to PNG server | Document Editor library
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:page_facing_up: p2. - Simple and secure PDF to PNG server.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of p2.
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p2. Examples and Code Snippets
def gather(params,
indices,
validate_indices=None,
name=None,
axis=None,
batch_dims=0): # pylint: disable=g-doc-args
r"""Gather slices from params axis `axis` according to indices.
Gather s
def map_structure(func, *structure, **kwargs):
"""Creates a new structure by applying `func` to each atom in `structure`.
Refer to [tf.nest](https://www.tensorflow.org/api_docs/python/tf/nest)
for the definition of a structure.
Applies `fun
def batch_gather_with_default(params,
indices,
default_value='',
name=None):
"""Same as `batch_gather` but inserts `default_value` for invalid indices.
Thi
Community Discussions
Trending Discussions on p2.
QUESTION
So basically I am getting two string inputs in the form of coordinates as (x,y) and then I am adding the numbers from the inputted string (which are p1 and p2) to different variables and then adding those variables (which are x1,x2,y1,y2). So is there a way to add the variables together i.e perform arithmetic on the variables, (not concatenate)
...ANSWER
Answered 2021-Jun-15 at 13:14You can do this with std::stoi()
. Add a line to put these string
s into int
variables and do your arithmetic:
int x = stoi(x1);
QUESTION
The given problem: Use friend function for getting the private variable and operator overloading for calculating the total number of goals by each side of the team. I'm completely new to C++ and unable to figure out how to fix this error. What I've tried:
...ANSWER
Answered 2021-Jun-12 at 10:41Not passing Player
as a reference in the operator solves the issue:
QUESTION
from playsound import playsound
import os
from multiprocessing import Process
def play_song(song_index, loc, song_list):
global play
while play:
try:
playsound(fr'{loc}\{song_list[song_index]}')
except Exception as e:
print(f'Error: {e}')
break
def controls(input):
global play
if input == 'stop':
play = False
print('stopped')
play = True
if __name__ == '__main__':
while True:
user = input('Enter folder name [Desktop]:\n>> ')
loc = fr'{os.environ["USERPROFILE"]}\Desktop\{user}'
music_dict = {name: index for name, index in enumerate(os.listdir(loc))}
for index in music_dict:
print(f'{index}) {music_dict[index]}')
choice = int(input(f'Play song[1-{index}]:\n>> '))
p1 = Process(target=play_song, args=(choice, loc, music_dict))
p1.start()
control = str(input('>> ')).lower()
p2 = Process(target=controls, args=(control,))
p2.start()
p1.join()
p2.join()
...ANSWER
Answered 2021-Jun-09 at 21:46The obvious problem here is that you are using multiprocessing
: Workers in a different process do not share global variables with the parent process: it will "see" another instance of the "play" variable.
This is the major difference between multiprocessing and multithreading: in multithreading, global variables are unique, and changes in one thread are visible in other threads. This comes with its own set of problems, but fr simple cases like this, it would just work:
Replace multiprocessing.Process
there with threading.Thread
and it would work. Note however that your worker thread will check the variable only when the song is over and it would skip to the next one (or rather, the way your code is, when it would start-over the same song).
If you want to really fix it, check the use of Queue
classes (there are both multithreading, async, and multiprocessing versions) and use those to control your worker, including sending the path for the next songs to be played.
Also, if you want to stop a song midway, which looks reasonable, you should stick with multiprocessing: then you stop the process by sending a kill signal to it - it is not possible to stop a thread in the same way: once Python would relinquish the control to the
playsound
call, you'd hav to wait for it to finnish. (But I suspect the playsound library have finer grained controls, in other calls than playsound.playsound
so that a song can be paused/resumed/stopped short of terminating the process - OH My!, googling for the docs, it actually does not have any controls - so the remote kill would work)
QUESTION
I am using tkinter and my goal is to print list L inside class Page2(Page)
whenever I click on Page 2. Currently, if you run the code, you can see that letters A & B are being printed in the console once you are in Page 1 which means that tkinter has already gone through that for loop. How can I change this code to go through that for loop only if I click on Page 2? FYI, I borrowed the code from the answer to Using buttons in Tkinter to navigate to different pages of the application?.
ANSWER
Answered 2021-Jun-08 at 23:59It's printing the list because that's part of creating an instance of the Page2
class that occurs before it's made visible (if ever) — which is just an artifact of the architecture of the code in the answer you "borrowed".
Here's a way to fix things. First change the Button
callback command=
options in MainView.__init__()
so the show()
method will get called instead of lift()
:
QUESTION
I use an online music player called "Netease Cloud Music", and I have multiple playlists in my account, they hold thousands of tracks and are very poorly organized and categorized and held duplicate entries, so I want to export them into an SQL table to organize them.
I have found a way to view the playlists without using the client software, that is, clicking the share button on top of the playlist page and then click "copy link".
But opening the link in any browser other than the client, the playlist will be limited to 1000 tracks.
But I have found a way to overcome it, I installed Tampermonkey and then installed this script.
