gridlayout | Lightweight grid system for advanced horizontal | Grid library
kandi X-RAY | gridlayout Summary
kandi X-RAY | gridlayout Summary
If you need to create complex app layouts, similar to native ones, with support for older browsers. GridLayout is a ~1 KB (minified and gzipped) CSS file and a ~0.5 KB JavaScript file used only for Internet Explorer support. If you just support modern browsers, you’re probably better off using Flexbox.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of gridlayout
gridlayout Key Features
gridlayout Examples and Code Snippets
Lines of Code : 93License : Strong Copyleft (CC BY-SA 4.0)
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{isLoading
?
: layout.map(({ i }) =>
// change this from a typical function into a React component
)}
{isLoading
?
:
using System.Collections;
using System.Collections.Generic;
using System.Linq; // needed for cloning the list with .ToList()
using UnityEngine;
using UnityEngine.Tilemaps; // needed for Tilemap
public class MyTilemapScript : MonoBehaviourimport React from 'react';
import './App.css';
import '/node_modules/react-grid-layout/css/styles.css';
import '/node_modules/react-resizable/css/styles.css';
import GridLayout from 'react-grid-layout';
import Highcharts from "highcharts/hCommunity Discussions
Trending Discussions on gridlayout
QUESTION
ANSWER
Answered 2021-Jun-15 at 08:00(this grew too long for a comment, but probably already answers what you need)
itemSectionProps:
Your props are defined as:
QUESTION
this code returns me a black screen, what am I doing wrong?
python file:
...ANSWER
Answered 2021-Jun-15 at 01:11The problem is that the kv language insists that class names start with a capital letter. The documentation says:
Keep class names capitalized to avoid syntax errors
I think your code will work if you change all your class names to meet that requirement.
.
QUESTION
This Has To One OF The Most Annoying Errors In Python That Have So Many Solutions Depending On The Question
My Files...Main.py
ANSWER
Answered 2021-Jun-13 at 13:56The cryptic error message is of little help, but the stack trace shows that the error occurs in the line:
QUESTION
I need help.
I created a small mobile application with Kivy.
I have two screens: ScreenList and ScreenDetail.
However the screen(ScreenList) containing GridLayout does not refresh
ScreenList: contains a list of items
ScreenDetail: Contains the details of a single item.
How the app works:
- When I click on the first item on button 1
- I go to the details of the item.
- I modify the second field. I replace the text:
Firt elementforFirst and update data - After recording, I redirect the application to the screens which contain (ScreenList) the list of elements.
- But the list of elements remains unchanged then the data has been modified in the database. 6.And when I return to the screen (ScreenDetail) which contains the details, there I see that the data is updated.
How can I refresh the item list in ScreenList?
Here are the pictures as an example
List before update
before update
after update
List after update
Here is the python code:
...ANSWER
Answered 2021-Jun-13 at 06:24When you're trying to share data in between screens, it's often useful to use
appmethods instead of specific methods of screens.And when you need to create lots of buttons, maybe inside a loop, and bind methods on its events(
on_press,on_release), it's often bad to create button instances on the fly and bind methods on its events because you'll need to do extra work to make sure that those bound methods are called with right parameters when events are fired. Rather create a custom class template and use that instead.
Created custom GridLayout:
QUESTION
I'm new to Android and I need to use a ScrollView to wrap my whole content, since in some cases it needs to take up more height than is available on the screen. Most of the cases though, the height of the content is smaller than the screen. The ScrollView will almost always have a background color (not white), which needs to fill the whole screen available, not just wrap the content. I've checked a few other topics related to this, but the answers were outdated and none of them seems to solve the issue or even focuses on the question asked.
Extra details: Inside the ScrollView there is a RelativeLayout which encapsulates the content, as there can be only one element inside a ScrollView.
Please limit the answers to Java for Android Studio or XML configuration, if they don't use a programmatic approach, neither Kotlin, nor any other language used for Android programming. Thank you in advance!
...ANSWER
Answered 2021-Jun-12 at 18:50Simply put your ScrollView inside a ConstraintLayout, and set ScrollView's android:layout_height="0dp" like following:
QUESTION
I am writing a program in Codenameone that will pull an array of products from a url and display them in a list. I want to reload the page every time I press a button, so I code in a method called reload that should delete everything in the form and then replace it all with the newly pulled list.
...ANSWER
Answered 2021-Jun-10 at 01:13removeAll() doesn't recurse. That would be expensive and often redundant since the GC usually removes the entire tree.
Typically these problems are pretty simple to workaround though. There are two approaches:
Stop caching the component and re-create it every time you reload. This will mean it's never "already in" something
Before adding the problematic component just do:
problematicComponent.remove(). This will remove it from its parent (or do nothing if it has no parent)
In your case it seems like you're doing this:
QUESTION
I could really really need some help with my actually quite simple Python Kivy Problem! I wrote a program that first announces counting to 5 and then should start counting from 1 to 5. The info should be shown in a scrollview-Label. The code roughly does its job but does not update the scrollview step-by-step but all at once after time is elapsed...can anybody please help? Thank you in advance!
...ANSWER
Answered 2021-Jun-10 at 20:39The problem is that you are running your countingtofive() method on the main thread. Since Kivy uses the main thread to update the GUI, it cannot do that until you release the main thread (by returning from the countingtofive() method). That is why you never see anything until that method completes.
To fix that, run the countingtofive() method in another thread, like this:
QUESTION
I'm trying to add a GUI to the predator-prey simulation. It can allow users to choose which simulation(species involved) they want to do, set the simulation field size they want, and show the progress of the simulation and result.
The question is after I generate the field, I can't reset the simulation or run the next step or run the next hundred steps by clicking the buttons I set, not to mention show the progress of the simulation.
Here is the code of my GUI Class:
...ANSWER
Answered 2021-Jun-09 at 13:25Never mind... I find out where caused the problem:
I create new objects method again when I click those button, that's why the data generated by generate button is not accessed when I use rest of the buttons.
QUESTION
ok so my goal is to have a very clean slate as I like it when my code is organized, but that has also caused me too much trouble.
I have 3 .py files:
Main.py:
...ANSWER
Answered 2021-Jun-07 at 15:32You just need to import the CoinFlip() method in your kv file like this:
QUESTION
I am trying to make a dynamic Gridlayout, 3 by 3 in portrait, or 5 by 5 in landscape. The plan is to fill the grid with ImageViews for a Tic Tac Toe game. During the game, players can choose to change the orientation so the grid will also change dimension. So i made the ImageViews fill the grid dynamically:
ImageView xml:
...ANSWER
Answered 2021-Jun-07 at 14:38You are in a FOR-LOOP and you try to add same "iv" multiple times to its "ttt" parent, so after one cycle "iv" already has a Parent....
Method rewritten (2nd time):
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