birdman | HTML5 Web Audio APIs to recreate the Birdman opening credits | Audio Utils library

 by   markmarkoh HTML Version: Current License: MIT

kandi X-RAY | birdman Summary

kandi X-RAY | birdman Summary

birdman is a HTML library typically used in Audio, Audio Utils applications. birdman has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

#Recreating the Birdman opening credits with HTML5 Web Audio APIs. The opening credits to the 2014 Best Picture Birdman was exceptionally creative. The music is composed primarily of a standard jazz drum set, and for each beat or loud hit of the cymbal, letters would appear on the screen, slowly filling out sentences. This is my attempt to recreate that effect using the Web Audio APIs available in most modern browsers. To do this, we download an .mp3 and pass it through a filter to better isolate the louder drum and cymbal hits. Then we loop through the channel data, and based on an arbitrary threshold (for this project it was 0.22), we make a note of when that beat occurred in the track (1.445 seconds, for example). Finally, after we have an array containing the timing of all the sound "peaks", we simply set a series of window.setTimeouts, each with a callback to update the UI.
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            kandi-support Support

              birdman has a low active ecosystem.
              It has 141 star(s) with 10 fork(s). There are 7 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 1 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of birdman is current.

            kandi-Quality Quality

              birdman has no bugs reported.

            kandi-Security Security

              birdman has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              birdman is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              birdman releases are not available. You will need to build from source code and install.

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            birdman Key Features

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            birdman Examples and Code Snippets

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            Community Discussions

            QUESTION

            merge 2 dataframes based on partial string-match between columns
            Asked 2021-Jun-04 at 13:05

            I have two data frames df1 and df2 as shown below:

            Df1:

            ...

            ANSWER

            Answered 2021-Jun-04 at 13:05

            QUESTION

            How to get combination of List of values in C#
            Asked 2020-Sep-03 at 11:29

            I am creating a game which composed of 6 cards, I want to make a combination of those cards but the problem is that I am stuck in creating that function. Below are the codes I made

            ...

            ANSWER

            Answered 2020-Sep-03 at 11:29

            Based on your requirements which is to get all possible combinations of pairs of cards, the following double nested loop should do the magic for you:

            Source https://stackoverflow.com/questions/63722407

            QUESTION

            Error 'int' object is not subscriptable, How do i convert it to list?
            Asked 2020-Aug-31 at 23:25

            I'm a python newbie and still learning, I have this code:

            ...

            ANSWER

            Answered 2020-Aug-31 at 23:25

            Your error is introduced here:

            Source https://stackoverflow.com/questions/63679381

            QUESTION

            Lowering resolution of the camera texture in Spark AR
            Asked 2020-Aug-08 at 11:25

            I am trying to modify the resolution of the camera texture in Spark AR, either through a script or patches. This medium post has been helpful in understanding some of the components of the camera texture, but I could use some help.

            require('Textures') and require('CameraInfo') seem to be essential, but I am unsure of how to modify them.

            CameraInfo.previewSize.width and CameraInfo.previewSize.height would likely play a major role to reduce the size, but I am also unsure of how to then pass those variables to the texture.

            This is a non-functional example. Any suggestions would be greatly appreciated:

            ...

            ANSWER

            Answered 2020-Jul-27 at 01:15

            Very simple answer - the Shader render pass patch allows you to reduce the resolution of the camera texture for a specific object.

            Add the Shader render pass from the patch menu. Adjust the size variables as necessary and choose the sizing mode you require. Plug your texture into the shader port, and attach the texture output to your material patch.

            See this wonderful and detailed tutorial: https://www.youtube.com/watch?v=0L2Gr-SQpCU&feature=youtu.be

            Source https://stackoverflow.com/questions/63082631

            QUESTION

            How to match text leading up to an optional trailing element
            Asked 2020-Feb-23 at 18:29

            I am trying (with ruby) to pick apart strings with original film titles – which can include bracketed elements themselves – and may include a trailing bracketed element with an alternative title. I need to capture the leading part and the optional trailing alternative title, if present.

            Example strings:

            1. "Solaris"
            2. "Alice Guy-Blaché (1873 – 1968) – Hommage an die erste Filmemacherin der Welt"
            3. "Ieri, oggi, domani (Gestern, heute und morgen)"
            4. "Your life (in code) – A tribute (L'ultimo hacker)"
            5. "Birdman or (The Unexpected Virtue of Ignorance) (Birdman oder (Die unverhoffte Macht der Ahnungslosigkeit))"

            For example string 1 I'd want

            ...

            ANSWER

            Answered 2019-Dec-19 at 06:25

            You can use the following regular expression:

            Source https://stackoverflow.com/questions/59362081

            QUESTION

            Printing movies in the same year in the proper order
            Asked 2019-Oct-13 at 22:59

            I have all my code complete and it runs properly my issue is that when I print two movies for the same year the print in the wrong order I need them to print in the order of the list. This only happens with movies printing in the same year can anyone see where in my code the problem is?

            ...

            ANSWER

            Answered 2019-Oct-13 at 21:10

            As described here you can't influence the order of items in dictionary.