Now I can view full playlists in a browser.
This is a sample playlist.
The playlists look like this:
The first column holds the songtitle, the second column holds the duration, the third column holds the artist, and the last column holds the album.
The text in the first, third and fourth columns are hyperlinks to the song, artist and album pages respectively.
I don't know a thing about html but I managed to get its data structure.
The thing we need is the table located at xpath //table/tbody
, each row is a childnode of the table named tr(xpath //table/tbody/tr
).
this is a sample row:
...ANSWER
Answered 2021-Jun-07 at 07:39The simplest answer is that you have to add some delay after opening the page with Firefox.get('https://music.163.com/#/playlist?id=158624364&userid=126762751')
before getting the elements with Firefox.find_elements_by_xpath('//table/tbody/tr')
to let the elements on the page loaded. It takes few moments.
So, you can simply add a kind of time.sleep(5)
there.
The better approach is to use expected conditions instead.
Something like this:
QUESTION
public String checkStrength(String password) {
String result = "";
//int strength = 0;
//If password contains both lower and uppercase characters, increase strength value.
Pattern ps = Pattern.compile("(?=.*[a-z])");
Pattern pl = Pattern.compile("(?=.*[A-Z])");
Matcher ms = ps.matcher(password);
Matcher ml = pl.matcher(password);
//System.out.println(ms.matches());
if(!ms.matches()) {
//strength += 1;
result += "lowercase letter not found\n";
}
if(!ml.matches()) {
//strength += 1;
result += "uppercase letter not found\n";
}
//If it has numbers and characters, increase strength value.
Pattern p1 = Pattern.compile("(?=.*[a-z])(?=.*[A-Z])");
Pattern p2 = Pattern.compile("(?=.*[0-9])");
Matcher m1 = p1.matcher(password);
Matcher m2 = p2.matcher(password);
if(m1.matches() == false || m2.matches() == false) {
//strength += 1;
result += "number and character combo not found\n";
}
//If it has one special character, increase strength value.
Pattern p3 = Pattern.compile("^(?=.*[@#$%^&+=])");
Matcher m3 = p3.matcher(password);
if(!m3.matches()) {
//strength += 1;
result += "special character not found\n";
}
//check length of password
if (password.length() < 8) {
//strength += 1;
result += "length must be minimum 8.\n";
}
//now check strength
// if(strength < 2) {
// //return "Weak";
// }
return result;
}
...ANSWER
Answered 2021-Jun-05 at 16:33Your pattern are incomplete. Add .+
at the end of each pattern.
Example: change
QUESTION
I have two classes as below:
...ANSWER
Answered 2021-Jun-03 at 07:23I think that what you are really looking for is "distinct" and not "groupBy". See here Select distinct using linq .
https://docs.microsoft.com/en-us/dotnet/api/system.linq.enumerable.distinct?view=net-5.0
What they say about distinct:
Returns distinct elements from a sequence.
Example:
QUESTION
I've two lists of objects that i wanna compare, a and b:
...ANSWER
Answered 2021-May-15 at 18:26ppp2 does not equal ppp3 because they are two different instances of a class. You could override the '==' operator to check if each field is the same. ie. ppp2.id == ppp3.id.
eg/ (taken from equatable docs but this is vanillar dart)
QUESTION
I have a series of headshots for a list of artists and on each of the headshots is a button that opens up a popup window with their bio. Currently, I am creating the elements and appending them to the content div inside of the popup window. My issue is it currently takes two clicks for the bio text to be created and appended to the popup window. This is because the first click adds the event listener to the button and then the second click would then run the function for appending their bio. How do I append the text on the first click?
...ANSWER
Answered 2021-Jun-02 at 20:32Call your function in first mount then it will open the pop up with first click.
QUESTION
I'm actually coding a Multitracker with Opencv using a CSRT tracker. (I used a online code and modified it as I need, here is the source: https://learnopencv.com/multitracker-multiple-object-tracking-using-opencv-c-python/ ) Every time a bounding box is 'updated' its coordinates are added to a list.
For every bbox (bounding box) I have to lists, one for the x and y coordinates of the top left corner of the bbox, and an other one for the x and y coordinates of the bottom right corner. (Those lists are respectively called p1 and p2.)
I have done almost everything that I want, but the p2 list of the bbox 1 don't stop copying itself or something like in the p2 list of the third bbox, and it don't depend of how much bbox exists. Note that I don't want any comments about improving it or optimizing it I don't care about it. Note too that the program is made to run with up to 6 bbox, and it's normal I don't need more but the program can run with 1, 2, or least that 6 bbox if I want.
If I'm lucky it's a stupid error, but I can't get it, so maybe that looks from other peoples on it may find it better than I can! ^^
Here is my long, unoptimized and ugly program! (And thanks if you help me!):
...ANSWER
Answered 2021-May-16 at 13:33Well after reading it almost 3 times I understood. Using lists which had siblings names wasn't a good thing to do same if I can't do it in an otherway, I was just printing an other list x3
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