            What you can do, though is get sorted list of keys and iterate over them. Like so:

            Source https://stackoverflow.com/questions/58367355

            QUESTION

            How to combine multiple columns in CSV file using pandas?
            Asked 2019-Apr-16 at 18:59

            I have a csv file for lyrics songs that I took from Genius. Right now, I m preparing my data. I have two column "songs" and "artist". In the "songs" columns I have a lot information: title, album, year, lyrics and URL. I need to separate the column "songs" in 5 columns.

            Then I tried to split the data by comma like this:

            ...

            ANSWER

            Answered 2019-Apr-16 at 18:59

            QUESTION

            Dictionary sorting issue - python
            Asked 2018-Dec-05 at 22:45

            I've been working on a project for school but I've hit a small bump in the road. Almost everything is working as intended, but I am having an issue with the output in an undesired order. I want the program to sort by year as well as director if the user decides to sort by director. Theoretically I would like for the order of output to always have the earliest year first and the most recent year last. You don't need to write out the code, just aim me in the right direction! Thank you in advance!

            ...

            ANSWER

            Answered 2018-Dec-05 at 22:45

            From the beginning, you can transform your dictionnary in a list.

            Source https://stackoverflow.com/questions/53641566

            QUESTION

            I need with this code I have a sorting issue I cant figure out
            Asked 2018-Jun-15 at 16:59
            movieDict = {"Munich":[2005, "Steven Spielberg"],
                                    "The Prestige": [2006, "Christopher Nolan"],
                                    "The Departed": [2006, "Martin Scorsese"],
                                    "Into the Wild": [2007, "Sean Penn"],
                                    "The Dark Knight": [2008, "Christopher Nolan"],
                                    "Mary and Max": [2009, "Adam Elliot"],
                                    "The King\'s Speech": [2010, "Tom Hooper"],
                                    "The Artist": [2011, "Michel Hazanavicius"],
                                    "The Help": [2011, "Tate Taylor"],
                                    "Argo": [2012, "Ben Affleck"],
                                    "12 Years a Slave": [2013, "Steve McQueen"],
                                    "Birdman": [2014, "Alejandro G. Inarritu"],
                                    "Spotlight": [2015, "Tom McCarthy"],
                                    "The BFG": [2016, "Steven Spielberg"]}
            promptForYear = True
            while promptForYear:
                yearChoice = int(input("Enter a year between 2005 and 2016:\n"))
                if yearChoice<2005 or yearChoice>2016:
                    print("N/A")   
                else:
                    for key, value in movieDict.items():
                        if value[0] == yearChoice:
                            print(key + ", " + str(value[1]) )
                    promptForYear = False          
            menu = "MENU" \
                    "\nSort by:" \
                    "\ny - Year" \
                    "\nd - Director" \
                    "\nt - Movie title" \
                    "\nq - Quit\n"
            promptUser = True
            first_time = True
            while promptUser:
                if first_time == True:
                    print()
                    first_time = False
                print(menu)
                userChoice = input("Choose an option:\n")
                if userChoice == "q":
                    promptUser = False
                elif userChoice=="y":
                    year_sorted = {}            
                    for key, value in sorted(movieDict.items(), key=lambda item: (item[1], item[0])):
                        year = value[0]
                        title = key
                        director = value[1]
                        if year not in year_sorted:
                            year_sorted[year] = [[title, director]]
                        else:
                            year_sorted[year].append([title, director])            
                    for year in sorted(year_sorted):
                        print (year,end=':\n')
                        movies = year_sorted[year]
                        for movie in sorted(movies, key = lambda x:x[0]):
                            print("\t"+movie[0] + ", " + movie[1])
                        print()
                elif userChoice == "d":
                    director_sorted = {}
                    for key, value in sorted(movieDict.items(), key=lambda item: (item[1][1])):
                        year = value[0]
                        title = key
                        director = value[1]
                        if director not in director_sorted:
                            director_sorted[director] = [[title, year]]
                        else:
                            director_sorted[director].append([title, year])            
                    for director in sorted(director_sorted):
                        print (director,end=':\n')
                        movies = director_sorted[director]
                        for movie in sorted(movies, key = lambda x:x[0]):
                            print("\t"+movie[0] + ", " + str(movie[1]))            
                        print()
                elif userChoice == "t":
                    for key, value in sorted(movieDict.items(), key=lambda item: (item[0], item[1])):
                        print(key,end=':\n')
                        print("\t" + str(value[1]) + ", " + str(value[0])+"\n")
                else:
                    print("Invalid input")
            
            ...

            ANSWER

            Answered 2018-Jun-15 at 16:59

            This code segment here:

            Source https://stackoverflow.com/questions/50879456

            QUESTION

            Input a number, Search through Lists and Dictionary, print associated key
            Asked 2018-Apr-14 at 20:17

            I am having an issue pulling from a combined dictionary and list. I understand how to pull keys from each one individually but I need to combine them and pull the keys from both. The following is an Example of a dictionary listing years. Each year has a title and director associated with it.

            ...

            ANSWER

            Answered 2018-Apr-14 at 03:33

            If you want to stay with your data structure, modify the listing code like so:

            Source https://stackoverflow.com/questions/49827330

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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